# Percentage : Aptitude Test

1.

33 1/3% OF 240?

A.) 72
B.) 16
C.) 80
D.) None of these

33 1/3 % = 1/3
1/3 × 240 = 80

2.

11 1/9 % of 900?

A.) 100
B.) 20
C.) 81
D.) None of these

11 1/9 % = 1/9
1/9 × 900 = 100

3.

Express 2/5 as rate percent:

A.) 80%
B.) 60%
C.) 40%
D.) None of these

2/5 × 100 % = 200/5 % = 40 %

4.

Express 3/4 as rate percent.

A.) 80%
B.) 30%
C.) 75%
D.) 25%

3/4 × 100 = 300/4 % = 75 %

5.

What percent is 70 of 280?

A.) 25%
B.) 50%
C.) 75%
D.) None of these

70/280 = 1/4
1/4 × 100 = 25 %

6.

What percent is 120 of 90?

A.) 132 1/3%
B.) 132 2/3%
C.) 133 1/3%
D.) None of these

120/90 = 4/3
4/3 × 100 = 400/3 = 133 1/3 %

7.

What percent is 5 gm of 1 kg?

A.) 0.05%
B.) 0.5%
C.) 0.005%
D.) None of these

1 kg = 1000 gm
5/1000 × 100 = 500/1000
=1/2 = 0.5 %

8.

What percent is 36paisa's of 12 rupees?

A.) 3%
B.) 0.03%
C.) 0.03%
D.) None of these

12 Rupees = 1200paisa's
36/1200 × 100 = 3/12
12/3 = 3 %

9.

A number increased by 20% gives 480. The number is

A.) 380
B.) 420
C.) 400
D.) 300

Formula = TOTAL=100% ,INCRESE = "+" DECREASE= "-"
A number means = 100 %
That same number increased by 20 % = 120 %
120 % -------> 480 (120 × 4 = 480)
100 % -------> 400 (100 × 4 = 400)

10.

Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. What are the marks obtained by them?

A.) 42, 33
B.) 44, 36
C.) 43, 36
D.) 42, 36

Let the marks secured by them be x and (x + 9)
Then sum of their marks = x + (x + 9) = 2x + 9
Given that (x + 9) was 56% of the sum of their marks
=>(x+9) = 56/100(2x+9)
=>(x+9) = 14/25(2x+9)
=> 25x + 225 = 28x + 126
=> 3x = 99
=> x = 33
Then (x + 9) = 33 + 9 = 42
Hence their marks are 33 and 42

11.

If 20% of a = b, then b% of 20 is the same as:

A.) 10% of a
B.) 25% of a
C.) 4% of a
D.) None of these

20% of a = b
=> b = 20/100a
b% of 20 = (b/100)20 = [(20/100a)/100]20
= (20 × 20 × a)/(100 × 100)
= 4a/100 = 4% of a

12.

Two employees X and Y are paid a total of Rs. 550 per week by their employer. If X is paid 120 percent of the sum paid to Y, how much is Y paid per week?

A.) Rs. 150
B.) Rs. 300
C.) Rs. 250
D.) Rs. 200

Let the amount paid to X per week = x
and the amount paid to Y per week = y
Then x + y = 550
But x = 120% of y = 120y/100 = 12y/10
∴12y/10 + y = 550
⇒ y[12/10 + 1] = 550
⇒ 22y/10 = 550
⇒ 22y = 5500
⇒ y = 5500/22 = 500/2 = Rs.250

13.

Rahul went to a shop and bought things worth Rs. 25, out of which 30 Paise went on sales tax on taxable purchases. If the tax rate was 6%, then what was the cost of the tax free items?

A.) Rs. 19.70
B.) Rs. 19.2
C.) Rs. 19.85
D.) Rs. 18.70

Total cost of the items he purchased = Rs.25
Given that out of this Rs.25, 30 Paise is given as tax
=> Total tax incurred = 30 Paise = Rs.30/100
Let the cost of the tax free items = x
Given that tax rate = 6%
∴ (25−30/100−x)6/100 = 30/100
⇒ 6(25 −0.3 −x) = 30
⇒ (25 − 0.3 − x) = 5
⇒ x = 25 − 0.3 − 5 = 19.7

14.

The Shopkeeper increased the price of a product by 25% so that customer finds it difficult to purchase the required amount. But somehow the customer managed to purchase only 70% of the required amount. What is the net difference in the expenditure on that product?

A.) 10% more
B.) 5% more
C.) 12.5% more
D.) 17.5% more

Quantity X Rate = Price
1 x 1 = 1
0.7 x 1.25 = 0.875
Decrease in price = (0.125/1) × 100 = 12.5%

15.

In a competitive examination in State A, 6% candidates got selected from the total appeared candidates. State B had an equal number of candidates appeared and 7% candidates got selected with 80 more candidates got selected than A. What was the number of candidates appeared from each State?

A.) 8000
B.) 8200
C.) 8020
D.) 7800

State A and State B had an equal number of candidates appeared.
In state A, 6% candidates got selected from the total appeared candidates
In state B, 7% candidates got selected from the total appeared candidates
But in State B, 80 more candidates got selected than State A
From these, it is clear that 1% of the total appeared candidates in State B = 80
=> total appeared candidates in State B = 80 x 100 = 8000
=> total appeared candidates in State A = total appeared candidates in State B = 8000

16.

Number decreased by 20% gives 480. The number is:

A.) 500
B.) 600
C.) 550
D.) None of these

Formula = TOTAL=100% ,INCRESE = "+" DECREASE= "-"
A number means = 100 %
That same number Decreased by 20 % = 80 %
80 % ------> 480 (80 × 6 = 480)
100 % ------> 600 (100 × 6 = 600)

17.

If 20% of a certain number is 80, then what is 30% of that number?

A.) 100
B.) 120
C.) 140
D.) 150

20% = 20 × 4 = 80
30% = 30 × 4= 120

18.

If 40% of a certain number is 120, then what is 90% of that number?

A.) 150
B.) 200
C.) 240
D.) 270

40% = 40 × 3 = 120
90% = 90 × 3 = 270

19.

When a number is first increased by 10% and then reduced by 10%, The number is:

A.) Does not change
B.) Decreases by 1%
C.) Increases by 1%
D.) None of these

Farmula = AFTER INCREASED 10% × AFTER REDUCED 10%/TOTAL 100%
= 110 × 90/100 = 99 %
= Decreases by 1%

20.

The Shopkeeper increased the price of a product by 25% so that customer finds it difficult to purchase the required amount. But somehow the customer managed to purchase only 70% of the required amount. What is the net difference in the expenditure on that product?

A.) 10% more
B.) 5% more
C.) 12.5% more
D.) 17.5% more