Percentage : Aptitude Test

1.

Two employees X and Y are paid a total of Rs. 550 per week by their employer. If X is paid 120 percent of the sum paid to Y, how much is Y paid per week? 

   A.) Rs. 150
   B.) Rs. 300
   C.) Rs. 250
   D.) Rs. 200

Answer: Option 'C'

Let the amount paid to X per week = x
and the amount paid to Y per week = y
Then x + y = 550
But x = 120% of y = 120y/100 = 12y/10 
∴12y/10 + y = 550
⇒ y[12/10 + 1] = 550
⇒ 22y/10 = 550
⇒ 22y = 5500
⇒ y = 5500/22 = 500/2 = Rs.250

2.

The Shopkeeper increased the price of a product by 25% so that customer finds it difficult to purchase the required amount. But somehow the customer managed to purchase only 70% of the required amount. What is the net difference in the expenditure on that product? 

   A.) 10% more
   B.) 5% more
   C.) 12.5% more
   D.) 17.5% more

Answer: Option 'C'

Quantity X Rate = Price
1 x 1 = 1
0.7 x 1.25 = 0.875
Decrease in price = (0.125/1) × 100 = 12.5%

3.

In a class 60% of students passed in telugu, 50% 0f students passde in english. Then every student Passed in either telugu or english or both the subjects and 120 members of students passed in both the subjects. How many number of students are their in the class? 

   A.) 1000
   B.) 1200
   C.) 1400
   D.) None of these

Answer: Option 'B'

only telugu passed = 50 % 
only english passed = 40 % 
both subjects passed student are 10 %, 
Then, 
10 % ------> 120 
100 % ------> 1200students

4.

In an examination it is required to get 30% of minimum marks to pass. A student got 110 marks and was declared failed by 10 marks difference. Then what is total marks:? 

   A.) 400
   B.) 500
   C.) 600
   D.) None of these

Answer: Option 'A'

30 % -------> 120 ( 30 × 4 = 120) 
100% -------> 400 (100 × 4 = 400)

6.

The population of a town is 8000. It decreases annually at the rate of 20% p.a. What will be its population after 2 years? 

   A.) 700 votes
   B.) 750 votes
   C.) 600 votes
   D.) 650 votes

Answer: Option 'B'

Formula : 
( After =100 denominator 
Ago = 100 numerator) 
8000 × 80/100 × 80/100 = 5120

7.

What percent is 36paisa's of 12 rupees? 

   A.) 3%
   B.) 0.03%
   C.) 0.03%
   D.) None of these

Answer: Option 'A'

12 Rupees = 1200paisa's 
36/1200 × 100 = 3/12 
12/3 = 3 %

9.

The population of a town is 10000. It increases annually at the rate of 20% p.a. What will be its population after 2 years? 

   A.) 14440
   B.) 12400
   C.) 14400
   D.) 11400

Answer: Option 'C'

Formula : 
( After =100 denominator 
Ago = 100 numerator) 
10000 × 120/100 × 120/100 = 14400

10.

From the salary of Roja, 20% is deducted as house rent, 10% of rest she spends on children's education and 20% of balance she spends on watching movies. If her savings are Rs.5760/- then hers total salary is: 

   A.) Rs.11520/-
   B.) Rs.10000/-
   C.) Rs.12000/-
   D.) None of these

Answer: Option 'B'

FORMULA:
First value = last value×100/100-p1×100/100-p2×---------------- (p=percentage) 
First value = 5760×100/100 - 20×100/100 - 10×100/100 - 20 
= 5760 × 100/80× 100/90× 100/80 = 10000/-

11.

What percent is 70 of 280? 

   A.) 25%
   B.) 50%
   C.) 75%
   D.) None of these

Answer: Option 'A'

70/280 = 1/4 
1/4 × 100 = 25 %

12.

Daal is now being sold at Rs. 20 a kg. Last month, is rate was Rs. 16 per kg. By how much percent should a family reduce its consumption so as to keep the expenditure fixed?

   A.) 30%
   B.) 25%
   C.) 20%
   D.) 15%

Answer: Option 'C'

Let a family's monthly consumption of daal be x kg.
To keep the expenditure fixed,
their consumption for this month should be 16x/20 = 4x/5.
Reduction in consumption = x/5 = 20% of x

13.

If 20% of a certain number is 80, then what is 30% of that number? 

   A.) 100
   B.) 120
   C.) 140
   D.) 150

Answer: Option 'B'

20% = 20 × 4 = 80 
30% = 30 × 4= 120

14.

A mixture of 20 litres of milk and water contains 20% of water. The new mixture is formed by adding 5 lit of water. What is the percentage of milk in the new mixture? 

   A.) 36%
   B.) 20%
   C.) 64%
   D.) 46%

Answer: Option 'C'

(20 li = 4 li water 16 li milk 
-------- 5 li water 
Total = 9 li water 16 li milk (new) 
16/25×100=64%

15.

The Shopkeeper increased the price of a product by 25% so that customer finds it difficult to purchase the required amount. But somehow the customer managed to purchase only 70% of the required amount. What is the net difference in the expenditure on that product? 

   A.) 10% more
   B.) 5% more
   C.) 12.5% more
   D.) 17.5% more

Answer: Option 'C'

Quantity X Rate = Price
1 x 1 = 1
0.7 x 1.25 = 0.875
Decrease in price = (0.125/1) × 100 = 12.5%

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