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Simplifications


  • 1. Find the value of 1/(3+1/(3+1/(3-1/3))) 
A.) 3/10
B.) 10/3
C.) 27/89
D.) 89/27

Answer: Option 'C'

1/[3 + (1/(3+1/(3 - 1/3)))] 
=> 1/[3 + 1/(3 + 1/(8/3))] 
=> 1/[3 + 1/(3 + 3/8)] 
=> 1/[3 + 8/27] 
=> 1/(89/27) 
=> 27/89

  • 2. Find the value of
A.) 3½ 99;
B.) 34/99
C.) 2.131313
D.) 3.141414

Answer: Option 'D'


6/9 + 7/9 + 9/9 + 69/99 
2/3 + 7/9 + 1 + 69/99 
(66 + 77 + 99 + 69)/99 
311/99 => 3.141414

  • 3. Find the value of
    ((0.1)3 + (0.6)3 + (0.7)3 − (0.3)(0.6)(0.7))/((0.1)2 + (0.6)2 + (0.7)2 − 0.006 − 0.42 − 0.07)
A.) 14/10
B.) 1.35
C.) 13/10
D.) 0

Answer: Option 'A'

((0.1)3 + (0.6)3 + (0.7)3 − (0.3)(0.6)(0.7))/((0.1)2 + (0.6)2 + (0.7)2 − 0.006 − 0.42 − 0.07)
=> (0.1 + 0.6 + 0.7)3/(0.1 + 0.6 + 0.7)2
=> 0.1 + 0.6 + 0.7 => 1.4 = 14/10

  • 4. Solve(0.76 × 0.76 × 0.76 − 0.008)/(0.76 × 0.76 + 0.76 × 0.2 + 0.04) 
A.) 0.56
B.) 0.65
C.) 0.54
D.) 0.45

Answer: Option 'A'

0.56

  • 5. Find the value of × in the following 
    (1 5/3) ÷ 3/11 × */11 = (2 2/3 × 7/5 × 6/7) 
A.) 4
B.) 3
C.) 3.6
D.) 3.06

Answer: Option 'C'

3.6

  • 6. Find the value of (2 − 1/3) (1 − 1/4)(1 − 1/5)……… (1 − 1/99)(1 − 1/100) 
A.) 1/50
B.) 1/25
C.) 1/20
D.) 1/40

Answer: Option 'C'

(2 − 1/3) (1 − 1/4)(1 − 1/5)..... (1 − 1/99)(1 − 1/100)
5/3 × 3/4 × 4/5 × ....... 98/99 × 99/100 = 5/100 = 1/20

  • 7. Find the value of (875 233/899) × 899 
A.) 786588
B.) 786858
C.) 786885
D.) 786885

Answer: Option 'B'

(875 233/899) × 899 
(786625 + 233)/899 × 899 
786858/899 × 899 
786858

To whom this Simplification Question and Answers section is beneficial?

Students can learn and improve on their skillset for using Simplification effectively and can also prepare for competitive examinations like...

  • All I.B.P.S and Public Sector Bank Competitive Exam
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  • NIIT online mock test
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  • Railway Competitive Exam
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  • Career Aptitude Test (IT Companies) and etc.

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