1.

In an election between the two candidates ,The candidates who gets 60% of votes polled is winned by 280 votes majority. What is the total number of votes polled?

**Answer: Option 'B'**

**Note : majority (20 %) = difference in votes polled to win (60 %) & defeated candidates (40 %)
20 % = 60 % - 40 %
20% -----> 280 (20×14 = 280 )
100% -----> 1400 (100×14 = 1400)**

2.

In a competitive examination in State A, 6% candidates got selected from the total appeared candidates. State B had an equal number of candidates appeared and 7% candidates got selected with 80 more candidates got selected than A. What was the number of candidates appeared from each State?

**Answer: Option 'A'**

**State A and State B had an equal number of candidates appeared.
In state A, 6% candidates got selected from the total appeared candidates
In state B, 7% candidates got selected from the total appeared candidates
But in State B, 80 more candidates got selected than State A
From these, it is clear that 1% of the total appeared candidates in State B = 80
=> total appeared candidates in State B = 80 x 100 = 8000
=> total appeared candidates in State A = total appeared candidates in State B = 8000**

3.

Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. The marks obtained by them are:

**Answer: Option 'C'**

**Let their marks be (x + 9) and x.
Then, x + 9 = (56/100)(x+9+x)
25(x+9) = 14(2x + 9)
3x = 99
x = 33
So, their marks are **

4.

In an election, the winning candidate got 58% of the valid votes. If he got 1600 votes more than the other candidate and 100 votes were invalid, find the number of votes cast.

**Answer: Option 'D'**

**Let the number of valid votes be x
Winning candidate - 58% of x
Other candidate - 42% of x
Difference - 16% of x
16% of x = 1600
x = 10000
Total votes = 10000 + 100 = 10100**

5.

If 40% of a certain number is 120, then what is 90% of that number?

**Answer: Option 'D'**

**40% = 40 × 3 = 120
90% = 90 × 3 = 270**

6.

In an election between two candidates first candidate got 60% of votes polled and second Candidate got 280 votes. The total number of votes polled was?

**Answer: Option 'A'**

**Total = 100 %,
First person got 60%
second person got remaining 40 % of votes.
than 40 % = 280
40% = 40×7 = 280
100% =100×7 =700votes**

7.

In a class 60% of students passed in telugu, 50% 0f students passde in english. Then if every student Passed in either telugu or english or both the subjects. Then what is the percentage of students passed In both the subjects?

**Answer: Option 'A'**

**passed in Telugu = 60 %
passed in English = 50 %
only passed in telugu = 50%
only passed in english = 40%
the percentage of studebts passed in both the subjects = 10 %**

8.

After selling 35% of the apples, a fruit vendor has 260 apples left. How many did he have originally?

**Answer: Option 'C'**

**After selling 35% of the apples, he has 65% left.
(65/100) × x = 260x = 400**

9.

11 1/9 % of 900?

**Answer: Option 'A'**

**11 1/9 % = 1/9
1/9 × 900 = 100**

10.

Number decreased by 20% gives 480. The number is:

**Answer: Option 'B'**

**Formula = TOTAL=100% ,INCRESE = "+" DECREASE= "-"
A number means = 100 %
That same number Decreased by 20 % = 80 %
80 % ------> 480 (80 × 6 = 480)
100 % ------> 600 (100 × 6 = 600)**

11.

Daal is now being sold at Rs. 20 a kg. Last month, is rate was Rs. 16 per kg. By how much percent should a family reduce its consumption so as to keep the expenditure fixed?

**Answer: Option 'C'**

**Let a family's monthly consumption of daal be x kg.
To keep the expenditure fixed,
their consumption for this month should be 16x/20 = 4x/5.
Reduction in consumption = x/5 = 20% of x**

12.

The population of a town was 1,00,000 three years ago. If increased by 2%, 3% and 5% respectively in the last three years, then the present population of town is

**Answer: Option 'C'**

**The present population = (102/100) × (103/100) × (105/100) × 100000 = 1,10,313**

13.

If 20% of a certain number is 80, then what is 30% of that number?

**Answer: Option 'B'**

**20% = 20 × 4 = 80
30% = 30 × 4= 120**

14.

When a number is first increased by 10% and then reduced by 10%, The number is:

**Answer: Option 'B'**

**Farmula = AFTER INCREASED 10% × AFTER REDUCED 10%/TOTAL 100%
= 110 × 90/100 = 99 %
= Decreases by 1%**

15.

Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. What are the marks obtained by them?

**Answer: Option 'A'**

**Let the marks secured by them be x and (x + 9)
Then sum of their marks = x + (x + 9) = 2x + 9
Given that (x + 9) was 56% of the sum of their marks
=>(x+9) = 56/100(2x+9)
=>(x+9) = 14/25(2x+9)
=> 25x + 225 = 28x + 126
=> 3x = 99
=> x = 33
Then (x + 9) = 33 + 9 = 42
Hence their marks are 33 and 42**

16.

The population of a town is 8000. It decreases annually at the rate of 20% p.a. What will be its population after 2 years?

**Answer: Option 'B'**

**Formula :
( After =100 denominator
Ago = 100 numerator)
8000 × 80/100 × 80/100 = 5120**

17.

What percent is 36paisa's of 12 rupees?

**Answer: Option 'A'**

**12 Rupees = 1200paisa's
36/1200 × 100 = 3/12
12/3 = 3 %**

18.

In an examination it is required to get 40% of minimum marks to pass. A student got 142 marks, Thus he got 22 marks more than minimum marks required to pass. What is total marks?

**Answer: Option 'C'**

**40 % ------> 120 ( 40 × 3 = 120 )
100 % ------> 300 ( 100 × 3 = 300 )**

19.

If the length and breadth of a cuboid are halved and the height is doubled, find the % change in volume.

**Answer: Option 'C'**

**New volume = (1/2) × (b/2) × 2h = (lbh/2)
So, there is 50% decrease.**

20.

In an elaction between two candidates, 20% of votes are were declares invalid. First candidate got 480 votes which were 60% of the total valid votes . The total number of votes enrolled in that election was:

**Answer: Option 'B'**

**(100%-20%=80%
48%-32%=16%
16% = 16×30 = 480
100% =100×30 =3000 votes)**

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