# Latest model Quant Questions for SBI PO - Practice Test 1

1.

A, B and C invest in a business. B invests Rs. 5000 more than A and C invests Rs. 5000 more than B. 4/9th of the total profit goes to C. Find the total capital invested in the business.

A.) Rs. 10,000/-
B.) Rs. 15,000/-
C.) Rs. 25,000/-
D.) Rs. 45,000/-

Let the amount of money invested by A be Rs. X
A : B : C = x : x+5000 : x+10000
C's share = (x + 10000)/(3x+15000) = 4/9
Solving the equation,
x = Rs. 10000/-
3x + 15000 = Rs. 45000/-

2.

A jar contains 10 liters of milk. After selling 1 liter of milk, the milkman adds 1 liter of water to the jar. He repeats the process again. What is the percentage of milk contained in the jar now?

A.) 71%
B.) 80%
C.) 81%
D.) 84%

Amount of milk after 2 operations = 10[1 - (1/10)]2 = 10 × (9/10) × (9/10) = 8.1 litres
% of milk = (8.1/10)×100 = 81%

3.

Raj lends a sum of money to Shyam at an interest rate of 5% p.a. After two years, he charges an interst of 8% p.a. At the end of five years, Shyam pays Rs. 13400/- to Raj, how much money did he initially borrow?

A.) Rs. 12,000/-
B.) Rs. 10,000/-
C.) Rs. 14,000/-
D.) Rs. 16,000/-

Let the sum of money be Rs. x
Total Interest = (x × 2 × 5/100) + (x × 3 × 8/100) = 0.34x
x + 0.34x = 1.34x = 13400

4.

How many seconds will a 500 meter long train moving with a speed of 63 km/hr, take to cross a man walking with a speed of 3 of 3 km/hr is the direction of the train? A.) 43
B.) 30
C.) 54
D.) 28

Distance = 500m
Speed = 63 - 3 km/hr = 60 km/hr
= 600/36 m/s = 50/3 m/s
Time taken = distance/speed = 500/(50/3) = 30 sec

5.

Charan is an much younger than Raju as he is older than Tharun. If the sum of the ages of Raju and Tharun is 50 years, what is definitely the difference between Raju and Charan's age?

A.) 4 years
B.) 5 years
C.) 3 years

Given that
1. The difference of age between Raju and Charan = The difference of age between Charan and Tharun.
2. Sum of age of Raju and Tharun is 50 i.e (Raju + Tharun) = 50
Question : Raju - Charan = ?
Solution :
Raju - Charan  = Charan - Tharun
(Raju + Tharun) = 2Charan
Now given that, (Raju + Tharun) = 50
So, 50 = 2Charan and therefore Charan = 25.
The question is (Raju - Charan) = ?
Here we know the value (age) of Charan(25), but we don't know the age of Raju.
Therefore, (Raju - Charan) cannot be determined