RRB NTPC - Co Ordinate Geometry - Problems and Solutions

1.

In which quadrant does the point(-7, 6) lie? 

   A.) 1st
   B.) 2nd
   C.) 3rd
   D.) 4th

Answer: Option 'B'

The point (-7, 6) lies in 2nd quadrant.

2.

In which quadrant does the point(1, 5) lie? 

   A.) 1st
   B.) 2nd
   C.) 3rd
   D.) 4th

Answer: Option 'A'

The point (1, 5) lies in 1st quadrant.

3.

Find the value of k for which the points A(-2, 6), B(5, k) and C(8, 3) are collinear. 

   A.) 5
   B.) 4
   C.) 7
   D.) 1

Answer: Option 'A'

x1 = -2, x2 = 5, x3 = 8 and y1 = 6, y2 = k, y3 = 3 
Now Δ = 0 <=> -2(k - 3) + 5(3 - 6) + 8(6 - k) = 0 
      <=> -2 (k-3) + 5(-3) + 8(6-k) = 0 
      <=> -2k + 6 - 15 + 48 - 8k = 0 
      <=> 39 - 10k = 0 
      <=> k = -(39/10) 
      <=> k = 3.9.

4.

In which quadrant does the point(9, 0) lie? 

   A.) x-axis
   B.) y-axis
   C.) 4th
   D.) None of these

Answer: Option 'A'

The point (9, 0) lies in y-axis.

5.

The distance between the points A(5, -7) and B(2, 3) is:

   A.) 109
   B.) 5√7
   C.) √109
   D.) None of these

Answer: Option ''

AB2 = (2 - 5)2 + (3 + 7)2 
=> (-3)2 + (10)2 
=> 9 + 100 => √109

Co Ordinate Geometry Download Pdf