Basic Computer Knowledge Test Questions and Answers

Simple Interest

1.

A man borrowed some amount, after 3 years he paid Rs.10,400/- with 10% interest, then how much Amount he borrowed? 

   A.) Rs.7000/-
   B.) Rs.8000/-
   C.) Rs.9000/-
   D.) Rs.1000/-

Answer: Option 'B'

principal P = ? 
Rate of interest R = 10% 
Time T = 3 years 
Accumulated Amount A = Rs.10400/- 
A = P + I 
A = P + PTR/100 
A = P(1+ TR/100) 
Rs.10400/- = P [1 + 3*10/100] 
Rs.10400/- = P [1/1 + 3/10] 
Rs.10400/- = P [10+3/10] = P[13/10] 
Rs.10400/- = P * 13/10 
==> P = Rs.104000/13 
==> P = Rs.8000/- 

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