1.
Two employees X and Y are paid a total of Rs. 550 per week by their employer. If X is paid 120 percent of the sum paid to Y, how much is Y paid per week?
Answer: Option 'C'
Let the amount paid to X per week = x
and the amount paid to Y per week = y
Then x + y = 550
But x = 120% of y = 120y/100 = 12y/10
∴12y/10 + y = 550
⇒ y[12/10 + 1] = 550
⇒ 22y/10 = 550
⇒ 22y = 5500
⇒ y = 5500/22 = 500/2 = Rs.250
2.
The population of a town is 8100. It decreases annually at the rate of 10% p.a. What was its population 2 years ago?
Answer: Option 'C'
Formula :
( After =100 denominator
Ago = 100 numerator)
8100 × 100/90 × 100/90 = 10000
3.
A mixture of 30 litres of milk and water contains 30% of water. The new mixture is formed by adding 10 lit of water. What is the percentage of water in the new mixture?
Answer: Option 'D'
(30 li = 9 li water 21 li milk
------= 10 li water
Total = 19li water 21 li milk (new)
19/40 × 100 = 47 1/2%
4.
In a class 60% of students passed in telugu, 50% 0f students passde in english and 20% of students passed in both the subjects then what is the percentage the students who failed in the both the subjects?
Answer: Option 'B'
only t = 40,only e = 30 and both subjects passed 20%
10% failed in both subjects
5.
The Shopkeeper increased the price of a product by 25% so that customer finds it difficult to purchase the required amount. But somehow the customer managed to purchase only 70% of the required amount. What is the net difference in the expenditure on that product?
Answer: Option 'C'
Quantity X Rate = Price
1 x 1 = 1
0.7 x 1.25 = 0.875
Decrease in price = (0.125/1) × 100 = 12.5%