RRB NTPC - Calender and Dates : MCQs with Answers Download PDF

1.

Today is Monday, after 61 days, the day will be: 

   A.) Wednesday
   B.) Saturday
   C.) Tuesday
   D.) Thursday

Answer: Option 'B'

Each day of the week is repeated after 7 days. 
So, after 63 days, it will be Monday. 
After 61 days, it will be saturday.

2.

  • Day Codes:-
    Sat = 0 
    Sun = 1 
    Mon = 2 
    Tue = 3 
    Wed = 4 
    Thu = 5 
    Fri = 6 
    Month Codes:- 
    Jan = 1 
    Feb = 4 
    Mar = 4 
    Apr = 0 
    May = 2 
    Jun = 5 
    Jul = 0 
    Aug = 3 
    Sep = 6 
    Oct = 1 
    Nov = 4 
    Dec = 6 
    Century Codes:- 
    1500 - 1599 ---> 0 
    1600 - 1699 ---> 6 
    1700 - 1799 ---> 4 
    1800 - 1899 ---> 2 
    1900 - 1999 ---> 0 
    2000 - 2099 ---> 6 
    2100 - 2199 ---> 4 
    2200 - 2299 ---> 2 
    2300 - 2399 ---> 0 

What was the day of the week on 24th July 2011? 

   A.) Monday
   B.) Sunday
   C.) Friday
   D.) None of these

Answer: Option 'B'

Formula:-(Date + Month code + No.of years + No.of leap year + Century code)/7 
= (24 + 0 + 11 + 2 + 6)/7 = 43/7 = 1 
= Sunday

3.

It was Sunday on January-1-2006. Find the day of the week on January-1-2010? 

   A.) Sunday
   B.) Saturday
   C.) Friday
   D.) Wednesday

Answer: Option 'C'

Answer: Option 'C' 
On 31st December, 2005 it was Saturday. 
Number of odd days from the year 200 to the tear 2009 = ( 1 + 1 + 2 + 1 ) = 5days
On 31st December 2009, it was Thursday. 
Thus, on 1st Jan, 2010 it is Friday.

4.

On 2007, What was the date of last Saturday in May month? 

   A.) 21
   B.) 22
   C.) 25
   D.) 26

Answer: Option 'D'

1 - May - 2007 
=(1 + 2 + 7 + 1 + 6)/7 = 17/7 = 3 = Tuesday 
= May 1st --> Tuesday + 5 days = Saturday = 5th may
5th may + 7 days = Saturday = 12th may
12th may + 7 days = Saturday = 19th may
19th may + 7 days = Saturday = 26th may
= Answer = 26th may

5.

What was the day of the week on 17th June, 1998 

   A.) Tuesday
   B.) Monday
   C.) Sunday
   D.) Wednesday

Answer: Option 'D'

17th June, 1998 = (1997 years + Period from 1.1.1998 to 17.6.1998)
Odd days in 1600 years = 0 
Odd days in 300 years = (5 × 3) = 1 
97 years has 24 leap years + 73 ordinary years.
Number of odd days in 97 years = (24 × 2 + 73) = 121 = 2 odd days
Jan Feb March April May June 
31 + 28 + 31 + 30 + 31 + 17 = 168 days = 24 weeks = 0 odd day
Total number of odd days = (0 + 1 + 2 + 0) = 3 
Given day is Wednesday

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