RRB NTPC - Ratios and Proportions (114 Questions with Explanation)

  • 1. Find the fourth proportional to 2.4, 4.6 and 7.6? 
   A.) 14
   B.) 14.657
   C.) 15.56
   D.) 14.56

Answer: Option 'D'

Formula = Fourth propotional = (b × c)/a 
A = 2.4 , B = 4.6 and C = 7.6 
(4.6 × 7.6)/2.4 = 14.56

  • 2. Find the third proportional to 9 and 12? 
   A.) 9
   B.) 108
   C.) 16
   D.) 9

Answer: Option 'C'

Formula = Third proportional = (b × b)/a 
A = 9 and B = 12 
(12 × 12)/ 9 = 144/9 = 16

  • 3. Find the mean proportional between 49 & 81? 
   A.) 16
   B.) 10
   C.) 63
   D.) 12

Answer: Option 'C'

Formula = √a×b
A = 49 and B = 81 
√49×81 = 7 × 9 = 63

  • 4. Find the fourth proportional to 0.2,0.12 and 0.3? 
   A.) 0.13
   B.) 0.18
   C.) 0.8
   D.) 0.15

Answer: Option 'B'

Formula = Fourth propotional = (b × c)/a 
A = 0.2 , B = 0.12 and C = 0.3 
(0.12 × 0.3)/0.2 
0.036/0.2 = 0.18

  • 5. If a:b=1:2 and b:c=3:4 find a:b:c? 
   A.) 3:8:6
   B.) 3:12:6
   C.) 3:6:8
   D.) 1:2:4

Answer: Option 'C'

a:b = 1:2, b:c = 3:4 
1:2 
3:4 
(a = 1 × 3 = 3, b = 2 × 3 = 6 and c = 2 × 4 = 8)
(a = a × b, b = b × b and c = b × c) 
a:b:c = 3:6:8 

  • 6. If a:b=1:2, b:c=3:4 and c:d = 2:3 find a:b:c:d? 
   A.) 3:6:8:24
   B.) 6:12:16:24
   C.) 6:18:24:16
   D.) 3:6:2:3

Answer: Option 'B'

a:b = 1:2, b:c = 3:4, c:d = 2:3
1:2 
3:4 
( a = 1 × 3 = 3, b = 2 × 3 = 6 and c = 2 × 4 = 8)
(a = a × b, b= b × b and c= b × c) 
a:b:c = 3:6:8 
a:b:c = 3:6:8 and c:d = 2:3
(Note: First a,b,c multiplication with c means 2 and last c means 8
multiplication with d means 3
a:b:c:d = 6:12:16:24 

  • 7. If a:b=2:3, b:c=4:5 and c:d=4:2 find a:b:c:d? 
   A.) 32:48:8:24
   B.) 8:12:60:24
   C.) 32:18:24:30
   D.) 32:48:60:30

Answer: Option 'D'

a:b = 2:3, b:c = 4:5, c:d = 4:2
2:3 
4:5 
( a = 2× 4 = 8, b = 37 × 4 = 12 and c = 3 × 5 = 15)
(a = a × b, b = b × b and c = b × c)
a:b:c = 8:12:15 
a:b:c = 8:12:15 and c:d = 4:2
(Note: First a=8,b=12,c=15 multiplication with c means 4 and last c = 15
multiplication with d means 2
a:b:c:d = 32:48:60:30 

  • 8. If  2a=6b and 9b=7c, Find a:b:c? 
   A.) 42:18:14
   B.) 3:9:7
   C.) 9:27:22
   D.) 21:7:9

Answer: Option 'D'

(2a = 6b => a/b = 6/2)
and (9b = 7c => b/c = 7/9) 
=> a:b = 6:2 and b:c = 7:9 
a:b:c = 42:14:18 = 21:7:9

  • 9. If 0.4:1.4 :: 1:4:x, then x=?
   A.) 49
   B.) 4.9
   C.) 0.49
   D.) 0.4

Answer: Option 'B'

0.4 × x = 1.4 × 1.4 
x = 1.4 × 1.4/0.4 = 14/10 × 14/10 × 1/(4/10) 
14/10 × 14/10 × 10/4 
7/10 × 7 = 49/10 = 4.9

  • 10. If x:y=5:3 then (8x-5y) : (8x+5y)=? 
   A.) 5:13
   B.) 13:5
   C.) 5:11
   D.) 11:5

Answer: Option 'C'

x/y = 5/3 (Given) 
(8x − 5y)/(8x + 5y) 
8(x/y) − 5/8(x/y)+5 
( on dividing Nr and Dr by y) 
(8(5/3) − 5)/(8(5/3) + 5) 
(40/3 − 5/1)/(40/3 + 5/1) 
[(40 − 15)/3]/[(40 + 15)/3] 
25/55 = 5/11 
(8x-5y):(8x+5y) = 5:11 

  • 11. A fraction bears the same ratio to 1/27 as 3/7 does to 5/9. The fraction is? 
   A.) 7/45
   B.) 1/35
   C.) 45/7
   D.) 5/21

Answer: Option 'B'

Let the fraction be x. Then, 
x:1/27 = 3/7 : 5/9 
x × 5/9 = 1/27 × 3/7 
x × 5/9 = 1/9 × 1/7 
x × 5/9 = 1/63 
x × 5 = 9/63 
5x = 1/7 = 1/35

  • 12. The ratio of two numbers is 3:4 and their sum is 28. The greater of the two numbers is? 
   A.) 8
   B.) 12
   C.) 14
   D.) 16

Answer: Option 'D'

3:4 
Total parts = 7 
= 7 parts --> 28 (7 × 4 = 28)
= 1 part ----> 4 (1 × 4 = 4) 
= The greater of the two number is = 4 
= 4 parts ----> 16 (4 × 4 = 16)

  • 13. The ratio of three numbers is 5:3:4 and their sum is 108. The second number of the three numbers is? 
   A.) 12
   B.) 27
   C.) 15
   D.) 29

Answer: Option 'B'

5:3:4 
Total parts = 12 
12 parts --> 108 
1 part ---->9 
The second number of the three numbers is = 3 
3 parts ----> 27 

  • 14. Three numbers are in the ratio 3:5:7. The largest number value is 42. Find difference between Smallest & largest number is? 
   A.) 16
   B.) 8
   C.) 12
   D.) 24

Answer: Option 'D'

= 3:5:7 
Total parts = 15 
= The largest number value is 42 
= The largest number is = 7 
= Then 7 parts -----> 42 ( 7 × 6 = 42 )
= smallest number = 3 & Largest number = 7
= Difference between smallest number & largest number is = 7 - 3 = 4 
= Then 4 parts -----> 24 (4 × 6 = 24) 

  • 15. If two numbers are in the ratio 2:3. If 10 is added to both of the numbers then the ratio becomes 3:4 then find the smallest number?
   A.) 10
   B.) 20
   C.) 30
   D.) 40

Answer: Option 'B'

2:3 
2x + 10 : 3x + 10 = 3 : 4 
4[2x + 10] = 3[3x + 10] 
8x + 40 = 9x + 30 
9x - 8x = 40 - 30 
x = 10 
Then smallest number is = 2 
2x = 20 
Short cut method: 
a:b = 2:3 
c:d = 3:4 
1.Cross multiplication with both ratios a × d ~ b × c = 2 * 4 ~ 3 × 3 = 8 ~ 9 = 1 
2. If 10 is added both the number means 10 × 3 = 30 and 10 × 4 = 40, 
Then 30 ~ 40 = 10 
=> 1 ---> 10 
=> 2 ---> 20 

  • 16. If two numbers are in the ratio 2:3. If 10 is added to both of the numbers then the ratio becomes 5:7 then find the largest number? 
   A.) 30
   B.) 10
   C.) 60
   D.) 40

Answer: Option 'D'

2:3 
2x + 10 : 3x + 10 = 5 : 7 
7[2x + 10] = 5[3x + 10] 
14x + 70 = 15x + 50 
15x - 14x = 70 - 50 
x = 20 
Then the first number is = 2 
2x = 40 
Short cut method: 
a:b = 2:3 
c:d = 5:7 
1.Cross multiplication with both ratios a × d ~ b × c = 2 × 7 ~ 3 × 5 = 14 ~ 15 = 1 
2. If 10 is added both the number means 10 × 5 = 50 and 10 × 7 = 70,
Then 50 ~ 70 = 20 
==> 1 ---> 20 
==> 2 ---> 40 (Answer is = 40)

  • 17. If two numbers are in the ratio 5:3. If 10 is Reduced to both of the numbers then the ratio becomes 2:1 then find the smallest number?
   A.) 10
   B.) 20
   C.) 30
   D.) 40

Answer: Option 'C'

5:3 
5x - 10 : 3x - 10 = 2 : 1 
1[5x - 10] = 2[3x - 10] 
5x - 10 = 6x - 20 
6x - 5x = 20 - 10 
x = 10 
the small number is = 3 
3x = 30 (Answer = 30)
Short cut method: 
a:b = 5:3 
c:d = 2:1 
1.Cross multiplication with both ratios a × d ~ b × c = 5 × 1 ~ 3 × 2 = 5 ~ 6 = 1 
2. If 10 is reduced both the number means 10 × 2 = 20 and 10 × 1 = 10, 
Then 20 ~ 10 = 10 
=> 1 ---> 10 
=> 3 ---> 30 (Answer is = 30)

  • 18. A mixture contains milk and water in the ratio 5:2. On adding 10 liters of water, the ratio of milk to water becomes 5:3. The quantity of milk in the original mixture is?
   A.) 70
   B.) 50
   C.) 30
   D.) 40

Answer: Option 'A'

milk:water = 5:2 
5x : 2x + 10 = 5 : 3 
3[5x] = 5[2x + 10] 
15x = 10x + 50 
15x - 10x = 50 
x = 10 
The quantity of milk in the original mixture is = 5 : 2 = 5 + 2 = 7 
7x = 70 
Short cut method: 
milk:water = 5 :2  
after adding 10 liters of water 
milk:water = 5 :3  
milk is same but water increse 10liters then the water ratio is increse 1 parts  
1 part ---> 10 liters  
The quantity of milk in the original mixture is = 5 : 2 = 5 + 2 = 7 
7 parts ---> 70 liters  (Answer is = 70) 
Short cut method - 2 : for Only milk problems 
milk : water 
5 : 2 
5 : 3 
milk ratio same but water ratio 1 part incress per 10 liters 
1 part of ratio ---> 10 liters 
7 part of ratio ---> 70 liters

  • 19. A mixture contains milk and water in the ratio 7:3. On adding 20 liters of water, the ratio of milk to water becomes 7:5. Total quantity of milk & water before adding water to it? 
   A.) 10
   B.) 100
   C.) 70
   D.) 30

Answer: Option 'B'

milk:water = 7:3 
7x : 3x + 20 = 7 : 5 
5[7x] = 7[3x + 20] 
35x = 21x + 140 
35x - 21x = 140 
14x = 140 
x = 10 
The quantity of milk in the original mixture is = 7 : 3 = 7 + 3 = 10 
10x = 100 
Short cut method: 
milk:water = 7 : 3  
after adding 20 liters of water 
milk:water = 7 : 5  
milk is same but water increse 20liters then the water ratio is increse 2 parts  
1 part ---> 10 liters  
The quantity of milk in the original mixture is = 7 : 3 = 7 + 3 = 10 
10 parts ---> 100 liters  (Answer is = 100) 
Short cut method - 2 : for Only milk problems 
milk : water 
7 : 3 
7 : 5 
milk ratio same but water ratio 2 parts incress per 20 liters 
2 part of ratio ---> 20 liters 
1 part of ratio ---> 10 liters 
10 part of ratio ---> 100 liters 

  • 20. A mixture contains milk and water in the ratio 3:2. On adding 10 liters of water, the ratio of milk to water becomes 2:3. Total quantity of milk & water before adding water to it?
   A.) 10
   B.) 50
   C.) 20
   D.) 40

Answer: Option 'C'

milk:water = 3:2 
after adding 10 liters of water
milk:water = 2:3 
Olny water patrs increase when mixture of water
milk:wate = 3:2 = 2*(3:2) = 6:4 
after adding 10 liters of water 
milk:water = 2:3 = 3*(2:3) = 6:9 
milk parts always same 
Short cut method: 
milk:water = 6 : 4  
after adding 10 liters of water 
milk:water = 6 : 9  
milk is same but water increse 10liters then the water ratio is increse 5 parts  
5 part ---> 10 liters  
The quantity of milk in the original mixture is = 6 : 4 = 6 + 4 = 10 
10 parts ---> 20 liters  (Answer is = 20) 
Short cut method - 2 : for Only milk problems 
milk : water 
6 : 4 
6 : 9 
milk ratio same but water ratio 5 parts incress per 10 liters 
5 part of ratio ----> 10 liters 
10 part of ratio ---> 20 liters 

  • 21. If Rs.900/- Rupees are divided among a,b and c in such a way that A’s share 3 times that of B and B’s share is 2 times that of C. The A’s share is? 
   A.) Rs.600/-
   B.) Rs.100/-
   C.) Rs.200/-
   D.) Rs.700/-

Answer: Option 'A'

A:B:C = 6:2:1 
Total parts = 9 
A's share is = 6 parts
9 -----> Rs.900/- 
6 -----> Rs.600/-

  • 22. If Rs.800/- Rupees are divided among a,b and c in such a way that A’s share 4 times more than B, B’s share is 3 times more than C. The C’s share is? 
   A.) Rs.650/-
   B.) Rs.600/-
   C.) Rs.150/-
   D.) Rs.50/-

Answer: Option 'D'

A:B:C = 12:3:1 
Total parts = 16 
C's share is = 1 parts 
16 -----> Rs.800/- 
1 -----> Rs.50/- (Answer = Rs.50/-)

  • 23. If Rs.540/- are divided among A,B and C in such a way that A’s share is ½nd of B share and B’s share is 1/3rd of C’s share. The share of A is? 
   A.) Rs.80/-
   B.) Rs.360/-
   C.) Rs.60/-
   D.) Rs.120/-

Answer: Option 'C'

A:B:C = 1:2:6 
Total parts = 9 
A's share is = 1 parts 
9 -----> Rs.540/- 
1 -----> Rs.60/- 

  • 24. If Rs.1440/- are divided among A,B and C so that A receives 1/3rd as much as B and B receives 1/4th as much as C. The amount B received is: 
   A.) Rs.90/-
   B.) Rs.270/-
   C.) Rs.1080/-
   D.) Rs.27/-

Answer: Option 'B'

A:B:C = 1:3:12 
Total parts = 16 
B's share is = 3 parts 
16 -----> 1440 
1 -----> 90 
3 -----> 270 (B's share is 270) 

  • 25. Rs.630/- distributed among A,B and C such that on decreasing their shares by RS.10,RS.5 and RS.15 respectively, The balance money would be divided among them in the ratio 3:4:5. Then, A’s share is:? 
   A.) Rs.150/-
   B.) Rs.200/-
   C.) Rs.160/-
   D.) Rs.255/-

Answer: Option 'C'

A:B:C = 3:4:5 
Total parts = 12 
A's share is = 3 parts 
12 -----> Rs.600/- 
3 -----> Rs.150/- 
A's total = 150 + 10 = Rs.160/-