1.
If the simple interest on Rs. 1120 for 2 years is Rs.8000/-, what is the rate of interest percent per annum?
Answer: Option 'B'
I = Rs.1120/-
T = 2 years
P = Rs.8000/-
R = ?
S.I = (P×T×R/100)
R = (S.I×100)/(P×T)
R = (1120×100)/(8000×2)
R = 56/8 = 7%
2.
A man borrowed some amount, after 3 years he paid Rs.10,400/- with 10% interest, then how much Amount he borrowed?
Answer: Option 'B'
principal P = ?
Rate of interest R = 10%
Time T = 3 years
Accumulated Amount A = Rs.10400/-
A = P + I
A = P + PTR/100
A = P(1+ TR/100)
Rs.10400/- = P [1 + 3*10/100]
Rs.10400/- = P [1/1 + 3/10]
Rs.10400/- = P [10+3/10] = P[13/10]
Rs.10400/- = P * 13/10
==> P = Rs.104000/13
==> P = Rs.8000/-
3.
A man took some money for borrowed, for 3 years the total will be Rs.4000 and 5 years it will be Rs.5000/-. Then how much amount he borrowed?
Answer: Option 'C'
3 years --------> Rs.4000/-
5 years --------> Rs.5000/-
~ ~
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2 years ----> Rs.1000/-
1 year -----> Rs.500/-
3 years × Rs.500/- = Rs.1500/-
P = Rs.4000/- - Rs.1500/- = Rs.2500/-
P = Rs.2500/-
4.
A borrow took by a man, for every 8 years it will be 3 times, then what is the rate of the interest?
Answer: Option 'C'
P = 1 , I = 2 , T = 8years R = ?
I = PTR/100
2 = 1×8×R/100
R = 25%
5.
A man took some money for borrowed, for 2 years the total will be Rs.9000/- and 5 years it will be13, Rs.500/-. Then how much amount he borrowed?
Answer: Option 'B'
2 years --------> Rs.9000/-
5 years --------> Rs.13500/-
~ ~
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3 years ----> Rs.4500/-
1 year -----> Rs.1500/-
2years × Rs.1500/- = Rs.3300/-
P = Rs.9000/- - Rs.30000/- = Rs.6000/-
P = Rs.6000/-