#### Quantitative Aptitude Problems With Answers - Free Online Practice Test

- Quantitative Aptitude Problems With Answers All Chapters with multiple Examples
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1.

33 1/3% OF 240?

**Answer: Option 'C'**

**33 1/3 % = 1/3
1/3 × 240 = 80**

2.

11 1/9 % of 900?

**Answer: Option 'A'**

**11 1/9 % = 1/9
1/9 × 900 = 100**

3.

Express 2/5 as rate percent:

**Answer: Option 'C'**

**2/5 × 100 % = 200/5 % = 40 %**

4.

Express 3/4 as rate percent.

**Answer: Option 'C'**

**3/4 × 100 = 300/4 % = 75 %**

5.

What percent is 70 of 280?

**Answer: Option 'A'**

**70/280 = 1/4
1/4 × 100 = 25 %**

6.

What percent is 120 of 90?

**Answer: Option 'C'**

**120/90 = 4/3
4/3 × 100 = 400/3 = 133 1/3 %**

7.

What percent is 5 gm of 1 kg?

**Answer: Option 'B'**

**1 kg = 1000 gm
5/1000 × 100 = 500/1000
=1/2 = 0.5 %**

8.

What percent is 36paisa's of 12 rupees?

**Answer: Option 'A'**

**12 Rupees = 1200paisa's
36/1200 × 100 = 3/12
12/3 = 3 %**

9.

A number increased by 20% gives 480. The number is

**Answer: Option 'C'**

**Formula = TOTAL=100% ,INCRESE = "+" DECREASE= "-"
A number means = 100 %
That same number increased by 20 % = 120 %
120 % -------> 480 (120 × 4 = 480)
100 % -------> 400 (100 × 4 = 400)**

10.

Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. What are the marks obtained by them?

**Answer: Option 'A'**

**Let the marks secured by them be x and (x + 9)
Then sum of their marks = x + (x + 9) = 2x + 9
Given that (x + 9) was 56% of the sum of their marks
=>(x+9) = 56/100(2x+9)
=>(x+9) = 14/25(2x+9)
=> 25x + 225 = 28x + 126
=> 3x = 99
=> x = 33
Then (x + 9) = 33 + 9 = 42
Hence their marks are 33 and 42**

#### Quantitative Aptitude Problems With Answers - Free Online Practice Test

- Quantitative Aptitude Problems With Answers All Chapters with multiple Examples
- Latest model Quant Questions for SBI PO - Free online Practice Test 1
- Latest model Quant Questions for SBI PO - Free online Practice Test 2
- Problems on Trains : Quantitative Aptitude
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- SBI PO Mains 2017 Free Online Exams Mock test
- Time and Work - Quantitative Aptitude

11.

If 20% of a = b, then b% of 20 is the same as:

**Answer: Option 'C'**

**20% of a = b
=> b = 20/100a
b% of 20 = (b/100)20 = [(20/100a)/100]20
= (20 × 20 × a)/(100 × 100)
= 4a/100 = 4% of a**

12.

Two employees X and Y are paid a total of Rs. 550 per week by their employer. If X is paid 120 percent of the sum paid to Y, how much is Y paid per week?

**Answer: Option 'C'**

**Let the amount paid to X per week = x
and the amount paid to Y per week = y
Then x + y = 550
But x = 120% of y = 120y/100 = 12y/10
∴12y/10 + y = 550
⇒ y[12/10 + 1] = 550
⇒ 22y/10 = 550
⇒ 22y = 5500
⇒ y = 5500/22 = 500/2 = Rs.250**

13.

Rahul went to a shop and bought things worth Rs. 25, out of which 30 Paise went on sales tax on taxable purchases. If the tax rate was 6%, then what was the cost of the tax free items?

**Answer: Option 'A'**

**Total cost of the items he purchased = Rs.25
Given that out of this Rs.25, 30 Paise is given as tax
=> Total tax incurred = 30 Paise = Rs.30/100
Let the cost of the tax free items = x
Given that tax rate = 6%
∴ (25−30/100−x)6/100 = 30/100
⇒ 6(25 −0.3 −x) = 30
⇒ (25 − 0.3 − x) = 5
⇒ x = 25 − 0.3 − 5 = 19.7**

14.

The Shopkeeper increased the price of a product by 25% so that customer finds it difficult to purchase the required amount. But somehow the customer managed to purchase only 70% of the required amount. What is the net difference in the expenditure on that product?

**Answer: Option 'C'**

**Quantity X Rate = Price
1 x 1 = 1
0.7 x 1.25 = 0.875
Decrease in price = (0.125/1) × 100 = 12.5%**

15.

In a competitive examination in State A, 6% candidates got selected from the total appeared candidates. State B had an equal number of candidates appeared and 7% candidates got selected with 80 more candidates got selected than A. What was the number of candidates appeared from each State?

**Answer: Option 'A'**

**State A and State B had an equal number of candidates appeared.
In state A, 6% candidates got selected from the total appeared candidates
In state B, 7% candidates got selected from the total appeared candidates
But in State B, 80 more candidates got selected than State A
From these, it is clear that 1% of the total appeared candidates in State B = 80
=> total appeared candidates in State B = 80 x 100 = 8000
=> total appeared candidates in State A = total appeared candidates in State B = 8000**

16.

Number decreased by 20% gives 480. The number is:

**Answer: Option 'B'**

**Formula = TOTAL=100% ,INCRESE = "+" DECREASE= "-"
A number means = 100 %
That same number Decreased by 20 % = 80 %
80 % ------> 480 (80 × 6 = 480)
100 % ------> 600 (100 × 6 = 600)**

17.

If 20% of a certain number is 80, then what is 30% of that number?

**Answer: Option 'B'**

**20% = 20 × 4 = 80
30% = 30 × 4= 120**

18.

If 40% of a certain number is 120, then what is 90% of that number?

**Answer: Option 'D'**

**40% = 40 × 3 = 120
90% = 90 × 3 = 270**

19.

When a number is first increased by 10% and then reduced by 10%, The number is:

**Answer: Option 'B'**

**Farmula = AFTER INCREASED 10% × AFTER REDUCED 10%/TOTAL 100%
= 110 × 90/100 = 99 %
= Decreases by 1%**

20.

The Shopkeeper increased the price of a product by 25% so that customer finds it difficult to purchase the required amount. But somehow the customer managed to purchase only 70% of the required amount. What is the net difference in the expenditure on that product?

**Answer: Option 'C'**

**Quantity X Rate = Price
1 x 1 = 1
0.7 x 1.25 = 0.875
Decrease in price = (0.125/1) × 100 = 12.5%**

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