# Percentage : Aptitude Test

1.

33 1/3% OF 240?

A.) 72
B.) 16
C.) 80
D.) None of these

33 1/3 % = 1/3
1/3 × 240 = 80

2.

11 1/9 % of 900?

A.) 100
B.) 20
C.) 81
D.) None of these

11 1/9 % = 1/9
1/9 × 900 = 100

3.

Express 2/5 as rate percent:

A.) 80%
B.) 60%
C.) 40%
D.) None of these

2/5 × 100 % = 200/5 % = 40 %

4.

Express 3/4 as rate percent.

A.) 80%
B.) 30%
C.) 75%
D.) 25%

3/4 × 100 = 300/4 % = 75 %

5.

What percent is 70 of 280?

A.) 25%
B.) 50%
C.) 75%
D.) None of these

70/280 = 1/4
1/4 × 100 = 25 %

6.

What percent is 120 of 90?

A.) 132 1/3%
B.) 132 2/3%
C.) 133 1/3%
D.) None of these

120/90 = 4/3
4/3 × 100 = 400/3 = 133 1/3 %

7.

What percent is 5 gm of 1 kg?

A.) 0.05%
B.) 0.5%
C.) 0.005%
D.) None of these

1 kg = 1000 gm
5/1000 × 100 = 500/1000
=1/2 = 0.5 %

8.

What percent is 36paisa's of 12 rupees?

A.) 3%
B.) 0.03%
C.) 0.03%
D.) None of these

12 Rupees = 1200paisa's
36/1200 × 100 = 3/12
12/3 = 3 %

9.

A number increased by 20% gives 480. The number is

A.) 380
B.) 420
C.) 400
D.) 300

Formula = TOTAL=100% ,INCRESE = "+" DECREASE= "-"
A number means = 100 %
That same number increased by 20 % = 120 %
120 % -------> 480 (120 × 4 = 480)
100 % -------> 400 (100 × 4 = 400)

10.

Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. What are the marks obtained by them?

A.) 42, 33
B.) 44, 36
C.) 43, 36
D.) 42, 36

Let the marks secured by them be x and (x + 9)
Then sum of their marks = x + (x + 9) = 2x + 9
Given that (x + 9) was 56% of the sum of their marks
=>(x+9) = 56/100(2x+9)
=>(x+9) = 14/25(2x+9)
=> 25x + 225 = 28x + 126
=> 3x = 99
=> x = 33
Then (x + 9) = 33 + 9 = 42
Hence their marks are 33 and 42