RRB NTPC - Percentage : Aptitude Test

1.

In an election between the two candidates ,The candidates who gets 60% of votes polled is winned by 280 votes majority. What is the total number of votes polled?

   A.) 1500
   B.) 1400
   C.) 1600
   D.) None of these

Answer: Option 'B'

Note : majority (20 %) = difference in votes polled to win (60 %) & defeated candidates (40 %) 
20 % = 60 % - 40 % 
20% -----> 280 (20×14 = 280 )
100% -----> 1400 (100×14 = 1400)

2.

What percent is 36paisa's of 12 rupees? 

   A.) 3%
   B.) 0.03%
   C.) 0.03%
   D.) None of these

Answer: Option 'A'

12 Rupees = 1200paisa's 
36/1200 × 100 = 3/12 
12/3 = 3 %

3.

Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. The marks obtained by them are:

   A.) 39, 33
   B.) 41, 33
   C.) 42, 33
   D.) 43, 33

Answer: Option 'C'

Let their marks be (x + 9) and x.
Then, x + 9 = (56/100)(x+9+x)
25(x+9) = 14(2x + 9)
3x = 99
x = 33
So, their marks are 42 and 33.

4.

In an elaction between two candidates, 20% of votes are were declares invalid. First candidate got 480 votes which were 60% of the total valid votes . The total number of votes enrolled in that election was: 

   A.) 450 votes
   B.) 3000 votes
   C.) 3200 votes
   D.) None of these

Answer: Option 'B'

(100%-20%=80% 
48%-32%=16% 
16% = 16×30 = 480 
100% =100×30 =3000 votes)

5.

If 20% of a certain number is 80, then what is 30% of that number? 

   A.) 100
   B.) 120
   C.) 140
   D.) 150

Answer: Option 'B'

20% = 20 × 4 = 80 
30% = 30 × 4= 120

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