1.
Answer: Option 'B'
Formula:-(Date + Month code + No.of years + No.of leap year + Century code)/7
= (24 + 0 + 11 + 2 + 6)/7 = 43/7 = 1
= Sunday
2.
What was day of the week on 21-September-1987?
Answer: Option 'B'
Formula:-(Date + Month code + No.of years + No.of leap year + Century code)/7
= (21 + 6 + 87 + 21 + 0)/7 = 135/7 = 2
= Monday
3.
What was the day of the week on 26-January-1950?
Answer: Option 'D'
Formula:-(Date + Month code + No.of years + No.of leap year + Century code)/7
= (26 + 1 + 50 + 12 + 0)/7 = 84/7 = 5
= Thursday
4.
Today is Monday, after 61 days, the day will be:
Answer: Option 'B'
Each day of the week is repeated after 7 days.
So, after 63 days, it will be Monday.
After 61 days, it will be saturday.
5.
Which of the following is not a leap year?
Answer: Option 'A'
The century divisible by 400 is a leap year.
The tear 700 is not a leap year
6.
Today is Friday, after 126 days, it will be:
Answer: Option 'C'
126/7 = 0
Each day of the week is repeated after 7 days.
So, after 126 days, it will be Friday.
After 126 days, it will be Friday.
7.
How many days are there in x weeks X days?
Answer: Option 'B'
x weeks x days = (7x + x) days = 8x days
8.
It was Sunday on January-1-2006. Find the day of the week on January-1-2010?
Answer: Option 'C'
Answer: Option 'C'
On 31st December, 2005 it was Saturday.
Number of odd days from the year 200 to the tear 2009 = ( 1 + 1 + 2 + 1 ) = 5days
On 31st December 2009, it was Thursday.
Thus, on 1st Jan, 2010 it is Friday.
9.
What was the day of the week on 7th October, 2003?
Answer: Option 'B'
Formula = ( Date + Monthcode + No.of years + No.of leapyears + Century code )/ 7
==> (7 + 1 + 3 + 0 + 6)/7 = 17/7 = 3
==> Tuesday
10.
On 2007, What was the date of last Saturday in May month?
Answer: Option 'D'
1 - May - 2007
=(1 + 2 + 7 + 1 + 6)/7 = 17/7 = 3 = Tuesday
= May 1st --> Tuesday + 5 days = Saturday = 5th may
5th may + 7 days = Saturday = 12th may
12th may + 7 days = Saturday = 19th may
19th may + 7 days = Saturday = 26th may
= Answer = 26th may
11.
What was the day of the week on 10th March 1996?
Answer: Option 'A'
(10 + 4 + 96 + 24 + 0)/7 = 134/7 = 1
= Sunday
12.
On 8th February 2005, it was Tuesday. What was the day of the week on 8 February 2004?
Answer: Option 'C'
The year 2004 is a leap year. It has 2 odd days.
The day on 8th Feb, 2004 is 2 days before the day on 8th Feb, 2005
Hence, this day is Sunday.
13.
What was the day of the week on 17th June, 1998
Answer: Option 'D'
17th June, 1998 = (1997 years + Period from 1.1.1998 to 17.6.1998)
Odd days in 1600 years = 0
Odd days in 300 years = (5 × 3) = 1
97 years has 24 leap years + 73 ordinary years.
Number of odd days in 97 years = (24 × 2 + 73) = 121 = 2 odd days
Jan Feb March April May June
31 + 28 + 31 + 30 + 31 + 17 = 168 days = 24 weeks = 0 odd day
Total number of odd days = (0 + 1 + 2 + 0) = 3
Given day is Wednesday
14.
It was Thursday on 2nd Jan 1993. What day of the week will be on 15th March 1993?
Answer: Option 'C'
Today number of days = 29(Jan) + 28 (Feb) + (15) Mar = 72 days 10 Weeks + 2 days.
Thus the given date will fall on two days beyond Thursday, that is Saturday.
15.
January 1, 2008 is Tuesday. What day of the week lies on January 1, 2009?
Answer: Option 'C'
The year 2008 is a leap year. So it has 2 odd days.
1st day of the year 2008 is Tuesday (given)
So, 1st day of the year 2009 is 2 days beyond Tuesday. So it has to be Thursday.
16.
On what dates on April 2001 did Wednesday fall?
Answer: Option 'C'
We shall find the day on 1st April 2001 1st April 2001 = 2000 years + Period from 1.1.2001 to 1.4.2001 Odd days in 1600 years = 0 Odd days in 400 years = 0 Jan, Feb, Mar, April = 31 + 28 + 31 + 1 = 91 days = 0 odd days On 1st April it is Sunday.
In April, 2001 Wednesday falls on 4th , 11th , 18th and 25th .
17.
It was Sunday on Jan 1, 2006. What was the day of the week Jan 1, 2010?
Answer: Option 'B'
On 31 Dec, 2005 it was Saturday.
Number of Odd days from the year 2006 to the year 2009 = 1 +1+2+1 =5 On 31st Dec 2009 it was Thursday So, 1st Jan 2010 is Friday