1.
What was the day of the week on 17th June, 1998
Answer: Option 'D'
17th June, 1998 = (1997 years + Period from 1.1.1998 to 17.6.1998)
Odd days in 1600 years = 0
Odd days in 300 years = (5 × 3) = 1
97 years has 24 leap years + 73 ordinary years.
Number of odd days in 97 years = (24 × 2 + 73) = 121 = 2 odd days
Jan Feb March April May June
31 + 28 + 31 + 30 + 31 + 17 = 168 days = 24 weeks = 0 odd day
Total number of odd days = (0 + 1 + 2 + 0) = 3
Given day is Wednesday
2.
It was Thursday on 2nd Jan 1993. What day of the week will be on 15th March 1993?
Answer: Option 'C'
Today number of days = 29(Jan) + 28 (Feb) + (15) Mar = 72 days 10 Weeks + 2 days.
Thus the given date will fall on two days beyond Thursday, that is Saturday.
3.
It was Sunday on January-1-2006. Find the day of the week on January-1-2010?
Answer: Option 'C'
Answer: Option 'C'
On 31st December, 2005 it was Saturday.
Number of odd days from the year 200 to the tear 2009 = ( 1 + 1 + 2 + 1 ) = 5days
On 31st December 2009, it was Thursday.
Thus, on 1st Jan, 2010 it is Friday.
4.
On what dates on April 2001 did Wednesday fall?
Answer: Option 'C'
We shall find the day on 1st April 2001 1st April 2001 = 2000 years + Period from 1.1.2001 to 1.4.2001 Odd days in 1600 years = 0 Odd days in 400 years = 0 Jan, Feb, Mar, April = 31 + 28 + 31 + 1 = 91 days = 0 odd days On 1st April it is Sunday.
In April, 2001 Wednesday falls on 4th , 11th , 18th and 25th .
5.
Answer: Option 'B'
Formula:-(Date + Month code + No.of years + No.of leap year + Century code)/7
= (24 + 0 + 11 + 2 + 6)/7 = 43/7 = 1
= Sunday