- 11. A train crosses a tree in 120sec, while it crosses a 700m long platform in 190sec. the length of the

Train is:

A.) 1500m B.) 1400m C.) 1300m D.) 1200m Answer: Option 'D'

In 190Sec Cross a 700m Platform I.e.,

Length of Train + Length of Platform.

190 Sec- 120Sec = 700m

70Sec= 700m

Speed= 10 M/Sec

In 120 Sec The length wil be 1200m.

- 12. A 1200m long train crosses a tree in 120sec, how much time will I take to pass a platform 700m long?

A.) 180sec B.) 190sec C.) 170sec D.) 175sec Answer: Option 'B'

L = S*T

S= 1200/120

S= 10M/Sec.

Total length(D)= 1900m

T = D/S

T = 1900/10

T = 190Sec

- 13. A train is running at 72 Kmph. It was crossed an electronic pole in 20sec. find the length of the train?

A.) 300m B.) 400m C.) 250m D.) 405m Answer: Option 'B'

L = S * T

L = 72 Kmph * 20Sec

L = 72* 5/18 * 20

L = 400m

- 14. A train is running at 108 Kmph. It was crossed an electronic pole in 28sec. find the length of the train?

A.) 480m B.) 840m C.) 640m D.) 740m Answer: Option 'B'

L = S * T

L = 108 Kmph * 28Sec

L =108 * 5/18 * 28

L= 840m - 15. A 180m long train is running at 72 Kmph. If it crossed the platform in 20sec. then find the platform

Length? - 16. A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?
- 17. A train passes a station platform in 36 seconds and a man standing on the platform in 20 seconds. If the

speed of the train is 54 km/hr, what is the length of the platform?

A.) 150 m B.) 160 m C.) 240 m D.) 250 m Answer: Option 'B'

Speed = 54 x 5/18 m/sec = 15 m/sec.

Length of the train = (15 x 20)m = 300 m.

Let the length of the platform be x metres.

Then, (x + 300)/36 = 15

x + 300 = 540

x = 240 m. - 18. The length of the bridge, which a train 130 metres long and travelling at 45 km/hr can cross in 30 seconds,

is:

A.) 150 m B.) 160 m C.) 240 m D.) 245 m Answer: Option 'D'

Speed = 45 x 5/18 m/sec = 25/2 m/sec.

Time = 30 sec.

Let the length of bridge be x metres.

Then, (130 + x)/30 = 25/2

2(130 + x) = 750

x = 245 m. - 19. A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10

seconds. The speed of the train is:

A.) 150 km/hr B.) 50 km/hr C.) 75 km/hr D.) 55 km/hr Answer: Option 'B'

Speed of the train relative to man = 125/10 m/sec

= 25/2 m/sec.

= 25/2 x 18/5 km/hr

= 45 km/hr.

Let the speed of the train be x km/hr. Then, relative speed = (x - 5) km/hr.

x - 5 = 45

x = 50 km/hr. - 20. Two trains running in opposite directions cross a man standing on the platform in 27 seconds and

17 seconds respectively and they cross each other in 23 seconds. The ratio of their speeds is:

A.) 3 : 2 B.) 1 : 3 C.) 3 : 7 D.) 3 : 4 Answer: Option 'A'

Let the speeds of the two trains be x m/sec and y m/sec respectively.

Then, length of the first train = 27x metres,

and length of the second train = 17y metres.

(27x + 17y)/(x + y) = 23

27x + 17y = 23x + 23y

4x = 6y

x/y = 3/2 .

A.) 210m | B.) 220m |

C.) 240m | D.) 250m |

Answer: Option 'B'

Length = Speed*Time

L = 72K.M/H*T

L=72*5/18*20

L= 400M.

Length of Platform= Length-Length of the Train

Length of Platform= 400-180

Length of Platform=220m

Length = Speed*Time

L = 72K.M/H*T

L=72*5/18*20

L= 400M.

Length of Platform= Length-Length of the Train

Length of Platform= 400-180

Length of Platform=220m

A.) 150 m | B.) 160 m |

C.) 240 m | D.) 250 m |

Answer: Option 'A'

Speed = 60 x 5/18 m/sec = 50/3 m/sec.

Length of the train = (Speed x Time) = 50/3 x 9 m = 150 m.

Speed = 60 x 5/18 m/sec = 50/3 m/sec.

Length of the train = (Speed x Time) = 50/3 x 9 m = 150 m.

Students can learn and improve on their Cognitive and Mathematical Fast Calculation skills and prepare for competitive examinations like...

- All I.B.P.S and Public Sector Bank Competitive Exam
- Common Aptitude Test (CAT) Exams
- UPSC Paper-II or CSAT Exams
- SSC Competitive Exams
- Defence Competitive Exams
- L.I.C / G.I.C AO and Clerk Competitive Exams
- Railway Competitive Exam
- University Grants Commission (UGC)
- Career Aptitude Test (IT Companies) and etc.

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