1.

In an examination it is required to get 40% of minimum marks to pass. A student got 142 marks, Thus he got 22 marks more than minimum marks required to pass. What is total marks?

**Answer: Option 'C'**

**40 % ------> 120 ( 40 × 3 = 120 )
100 % ------> 300 ( 100 × 3 = 300 )**

2.

If X is 20% greater than Y, Z is 20% smaller than how much percent is X greater than Z?

**Answer: Option 'B'**

**X = 120
Y = 100
Z = 80
X-Z/Z × 100 = 40/80 × 100 = 50 % greater than Z**

3.

Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. The marks obtained by them are:

**Answer: Option 'C'**

**Let their marks be (x + 9) and x.
Then, x + 9 = (56/100)(x+9+x)
25(x+9) = 14(2x + 9)
3x = 99
x = 33
So, their marks are **

4.

Out of the first 75 natural numbers, what percentage of them have 7 either in the units place or the tens place?

**Answer: Option 'B'**

**There are 13 numbers.
(7, 17, 27, 37, 47, 57, 67, 70, 71, 72, 73, 74, 75) * 100 = 17.33%**

5.

If X,Y is 20%,30% smaller than Z then how much percentage is Y greater than X?

**Answer: Option 'C'**

**X = 80 %
Y = 70 %
Z = 100 %
X-Y/X × 100 = 10/80 × 100 = 12 1/2 % greater than X**

6.

In a competitive examination in State A, 6% candidates got selected from the total appeared candidates. State B had an equal number of candidates appeared and 7% candidates got selected with 80 more candidates got selected than A. What was the number of candidates appeared from each State?

**Answer: Option 'A'**

**State A and State B had an equal number of candidates appeared.
In state A, 6% candidates got selected from the total appeared candidates
In state B, 7% candidates got selected from the total appeared candidates
But in State B, 80 more candidates got selected than State A
From these, it is clear that 1% of the total appeared candidates in State B = 80
=> total appeared candidates in State B = 80 x 100 = 8000
=> total appeared candidates in State A = total appeared candidates in State B = 8000**

7.

The population of a town increases 10% and 20% respectively in two consecutive years. After the growth the present population of the town is 13200. Then what is the population of the town 2 years ago?

**Answer: Option 'C'**

**Formula :
( After =100 denominator
Ago = 100 numerator)
13200 × 100/110 × 100/120 = 10000 **

8.

Two employees X and Y are paid a total of Rs. 550 per week by their employer. If X is paid 120 percent of the sum paid to Y, how much is Y paid per week?

**Answer: Option 'C'**

**Let the amount paid to X per week = x
and the amount paid to Y per week = y
Then x + y = 550
But x = 120% of y = 120y/100 = 12y/10
∴12y/10 + y = 550
⇒ y[12/10 + 1] = 550
⇒ 22y/10 = 550
⇒ 22y = 5500
⇒ y = 5500/22 = 500/2 = Rs.250**

9.

In an elaction between two candidates, 20% of votes are were declares invalid. First candidate got 480 votes which were 60% of the total valid votes . The total number of votes enrolled in that election was:

**Answer: Option 'B'**

**(100%-20%=80%
48%-32%=16%
16% = 16×30 = 480
100% =100×30 =3000 votes)**

10.

What percent is 70 of 280?

**Answer: Option 'A'**

**70/280 = 1/4
1/4 × 100 = 25 %**

11.

In an election between two candidates first candidate got 60% of votes polled and second Candidate got 280 votes. The total number of votes polled was?

**Answer: Option 'A'**

**Total = 100 %,
First person got 60%
second person got remaining 40 % of votes.
than 40 % = 280
40% = 40×7 = 280
100% =100×7 =700votes**

12.

11 1/9 % of 900?

**Answer: Option 'A'**

**11 1/9 % = 1/9
1/9 × 900 = 100**

13.

In an election, the winning candidate got 58% of the valid votes. If he got 1600 votes more than the other candidate and 100 votes were invalid, find the number of votes cast.

**Answer: Option 'D'**

**Let the number of valid votes be x
Winning candidate - 58% of x
Other candidate - 42% of x
Difference - 16% of x
16% of x = 1600
x = 10000
Total votes = 10000 + 100 = 10100**

14.

In an election between the two candidates ,The candidates who gets 60% of votes polled is winned by 280 votes majority. What is the total number of votes polled?

**Answer: Option 'B'**

**Note : majority (20 %) = difference in votes polled to win (60 %) & defeated candidates (40 %)
20 % = 60 % - 40 %
20% -----> 280 (20×14 = 280 )
100% -----> 1400 (100×14 = 1400)**

15.

A mixture of 20 litres of milk and water contains 20% of water. The new mixture is formed by adding 5 lit of water. What is the percentage of milk in the new mixture?

**Answer: Option 'C'**

**(20 li = 4 li water 16 li milk
-------- 5 li water
Total = 9 li water 16 li milk (new)
16/25×100=64%**

16.

Ganesh scored 93% in his exams. If he scored 84 marks less than the maximum marks. Find the maximum marks

**Answer: Option 'B'**

**He scored 7% less than the maximum marks.
7% of x = 84 x = 1200**

17.

When a number is first increased by 10% and then reduced by 10%, The number is:

**Answer: Option 'B'**

**Farmula = AFTER INCREASED 10% × AFTER REDUCED 10%/TOTAL 100%
= 110 × 90/100 = 99 %
= Decreases by 1%**

18.

In a class 60% of students passed in telugu, 50% 0f students passde in english. Then if every student Passed in either telugu or english or both the subjects. Then what is the percentage of students passed In both the subjects?

**Answer: Option 'A'**

**passed in Telugu = 60 %
passed in English = 50 %
only passed in telugu = 50%
only passed in english = 40%
the percentage of studebts passed in both the subjects = 10 %**

19.

If 40% of a certain number is 120, then what is 90% of that number?

**Answer: Option 'D'**

**40% = 40 × 3 = 120
90% = 90 × 3 = 270**

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20.

The population of a town is 8100. It decreases annually at the rate of 10% p.a. What was its population 2 years ago?

**Answer: Option 'C'**

**Formula :
( After =100 denominator
Ago = 100 numerator)
8100 × 100/90 × 100/90 = 10000**

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