1.

**Day Codes:-**

Sat = 0

Sun = 1

Mon = 2

Tue = 3

Wed = 4

Thu = 5

Fri = 6

**Month Codes:-**

Jan = 1

Feb = 4

Mar = 4

Apr = 0

May = 2

Jun = 5

Jul = 0

Aug = 3

Sep = 6

Oct = 1

Nov = 4

Dec = 6

**Century Codes:-**

1500 - 1599 ---> 0

1600 - 1699 ---> 6

1700 - 1799 ---> 4

1800 - 1899 ---> 2

1900 - 1999 ---> 0

2000 - 2099 ---> 6

2100 - 2199 ---> 4

2200 - 2299 ---> 2

2300 - 2399 ---> 0

What was the day of the week on 24th July 2011?

**Answer: Option 'B'**

**Formula:-(Date + Month code + No.of years + No.of leap year + Century code)/7
= (24 + 0 + 11 + 2 + 6)/7 = 43/7 = 1
= Sunday**

2.

What was day of the week on 21-September-1987?

**Answer: Option 'B'**

**Formula:-(Date + Month code + No.of years + No.of leap year + Century code)/7
= (21 + 6 + 87 + 21 + 0)/7 = 135/7 = 2
= Monday**

3.

What was the day of the week on 26-January-1950?

**Answer: Option 'D'**

**Formula:-(Date + Month code + No.of years + No.of leap year + Century code)/7
= (26 + 1 + 50 + 12 + 0)/7 = 84/7 = 5
= Thursday**

4.

Today is Monday, after 61 days, the day will be:

**Answer: Option 'B'**

**Each day of the week is repeated after 7 days.
So, after 63 days, it will be Monday.
After 61 days, it will be saturday.**

5.

Which of the following is not a leap year?

**Answer: Option 'A'**

**The century divisible by 400 is a leap year.
The tear 700 is not a leap year**

6.

Today is Friday, after 126 days, it will be:

**Answer: Option 'C'**

**126/7 = 0
Each day of the week is repeated after 7 days.
So, after 126 days, it will be Friday.
After 126 days, it will be Friday.**

7.

How many days are there in x weeks X days?

**Answer: Option 'B'**

**x weeks x days = (7x + x) days = 8x days**

8.

It was Sunday on January-1-2006. Find the day of the week on January-1-2010?

**Answer: Option 'C'**

**Answer: Option 'C'
On 31st December, 2005 it was Saturday.
Number of odd days from the year 200 to the tear 2009 = ( 1 + 1 + 2 + 1 ) = 5days
On 31st December 2009, it was Thursday.
Thus, on 1st Jan, 2010 it is Friday.**

9.

What was the day of the week on 7th October, 2003?

**Answer: Option 'B'**

**Formula = ( Date + Monthcode + No.of years + No.of leapyears + Century code )/ 7
==> (7 + 1 + 3 + 0 + 6)/7 = 17/7 = 3
==> Tuesday**

10.

On 2007, What was the date of last Saturday in May month?

**Answer: Option 'D'**

**1 - May - 2007
=(1 + 2 + 7 + 1 + 6)/7 = 17/7 = 3 = Tuesday
= May 1st --> Tuesday + 5 days = Saturday = 5th may
5th may + 7 days = Saturday = 12th may
12th may + 7 days = Saturday = 19th may
19th may + 7 days = Saturday = 26th may
= Answer = 26th may
**

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