1.
A sum of money is invested at 10% per annum compounding annually for 2 years. If the interest received is Rs. 210, find the principal.
Answer: Option 'B'
Given, r = 10%
n = 2 years
Compound interest, C.I = Rs. 210
Compound Interest = Amount – Principal
=> C.I = P {[1 + (r/100)]n - 1}
=> 210 = P {[1 + (10/100)]2 - 1}
=> 210 = P {[1 + (1/10)]2 - 1}
=> 210 = P {[(10 + 1)/10]2 - 1}
=> 210 = P {[11/10]^2 - 1}
=> 210 = P {[121 / 100] – 1}
=> 210 = P {(121 – 100) / 100}
=> 210 = P {21 / 100}
=> P = (210 × 100) / 21
=> P = 1000 Rs.
Thus, Principal = Rs. 1000
2.
The Compound interest of Rs.10240/- at 6 ¼% per annum for 2 years 292days is:
Answer: Option 'A'
Rs.1898/-
3.
Find the simple interest on Rs. 1300 at 10 % per annum for 5 years
Answer: Option 'A'
Given
Principal : 1300
Rate of interest : 10
Number of years : 5
Simple Interest = pnr / 100
Simple Interest = (1300 x 5 x 10) / 100
= 13 x 5 x 10
= 650
So,Simple Interest = 650
4.
What would be the compound interest accrued on an amount of 4500 Rs. at the end of 2 years at the rate of 10 % per annum ?
Answer: Option 'B'
Given principal = 4500
No. of years = 2
Rate of interest = 10
Amount = P x (1+r/100)n,
We get Amount = 4500 x (1+10/100)2
Ans : 5445
5.
What would be the compound interest accrued on an amount of 11500 Rs. at the end of 2 years at the rate of 10 % per annum ?
Answer: Option 'B'
Given
Principal = 11500 No. of years = 2 Rate of interest = 10
Amount = P x (1+r/100)n,
we get Amount = 11500 x (1+10/100)2
= 11500 x ( 110 / 100 )2
= 115 x 11 x 11
= 115 x 121
Ans : 13915