1.

A person took some amount with some interest for 1 years, but increase the interest for 2%, he paid Rs.60/- extra, then how much amount he took?

**Answer: Option 'A'**

**Only 1 year = 60/1 = 60
Rate of Interest = 2%
100/2% × 60 = Rs.3000/-
P = Rs.3000/- **

2.

At what rate of percent per annum will a sum of money double in 8 years?

**Answer: Option 'B'**

**Let principal be Rs P. Then, S.I = Rs P and Time = 8 years>
Rate = (100 × S.I)/(P × T) = (100 × P/P × 8)% p.a
= 25/2 % p.a = 12.5% p.a **

3.

A borrow took by a man, for every 5 years it will be doubled, then what is the rate of the interest?

**Answer: Option 'B'**

**P = 1 , I = 1 , T = 5years R = ?
I = PTR/100
1 = 1×5×R/100
R = 20% **

4.

A borrow took by a man, for every 8 years it will be 3 times, then what is the rate of the interest?

**Answer: Option 'C'**

**P = 1 , I = 2 , T = 8years R = ?
I = PTR/100
2 = 1×8×R/100
R = 25% **

5.

Find the principle, interest on Rs.1200 at 8% p.a. for 2 years?

**Answer: Option 'B'**

**P = ?
T = 2 years
R = 8%
I = Rs.1200/-
I = PTR/100
P = 100I/TR
P = (100 × 1200)/(2 × 8)
P = Rs.7500/-**

6.

Find the simple interest on Rs.7300/- at 12% p.a. for the period from jan-2007 to 18- april-2007?

**Answer: Option 'A'**

**247.20**

7.

A man took some money for borrowed, for 2 years the total will be Rs.9000/- and 5 years it will be13, Rs.500/-. Then how much amount he borrowed?

**Answer: Option 'B'**

**2 years --------> Rs.9000/-
5 years --------> Rs.13500/-
~ ~
-----------------------------
3 years ----> Rs.4500/-
1 year -----> Rs.1500/-
2years × Rs.1500/- = Rs.3300/-
P = Rs.9000/- - Rs.30000/- = Rs.6000/-
P = Rs.6000/- **

8.

Find the simple interest 0n Rs.3000/- at 5 1/3% p.a. for 2 ½ years?

**Answer: Option 'C'**

**P = Rs.3000/-
T = 5/2 years
R = 16/3%
I = PTR/100
I = (3000 × 5/2 × 16/3)/100
I = 25 × 16 = Rs.400/-**

9.

Find simple interest on Rs.5000/- at 12% p.a, for 2 years?

**Answer: Option 'C'**

**P = Rs.5000/-
T = 2 years
R = 12%
I = PTR/100
I = Rs.5000 × 2 × 12/100 = Rs.1200/- **

10.

A man borrowed some amount, after 3 years he paid Rs.10,400/- with 10% interest, then how much Amount he borrowed?

**Answer: Option 'B'**

**principal P = ?
Rate of interest R = 10%
Time T = 3 years
Accumulated Amount A = Rs.10400/-
A = P + I
A = P + PTR/100
A = P(1+ TR/100)
Rs.10400/- = P [1 + 3*10/100]
Rs.10400/- = P [1/1 + 3/10]
Rs.10400/- = P [10+3/10] = P[13/10]
Rs.10400/- = P * 13/10
==> P = Rs.104000/13
==> P = Rs.8000/- **

11.

In how many years will sum of Rs.6000/- yield an interest of Rs.1200/- at 8% p.a?

**Answer: Option 'A'**

**P = Rs.6000/-
T = ?
R = 8%
I = Rs.1200/-
I = PTR/100
T = (I × 100)/PR
T = (1200 × 100)/(6000 × 8)
T = 5/2 ==> 2 1/2 years **

12.

A borrow taken by a man, for every 5 years it will be doubled, then how much time it will be taken

**Answer: Option 'B'**

**(R)1% ------> 5 years
3/1% × 5 = 15 years
Answer = 15 years **

13.

A man took some money for borrowed, for 3 years the total will be Rs.4000 and 5 years it will be Rs.5000/-. Then how much amount he borrowed?

**Answer: Option 'C'**

**3 years --------> Rs.4000/-
5 years --------> Rs.5000/-
~ ~
------------------------------
2 years ----> Rs.1000/-
1 year -----> Rs.500/-
3 years × Rs.500/- = Rs.1500/-
P = Rs.4000/- - Rs.1500/- = Rs.2500/-
P = Rs.2500/-**

14.

An employ sell a t.v for Rs.9000/- with 10% simple interest for 5 years on an installment basis. Then How much amount he paid for each installment?

**Answer: Option 'B'**

**Instalment = 100 × P/100 × T+T × (T - 1)R/2
= 100 × 9000/100 × 5+5 × (5-1)10/2
= 100 × 9000/6000 = Rs.1500/- **

15.

If the simple interest on Rs. 1120 for 2 years is Rs.8000/-, what is the rate of interest percent per annum?

**Answer: Option 'B'**

**I = Rs.1120/-
T = 2 years
P = Rs.8000/-
R = ?
S.I = (P×T×R/100)
R = (S.I×100)/(P×T)
R = (1120×100)/(8000×2)
R = 56/8 = 7% **

16.

Find simple interest on Rs.6000/- at 7 ½% p.a. for 3years?

**Answer: Option 'B'**

**P = Rs.6000/- **

**T = 3 years **

**R = 15/2% **

**I = PTR/100 **

**I = (6000 × 3 × 15/2)/100 **

**I = 90 × 15 = Rs.1350/-**

17.

A person took some amount with some interest for 2 years, but increase the interest for 1%, he paid Rs.120/- extra, then how much amount he took?

**Answer: Option 'B'**

**2 years = Rs.120/-
year = 120/2
Rate of Interest = 1%
100/1% × 120/2 = Rs.6000/-
P = Rs.6000/- **

18.

Find simple interest on Rs.4000/- at 15% p.a. for 9months?

**Answer: Option 'D'**

**T = 9 months = 9/12 = 3/4
P = Rs.4000/- , R = 15%
I =(4000 × 3/4 × 15) /100 = 30 v 15 = Rs.450/-
I = Rs.450/-**

19.

Find simple interest on Rs.6000/- at 10% p.a. for 2years 3 months?

**Answer: Option 'A'**

**2 years 3months = 27/12 = T
P = Rs.6000/-
R = 10%
I = (6000 × 27/12 × 10)/100 = 27 × 50
I = Rs.1350/-**

20.

If the simple interest on Rs.400 for 3 years is Rs.4000/-, what is the rate of interest percent per annum?

**Answer: Option 'C'**

**I = Rs.400/-
T = 3 years
P = Rs.4000/-
R = ?
S.I = (P×T×R/100)
R = (S.I×100)/(P×T)
R = (400×100)/(4000×3)
R = 10/3 = 3 1/3% **

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