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Permutations Combinations Questions and Answers : Quantitative Aptitude Test

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  • 1. In how many different number of ways 4 boys and 2 girls can sit on a bench?
A.) 620
B.) 640
C.) 720
D.) None of these

Answer: Option ''

Answer: Option 'C'
npn = n! 
6p6
= 6 × 5 × 4 × 3 × 2 × 1 = 720

  • 2. In how many different number of ways 5 men and 2 women can sit on a shopa which can accommodate persons? 
A.) 230
B.) 203
C.) 220
D.) 210

Answer: Option 'D'

Answer: Option 'D' 
7p3 = 7 × 6 × 5 = 210

  • 3. In how many different number of ways 4 boys and 3 girls can sit on a bench such that girls always sit together. 
A.) 720
B.) 5040
C.) 4320
D.) None of these

Answer: Option 'A'

Answer: Option 'A'

  • 4. In how many different ways can the letters of the word "CLAIM" be rearrangement? 
A.) 120
B.) 125
C.) 130
D.) None of these

Answer: Option 'A'

Answer: Option 'A' 
The total number of arrangements is 
5P5  = 5! = 120

  • 5. If the letters of the word PLACE are arranged taken all at a time, find how many do not start with AE. 
A.) 142
B.) 141
C.) 114
D.) None of these

Answer: Option 'C'

Answer: Option 'C' 
Total no'of arrangements 5P5  = 5! = 120 
no'of arrangements start with AE = 1 × 6 = 6 
no'of arrangements which do not start with AE = 120 - 6 = 114.

  • 6. How many arrangements of the letters of the word BEGIN can be made, without changing the place of the vowels in the word? 
A.) 7 ways
B.) 6 ways
C.) 5 ways
D.) 2 ways

Answer: Option ''

Answer: Option 'B' 
E,I fixed. Consonants can be arrangements in 3P3 = 3! = 6 ways

  • 7. If all the numbers 2, 3, 4, 5, 6, 7, 8 are arranged, find the number of arrangements in which 2, 3, 4, are together? 
A.) 720
B.) 620
C.) 700
D.) None of these

Answer: Option 'A'

Answer: Option 'A'
If (2 3 4) is one. 
we must arrange (2 3 4), 5, 6, 7, 8 in 
5P5 = 5! = 120 ways 
2, 3, 4 can be arranged in 3P3 = 3! = 6 
120 × 6 = 720.

  • 8. Find 10P6 
A.) 150200
B.) 151200
C.) 152200
D.) None of these

Answer: Option ''

Answer: Option 'B'
10P6 = 10!/4! = 10 × 9 × 8 × 7 × 6 × 5 
= 151200.

  • 9. Find 9P3
A.) 414
B.) 514
C.) 504
D.) None of these

Answer: Option 'B'

9P3 = 9!/6! = 9 × 8 × 7
= 504.

  • 10. Find 7P7
A.) 4440
B.) 5040
C.) 5045
D.) None of these

Answer: Option 'B'

7P7 = 7! = 7 × 6 × 5 × 4 × 3 × 2 × 1 = 5040

To whom this Permutations Combinations Question and Answers section is beneficial?

Students can learn and improve on their skillset for using Permutations Combinations effectively and can also prepare for competitive examinations like...

  • All I.B.P.S and Public Sector Bank Competitive Exam
  • Common Aptitude Test (CAT) Exams
  • UPSC Paper-II or CSAT Exams
  • SSC Competitive Exams
  • Defence Competitive Exams
  • L.I.C Assistant Administrative Officer (AAO)/ G.I.C AAO and Clerk Competitive Exams
  • Railway Competitive Exam
  • University Grants Commission (UGC)
  • Career Aptitude Test (IT Companies) and etc.