1.

What was the day of the week on 7th October, 2003?

A.) Sunday
B.) Saturday
C.) Friday
D.) Wednesday

Formula = ( Date + Monthcode + No.of years + No.of leapyears + Century code )/ 7
==> (7 + 1 + 3 + 0 + 6)/7 = 17/7 = 3
==> Tuesday

2.

On 8th February 2005, it was Tuesday. What was the day of the week on 8 February 2004?

A.) Tuesday
B.) Monday
C.) Sunday
D.) Wednesday

The year 2004 is a leap year. It has 2 odd days.
The day on 8th Feb, 2004 is 2 days before the day on 8th Feb, 2005
Hence, this day is Sunday.

3.

How many days are there in x weeks X days?

A.) 7x²
B.) 8x
C.) 14x
D.) 7

x weeks x days = (7x + x) days = 8x days

4.

On what dates on April 2001 did Wednesday fall?

A.) 1st , 8th, 15th, 22nd , 29th
B.) 2nd , 9th , 16th , 23rd , 30th
C.) 4th , 11th , 18th , 25th
D.) 3rd , 10th , 17th , 24th

We shall find the day on 1st April 2001 1st April 2001 = 2000 years + Period from 1.1.2001 to 1.4.2001 Odd days in 1600 years = 0 Odd days in 400 years = 0 Jan, Feb, Mar, April = 31 + 28 + 31 + 1 = 91 days = 0 odd days On 1st April it is Sunday.
In April, 2001 Wednesday falls on 4th , 11th , 18th and 25th .

5.

What was the day of the week on 17th June, 1998

A.) Tuesday
B.) Monday
C.) Sunday
D.) Wednesday

17th June, 1998 = (1997 years + Period from 1.1.1998 to 17.6.1998)
Odd days in 1600 years = 0
Odd days in 300 years = (5 × 3) = 1
97 years has 24 leap years + 73 ordinary years.
Number of odd days in 97 years = (24 × 2 + 73) = 121 = 2 odd days
Jan Feb March April May June
31 + 28 + 31 + 30 + 31 + 17 = 168 days = 24 weeks = 0 odd day
Total number of odd days = (0 + 1 + 2 + 0) = 3
Given day is Wednesday