RRB NTPC - Percentage : Aptitude Test

1.

In an election between the two candidates ,The candidates who gets 60% of votes polled is winned by 280 votes majority. What is the total number of votes polled?

   A.) 1500
   B.) 1400
   C.) 1600
   D.) None of these

Answer: Option 'B'

Note : majority (20 %) = difference in votes polled to win (60 %) & defeated candidates (40 %) 
20 % = 60 % - 40 % 
20% -----> 280 (20×14 = 280 )
100% -----> 1400 (100×14 = 1400)

2.

In a competitive examination in State A, 6% candidates got selected from the total appeared candidates. State B had an equal number of candidates appeared and 7% candidates got selected with 80 more candidates got selected than A. What was the number of candidates appeared from each State? 

   A.) 8000
   B.) 8200
   C.) 8020
   D.) 7800

Answer: Option 'A'

State A and State B had an equal number of candidates appeared.
In state A, 6% candidates got selected from the total appeared candidates
In state B, 7% candidates got selected from the total appeared candidates
But in State B, 80 more candidates got selected than State A
From these, it is clear that 1% of the total appeared candidates in State B = 80
=> total appeared candidates in State B = 80 x 100 = 8000
=> total appeared candidates in State A = total appeared candidates in State B = 8000

3.

Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. The marks obtained by them are:

   A.) 39, 33
   B.) 41, 33
   C.) 42, 33
   D.) 43, 33

Answer: Option 'C'

Let their marks be (x + 9) and x.
Then, x + 9 = (56/100)(x+9+x)
25(x+9) = 14(2x + 9)
3x = 99
x = 33
So, their marks are 42 and 33.

4.

In an election, the winning candidate got 58% of the valid votes. If he got 1600 votes more than the other candidate and 100 votes were invalid, find the number of votes cast.

   A.) 13500
   B.) 15150
   C.) 10109
   D.) 10100

Answer: Option 'D'

Let the number of valid votes be x
Winning candidate - 58% of x
Other candidate - 42% of x 
Difference - 16% of x
16% of x = 1600
x = 10000
Total votes = 10000  + 100 = 10100

5.

If 40% of a certain number is 120, then what is 90% of that number? 

   A.) 150
   B.) 200
   C.) 240
   D.) 270

Answer: Option 'D'

40% = 40 × 3 = 120 
90% = 90 × 3 = 270

6.

In an election between two candidates first candidate got 60% of votes polled and second Candidate got 280 votes. The total number of votes polled was? 

   A.) 700 votes
   B.) 750 votes
   C.) 600 votes
   D.) 650 votes

Answer: Option 'A'

Total = 100 %,
First person got 60% 
second person got remaining 40 % of votes.
than 40 % = 280 
40% = 40×7 = 280 
100% =100×7 =700votes

7.

In a class 60% of students passed in telugu, 50% 0f students passde in english. Then if every student Passed in either telugu or english or both the subjects. Then what is the percentage of students passed In both the subjects? 

   A.) 10%
   B.) 20%
   C.) 15%
   D.) 12%

Answer: Option 'A'

passed in Telugu = 60 % 
passed in English = 50 % 
only passed in telugu = 50% 
only passed in english = 40% 
the percentage of studebts passed in both the subjects = 10 %

8.

After selling 35% of the apples, a fruit vendor has 260 apples left. How many did he have originally?

   A.) 300
   B.) 250
   C.) 400
   D.) 350

Answer: Option 'C'

After selling 35% of the apples, he has 65% left.
(65/100) × x = 260x = 400

9.

11 1/9 % of 900? 

   A.) 100
   B.) 20
   C.) 81
   D.) None of these

Answer: Option 'A'

11 1/9 % = 1/9 
1/9 × 900 = 100

10.

Number decreased by 20% gives 480. The number is: 

   A.) 500
   B.) 600
   C.) 550
   D.) None of these

Answer: Option 'B'

Formula = TOTAL=100% ,INCRESE = "+" DECREASE= "-" 
A number means = 100 % 
That same number Decreased by 20 % = 80 % 
80 % ------> 480 (80 × 6 = 480) 
100 % ------> 600 (100 × 6 = 600)

11.

Daal is now being sold at Rs. 20 a kg. Last month, is rate was Rs. 16 per kg. By how much percent should a family reduce its consumption so as to keep the expenditure fixed?

   A.) 30%
   B.) 25%
   C.) 20%
   D.) 15%

Answer: Option 'C'

Let a family's monthly consumption of daal be x kg.
To keep the expenditure fixed,
their consumption for this month should be 16x/20 = 4x/5.
Reduction in consumption = x/5 = 20% of x

12.

The population of a town was 1,00,000 three years ago. If increased by 2%, 3% and 5% respectively in the last three years, then the present population of town is

   A.) 1,11,111
   B.) 1,10,101
   C.) 1,10,313
   D.) 1,11,125

Answer: Option 'C'

The present population = (102/100) × (103/100) × (105/100) × 100000 = 1,10,313

13.

If 20% of a certain number is 80, then what is 30% of that number? 

   A.) 100
   B.) 120
   C.) 140
   D.) 150

Answer: Option 'B'

20% = 20 × 4 = 80 
30% = 30 × 4= 120

14.

When a number is first increased by 10% and then reduced by 10%, The number is: 

   A.) Does not change
   B.) Decreases by 1%
   C.) Increases by 1%
   D.) None of these

Answer: Option 'B'

Farmula = AFTER INCREASED 10% × AFTER REDUCED 10%/TOTAL 100% 
= 110 × 90/100 = 99 % 
= Decreases by 1%

15.

Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. What are the marks obtained by them? 

   A.) 42, 33
   B.) 44, 36
   C.) 43, 36
   D.) 42, 36

Answer: Option 'A'

Let the marks secured by them be x and (x + 9)
Then sum of their marks = x + (x + 9) = 2x + 9
Given that (x + 9) was 56% of the sum of their marks
=>(x+9) = 56/100(2x+9)
=>(x+9) = 14/25(2x+9)
=> 25x + 225 = 28x + 126
=> 3x = 99
=> x = 33
Then (x + 9) = 33 + 9 = 42
Hence their marks are 33 and 42

16.

The population of a town is 8000. It decreases annually at the rate of 20% p.a. What will be its population after 2 years? 

   A.) 700 votes
   B.) 750 votes
   C.) 600 votes
   D.) 650 votes

Answer: Option 'B'

Formula : 
( After =100 denominator 
Ago = 100 numerator) 
8000 × 80/100 × 80/100 = 5120

17.

What percent is 36paisa's of 12 rupees? 

   A.) 3%
   B.) 0.03%
   C.) 0.03%
   D.) None of these

Answer: Option 'A'

12 Rupees = 1200paisa's 
36/1200 × 100 = 3/12 
12/3 = 3 %

18.

In an examination it is required to get 40% of minimum marks to pass. A student got 142 marks, Thus he got 22 marks more than minimum marks required to pass. What is total marks? 

   A.) 350
   B.) 400
   C.) 300
   D.) None of these

Answer: Option 'C'

40 % ------> 120 ( 40 × 3 = 120 ) 
100 % ------> 300 ( 100 × 3 = 300 )

19.

If the length and breadth of a cuboid are halved and the height is doubled, find the % change in volume.

   A.) 40% increase
   B.) 45% increase
   C.) 50% decrease
   D.) 25% decrease

Answer: Option 'C'

New volume = (1/2) × (b/2) × 2h = (lbh/2)
So, there is 50% decrease.

20.

In an elaction between two candidates, 20% of votes are were declares invalid. First candidate got 480 votes which were 60% of the total valid votes . The total number of votes enrolled in that election was: 

   A.) 450 votes
   B.) 3000 votes
   C.) 3200 votes
   D.) None of these

Answer: Option 'B'

(100%-20%=80% 
48%-32%=16% 
16% = 16×30 = 480 
100% =100×30 =3000 votes)


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