## Time and Distance

• 1. A person walking at 4 Kmph reaches his office 8 minutes late. If he walks at 6 Kmph, he reaches there 8 minutes earlier. How far is the office from his house?
A.) 3 1/5 Km
B.) 2 1/5 Km
C.) 4 1/5 Km
D.) 5 1/5 Km

Formula = S1×S2/S2-S1 × T1+T2/60
= 4×6/2 × 16/6
= 24/2 × 16/60
= 8 × 2/5
= 16/5 = 3 1/5 Km

• 2. A car takes 6 hours to cover a distance of 540 Km. how much should the speed in Kmph be maintained to cover the same direction in 3/2th of the previous time?
A.) 6o Kmph
B.) 62 Kmph
C.) 75 Kmph
D.) 77 Kmph

Time = 6
Distence = 540
3/2 of 6 hours = 6 × 3/2 = 9 Hours
Required speed = 540/9 = 60 Kmph

• 3. Avinash covers a distance of 8km in 50 minutes. If he covers 3km distance in 2/5th of time then, What speed should he maintain to cover the remaining distance in the remaining time?
A.) 13 Kmph
B.) 14 Kmph
C.) 15 Kmph
D.) 11 Kmph

Total distance = 8 Km
Total time = 50 Km
Time taken to cover the distence of 3 Km = 50*2/5 = 20 min = 1/3 hours
Remaining distance = 8 - 3 = 5 Km
Required speed = 5/1/3 = 15 Kmph

• 4. A man covers a distance of 180 Km at 72 Kmph and next 190km at 88 Kmph. what is his average speed For his whole journey of 370 Km?
A.) 79.2 Kmph
B.) 79.3 Kmph
C.) 77.25 Kmph
D.) 78.5 Kmph

Formula = 2 × F.S*S.P/F.S+S.P
= 2 × 72 × 88/88+72
= 79.2 Kmph

• 5. An aeroplane covers a certain distance of 420 Kmph in 6 hours. to cover the same distance in 4 2/3 hours, it Must travel at a speed of
A.) 580 Kmph
B.) 550 Kmph
C.) 540 Kmph
D.) 530 Kmph

Speed of aeroplane = 420 Kmph
Distance travelled in 6 hours
= 420 × 6 = 2520 Km
Speed of aeroplane to acver 2520 Km in 14/3
= 2520 × 3/14 = 540 Km

• 6. If a man walks 24 Km at 8 Kmph, he will be late by 25min. if he walks 12 Kmph, how early the fixed time Will he reach?
A.) 30 minutes
B.) 25 minutes
C.) 40 minutes
D.) 35 minutes

Time taken to cover 24 Km at the speed of 8 Kmph = 24/8 = 3 hours
Thus, right time was 2 hours 35 mintes
Now, time taken to cover 20 Km at the speed as 12 Kmph = 2 hours
Required time = 2 hours 35 minutes - 2 hours
= 35 minutes

• 7. In a covering a certain distance the speed of A and B are in the ratio of 6: 9, A takes 20 min more, than B to reach the destination. The time taken by A to reach the destination is:
A.) 1 Hour
B.) 2 Hours
C.) 1 1/2 Hour
D.) 1 1/4 Hour

Let the speed of A and B are 6x Kmph
and 9x Kmph respectively,
Let the total distance to travel = y Km
y/6x - y/9x = 1/3
y/x(1/18 = 1/3
y = 6x
Required time = 6x/6x = 1 hour

To whom this Time and Distance Question and Answers section is beneficial?

Students can learn and improve on their skillset for using Time and Distance effectively and can also prepare for competitive examinations like...

• All I.B.P.S and Public Sector Bank Competitive Exam
• Common Aptitude Test (CAT) Exams
• UPSC Paper-II or CSAT Exams
• SSC Competitive Exams
• Defence Competitive Exams
• NIIT online mock test
• L.I.C Assistant Administrative Officer (AAO)/ G.I.C AAO and Clerk Competitive Exams
• Railway Competitive Exam
• University Grants Commission (UGC)
• Career Aptitude Test (IT Companies) and etc.