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Number System : Aptitude Test


  • 1. What is the place value of 7 in the numeral 2734? 
A.) 70
B.) 7
C.) 700
D.) 7.00

Answer: Option 'C'

7 × 100 = 700

  • 2. What is the place value of 3 in the numeral 3259 
A.) 300
B.) 30
C.) 3
D.) 3000

Answer: Option 'D'

3 × 1000 = 3000

  • 3. What is the diffference between the place value of 2 in the numeral 7229? 
A.) 20
B.) 200
C.) 180
D.) 18

Answer: Option 'C'

200 - 20 = 180

  • 4. What is the place value of 0 in the numeral 2074?
A.) 100
B.) 70
C.) 7.0
D.) 0

Answer: Option 'D'

Note : The place value of zero (0) is always 0. It may hold any place in a number,
its value is always 0.

  • 5. What is the diffference between the place value and face value of 3 in the numeral 1375? 
A.) 300
B.) 3
C.) 297
D.) 303

Answer: Option 'C'

place value of 3 = 3 × 100 = 300 
face value of 3 = 3
300 - 3 = 297

  • 6. A number when divided by a divisor leaves a remainder of 24.
    When twice the original number is divided by the same divisor, the remainder is 11. What is the value of the divisor? 
A.) 73
B.) 37
C.) 64
D.) 53

Answer: Option 'B'

Let the original number be 'a'
Let the divisor be 'd'
Let the quotient of the division of aa by dd be 'x'
Therefore, we can write the relation as a/d = x and the remainder is 24.
i.e., a=dx+24 When twice the original number is divided by d, 2a is divided by d.
We know that a=dx+24. Therefore, 2a = 2dx + 48
The problem states that (2dx+48)/d leaves a remainder of 11.
2dx2dx is perfectly divisible by d and will therefore, not leave a remainder.
The remainder of 11 was obtained by dividing 48 by d.
When 48 is divided by 37, the remainder that one will obtain is 11.
Hence, the divisor is 37.

  • 7. The largest number amongst the following that will perfectly divide 101100 – 1 is: 
A.) 100
B.) 10000
C.) 100^100
D.) 10

Answer: Option 'C'

The easiest way to solve such problems for objective exam purposes is trial and error or by back
substituting answers in the choices given.
1012 = 10,201
1012 − 1 = 10,200. 
This is divisible by 100. 
Similarly try for 1013 − 1 = 1,030,301−1 = 1,030,300.
So you can safely conclude that (1011 − 1) to (1019 − 1) will be divisible by 100.
(10110 − 1) to (10199 − 1) will be divisible by 1000. 
Therefore, (101100 − 1) will be divisible by 10,000.

To whom this Number System Question and Answers section is beneficial?

Students can learn and improve on their skillset for using Number System effectively and can also prepare for competitive examinations like...

  • All I.B.P.S and Public Sector Bank Competitive Exam
  • Common Aptitude Test (CAT) Exams
  • UPSC Paper-II or CSAT Exams
  • SSC Competitive Exams
  • Defence Competitive Exams
  • NIIT online mock test
  • L.I.C Assistant Administrative Officer (AAO)/ G.I.C AAO and Clerk Competitive Exams
  • Railway Competitive Exam
  • University Grants Commission (UGC)
  • Career Aptitude Test (IT Companies) and etc.

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