Problems on Trains


  • 1. A 400m long train is running at 72 Kmph. how much time it will take to cross an electric pole? 
A.) 15sec
B.) 20sec
C.) 19sec
D.) 21sec

Answer: Option 'B'

Formula: Distance = Speed × Time
If we convert Kmph in to Mpsec multiply by 5/18,
400 = 72 KmpH × time
400 = 72×5/18 × time
Time = 20Sec

  • 2. A 180m long train is running at 54 Kmph. how much time it will take to cross a platform of 120m long? 
A.) 20sec
B.) 22sec
C.) 19sec
D.) 18sec

Answer: Option 'A'

Formula: D = S × T 
180 = 54 Kmph × Time 
180= 54×5/18 × Time 
Time = 20 Sec 

  • 3. 320m long train is running at 72 Kmph. how much time it will take to cross a platform of 180m long? 
A.) 20sec
B.) 25sec
C.) 30sec
D.) 27sec

Answer: Option 'B'

Total Length = platform Length+ Train Length 
Total Length= 500m 
D = S × T 
500 = 72 × time 
500 = 72 × 5/18 × time 
Time = 25Sec 

  • 4. A 600m long train is running at 90 Kmph. how much time it will take to cross an electric pole? 
A.) 16sec
B.) 20sec
C.) 24sec
D.) 22sec

Answer: Option 'C'

Formula: D = S × T 
600 = 90 Kmph × T 
600 = 90 × 5/18 × T 
Time = 24Sec

  • 5. Two trains 300m and 400m long run at the speeds of 40 kmph and 50kmph respectively in opposite Directions on parallel tracks. The time taken to cross each other? 
A.) 20sec
B.) 25secs
C.) 26sec
D.) 28sec

Answer: Option 'D'

Length of two Trains = 300m + 400m = 700m 
Total Speed= 40 Kmph + 50 Kmph (Opposite Direction)
= 90 Kmph 
Time = Distance/Speed 
Time = 700/ 90 
Time = 28Sec

  • 6. A train overtakes two persons who are walking in the same direction in which the train is going, at the rate of 2 kmph and 4 kmph and passes them completely in 9 and 10 seconds respectively. The length of the train is: 
A.) 45 m
B.) 55 m
C.) 50 m
D.) 65 m

Answer: Option 'C'

2 kmph = (2 x 5/18) m/sec = 5/9 m/sec.
4 kmph = (4 x 5/18 m/sec = 10/9 m/sec.
Let the length of the train be x metres and its speed by y m/sec.
Then, ( x/(y - 5) = 9 and ( x/(y - 10) = 10.
Therefore 9y - 5 = x and 10(9y - 10) = 9x
=> 9y - x = 5 and 90y - 9x = 100.
On solving, we get: x = 50.

  • 7. Two stations A and B are 110 km apart on a straight line. One train starts from A at 7 a.m. and travels towards B at 20 kmph. Another train starts from B at 8 a.m. and travels towards A at a speed of 25 kmph. At what time will they meet? 
A.) 10 a.m.
B.) 11 a.m.
C.) 8 a.m.
D.) 9 a.m.

Answer: Option 'A'

Suppose they meet x hours after 7 a.m.
Distance covered by A in x hours = 20x km.
Distance covered by B in (x - 1) hours = 25(x - 1) km.
Therefore 20x + 25(x - 1) = 110
=> 45x = 135
=> x = 3.
So, they meet at 10 a.m.

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