1.
Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. What are the marks obtained by them?
Answer: Option 'A'
Let the marks secured by them be x and (x + 9)
Then sum of their marks = x + (x + 9) = 2x + 9
Given that (x + 9) was 56% of the sum of their marks
=>(x+9) = 56/100(2x+9)
=>(x+9) = 14/25(2x+9)
=> 25x + 225 = 28x + 126
=> 3x = 99
=> x = 33
Then (x + 9) = 33 + 9 = 42
Hence their marks are 33 and 42
2.
Ganesh scored 93% in his exams. If he scored 84 marks less than the maximum marks. Find the maximum marks
Answer: Option 'B'
He scored 7% less than the maximum marks.
7% of x = 84 x = 1200
3.
If X,Y is 20%,25% greater than Z then how much percentage is X smaller than Y?
Answer: Option 'C'
X = 120%
Y = 125%
Z = 100%
X-Y/Y × 100 = 5/125 × 100 = 4 % smaller than Y
4.
In a class 60% of students passed in telugu, 50% 0f students passde in english. Then if every student Passed in either telugu or english or both the subjects. Then what is the percentage of students passed In both the subjects?
Answer: Option 'A'
passed in Telugu = 60 %
passed in English = 50 %
only passed in telugu = 50%
only passed in english = 40%
the percentage of studebts passed in both the subjects = 10 %
5.
In a class 60% of students passed in telugu, 50% 0f students passde in english and 20% of students passed in both the subjects then what is the percentage the students who failed in the both the subjects?
Answer: Option 'B'
only t = 40,only e = 30 and both subjects passed 20%
10% failed in both subjects
6.
A mixture of 30 litres of milk and water contains 30% of water. The new mixture is formed by adding 10 lit of water. What is the percentage of water in the new mixture?
Answer: Option 'D'
(30 li = 9 li water 21 li milk
------= 10 li water
Total = 19li water 21 li milk (new)
19/40 × 100 = 47 1/2%
7.
In a cricket match, Dravid scored a century with 13 boundaries and 3 sixes. What percentage of his runs did he make by running between the wickets?
Answer: Option 'D'
Runs scored in boundaries and sixes = (13 × 4) + (3 × 6) = 52 + 18 = 70 Runs
Scored between the wickets = 100 -70 = 30
30% of the runs are scored by running between the wickets.
8.
What percent is 36paisa's of 12 rupees?
Answer: Option 'A'
12 Rupees = 1200paisa's
36/1200 × 100 = 3/12
12/3 = 3 %
9.
In an election between two candidates first candidate got 60% of votes polled and second Candidate got 280 votes. The total number of votes polled was?
Answer: Option 'A'
Total = 100 %,
First person got 60%
second person got remaining 40 % of votes.
than 40 % = 280
40% = 40×7 = 280
100% =100×7 =700votes
10.
The population of a town is 10000. It increases annually at the rate of 20% p.a. What will be its population after 2 years?
Answer: Option 'C'
Formula :
( After =100 denominator
Ago = 100 numerator)
10000 × 120/100 × 120/100 = 14400
11.
Number decreased by 20% gives 480. The number is:
Answer: Option 'B'
Formula = TOTAL=100% ,INCRESE = "+" DECREASE= "-"
A number means = 100 %
That same number Decreased by 20 % = 80 %
80 % ------> 480 (80 × 6 = 480)
100 % ------> 600 (100 × 6 = 600)
12.
The population of a town is 8000. It decreases annually at the rate of 20% p.a. What will be its population after 2 years?
Answer: Option 'B'
Formula :
( After =100 denominator
Ago = 100 numerator)
8000 × 80/100 × 80/100 = 5120
13.
If the length and breadth of a cuboid are halved and the height is doubled, find the % change in volume.
Answer: Option 'C'
New volume = (1/2) × (b/2) × 2h = (lbh/2)
So, there is 50% decrease.
14.
What percent is 70 of 280?
Answer: Option 'A'
70/280 = 1/4
1/4 × 100 = 25 %
15.
Two employees X and Y are paid a total of Rs. 550 per week by their employer. If X is paid 120 percent of the sum paid to Y, how much is Y paid per week?
Answer: Option 'C'
Let the amount paid to X per week = x
and the amount paid to Y per week = y
Then x + y = 550
But x = 120% of y = 120y/100 = 12y/10
∴12y/10 + y = 550
⇒ y[12/10 + 1] = 550
⇒ 22y/10 = 550
⇒ 22y = 5500
⇒ y = 5500/22 = 500/2 = Rs.250
16.
A number increased by 20% gives 480. The number is
Answer: Option 'C'
Formula = TOTAL=100% ,INCRESE = "+" DECREASE= "-"
A number means = 100 %
That same number increased by 20 % = 120 %
120 % -------> 480 (120 × 4 = 480)
100 % -------> 400 (100 × 4 = 400)
17.
11 1/9 % of 900?
Answer: Option 'A'
11 1/9 % = 1/9
1/9 × 900 = 100
18.
If 20% of a = b, then b% of 20 is the same as:
Answer: Option 'C'
20% of a = b
=> b = 20/100a
b% of 20 = (b/100)20 = [(20/100a)/100]20
= (20 × 20 × a)/(100 × 100)
= 4a/100 = 4% of a
19.
If X,Y is 20%,30% smaller than Z then how much percentage is Y greater than X?
Answer: Option 'C'
X = 80 %
Y = 70 %
Z = 100 %
X-Y/X × 100 = 10/80 × 100 = 12 1/2 % greater than X
20.
The population of a town is 8100. It decreases annually at the rate of 10% p.a. What was its population 2 years ago?
Answer: Option 'C'
Formula :
( After =100 denominator
Ago = 100 numerator)
8100 × 100/90 × 100/90 = 10000