Averages Problems for SSC CGL

1.

 In a class of 18 students in an examination in science 1 student scored 100 marks, 2 get zero each and the average oh the rest was 45. What is the average of the whole class? 

   A.) 41
   B.) 43
   C.) 42
   D.) 44

Answer: Option 'B'

43

2.

There were 25 students in a particular Class. The class teacher knows the overall height of all the students in the class is 1200. Can you find the average height of students in the class?

   A.) 45.6
   B.) 50.4
   C.) 48
   D.) 52.8

Answer: Option 'C'

Use the below formula to find the average height of students in the class
Average Height = (Total Height of all students in the Class / Total Number of Students)
Average Height = (1200/25) = 48

3.

The average age of a group of 10 students was 6. The average age increased by 2 years when two new students joined the group. What is the average age of the two new students who joined the group ?  

   A.) 15
   B.) 18
   C.) 16
   D.) 17

Answer: Option 'B'

The average age of a group of 10 students is 6.
Therefore, the sum of the ages of all 10 of them = 10 × 6 = 60
When two students joins the group, the average increase by 2.
New Average = 8
Now there are 12 students Therefore, sum of all the ages of 12 students =12 x 8 = 96
Therefore, the sum of the ages of two students who joined = 96 - 60 = 36
And the average age of these two students = 18.

4.

Find the average of the first 70 natural numbers ?

   A.) 31.5
   B.) 35.5
   C.) 34.5
   D.) 35

Answer: Option 'B'

Solution is :
Average of the first n natural numbers = ( n + 1 ) / 2
Average of the first 70 natural numbers = ( 70 + 1 ) / 2
= 71 / 2
= 35.5

5.

Average of 13 results is 65. If the average of first six results is 61 and average of last six results is 59 Then find the seventh result?

   A.) 115
   B.) 135
   C.) 125
   D.) 105

Answer: Option 'C'

125

6.

In the first 25 overs of a cricket game, the run rate was only 2.2. What should be the run rate in the remaining 25 overs to reach the target of 225 runs?

   A.) 7.48
   B.) 6.8
   C.) 8.8
   D.) 16.8

Answer: Option 'B'

Required Run rate = ( 225 - ( 2.2 x 25 ) )/ (25)
= ( 170) /(25)
= 6.8

7.

The average age of a group of 10 students was 20. The average age increased by 2 years when two new students joined the group. What is the average age of the two new students who joined the group ?

   A.) 32
   B.) 30
   C.) 33.5
   D.) 34

Answer: Option 'A'

The average age of a group of 10 students is 20.
Therefore, the sum of the ages of all 10 of them = 10 * 20 = 200 When two students joins the group, the average increase by 2. New Average = 22
Now there are 12 students Therefore, sum of all the ages of 12 students = (12 X 22) = 264
Therefore, the sum of the ages of two students who joined = 264 - 200 = 64
And the average age of these two students = 32

8.

The average of first five odd numbers is?

   A.) 5
   B.) 4
   C.) 4.5
   D.) 5.2

Answer: Option 'A'

5

9.

The average weight of a class having 14 students is 36 kg. Find the total weight of the class.

   A.) 504
   B.) 514
   C.) 494
   D.) 524

Answer: Option 'A'

Solution is :
Given, Average weight of the class = 36 kg
No. of students in the class = 14
Average = Total Quantity / No. of Quantity
=> Total weight of the class = Average weight x No. of students

= 36 × 14
= 504

10.

Total Marks obtained by a class is 1872 and the average score of the class is 72. Find the Total students in the class?

   A.) 27
   B.) 26
   C.) 25
   D.) 24

Answer: Option 'B'

Use the below formula to find the Total, when Average and Total No. of Students is provided Total no of students = Total Marks / Average Marks Total No. of students = ( 1872 / 72) = 26

11.

Physics Teacher knows the average score of 33 students in her subject is 49.5. Can you help the physics teacher to find the overall marks obtained by all the students in her subject?

   A.) 1551.83
   B.) 1633.5
   C.) 1796.85
   D.) 1726.85

Answer: Option 'B'

Use the below formula to find the Total, when Average and Total No. of Students is provided Total = Average * Total Students/People Total = Average * Total Number of Students) Average Weight = ( 49.5 x 33) = 1633.5

12.

There were 22 students in a particular Class. The class teacher knows the overall height of all the students in the class is 1200. Can you find the average height of students in the class?

   A.) 54.55
   B.) 57.28
   C.) 60.01
   D.) 51.82

Answer: Option 'A'

Use the below formula to find the average height of students in the class Average Height = ( Total Height of all students in the Class / Total Number of Students) Average Height = ( 1200/22) = 54.55

13.

Ayesha's father was 38 years of age when she was born while her mother was 36 years old when her brother four years younger to her was born. What is the difference between the ages of her parents? 

   A.) 2 years
   B.) 4 years
   C.) 6 years
   D.) 8 years

Answer: Option 'C'

Given
Mother's age when Ayesha's brother was born = 36 years.
Father's age when Ayesha's brother was born = (38 + 4) years = 42 years.
Required difference = (42 - 36) years = 6 years.

14.

Total Marks obtained by a class is 2695 and the average score of the class is 55. Find the Total students in the class?

   A.) 48
   B.) 49
   C.) 50
   D.) 51

Answer: Option 'B'

Use the below formula to find the Total, when Average and Total No. of Students is provided Total no of students = Total Marks / Average Marks Total No. of students = ( 2695 / 55) = 49

15.

Find the average of the first 56 natural numbers 

   A.) 28
   B.) 28.5
   C.) 29
   D.) 29.5

Answer: Option 'B'

Solution is
Average of n natural numbers = (n + 1) / 2
= (56 + 1) / 2
= 57 / 2
= 28.5
Answer is 28.5

16.

Total Marks obtained by a class is 864 and the average score of the class is 72. Find the Total students in the class?

   A.) 10
   B.) 11
   C.) 12
   D.) 13

Answer: Option 'C'

Use the below formula to find the Total, when Average and Total No. of Students is provided Total no of students = Total Marks / Average Marks Total No. of students = ( 864 / 72) = 12

17.

The average of 20 numbers is zero. Of them, at the most how many may be greater than zero?

   A.) 20
   B.) 21
   C.) 19
   D.) 18

Answer: Option 'C'

Average of 20 numbers is = 0 Therefore sum of all 20 numbers = 0
It is quite possible that 19 of these numbers may be positive and if their sum is "a" then 20th number is "(-a)"

18.

Find the average of first 17 multiples of 3

   A.) 6.33
   B.) 27
   C.) 20
   D.) 7.33

Answer: Option ''

Solution is
Given

Average of first 17 natural numbers= (n + 1 ) / 2 
=(18 / 2 )
= 9
Average of first 17 multiples of 3 =(Average of first 17 natural numbers) x 3
= 9 x 3

19.

The average of 26 numbers is zero. Of them, at the most how many may be greater than zero?

   A.) 25
   B.) 27
   C.) 24
   D.) 13

Answer: Option 'A'

Average of 26 numbers is = 0 Therefore sum of all 26 numbers = 0
It is quite possible that 25 of these numbers may be positive and if their sum is "a" then 26th number is "(-a)"

20.

Find the average of the first 56 natural numbers

   A.) 28.5
   B.) 28
   C.) 27.5
   D.) 29

Answer: Option 'A'

Solution is
Average of the first n natural numbers = (n + 1) / 2
Average of the first 56 natural numbers = (56 + 1) / 2
= 57 / 2
= 28.5


Averages Problems for SSC CGL Download Pdf