1.
A train of length 200 m can cross a man, sitting inside another train of length 100 m coming from opposite direction at speed of 25 m/sec, in 5 seconds. Find the speed of first train?
Answer: Option 'D'
Time taken by the train to cross the man = 300/(x+25) = 5 or 'x' = 35 m/sec
2.
A train 360 m long is running at a speed of 45 km/hr. In what time will it pass a bridge 140 m long?
Answer: Option 'A'
Given, Length of train =360 m
Length of bridge =140 m
Speed of train = 45 km/hr ---> Converting into meter/ second
= 45 × (5/18) m / sec
= 12.5 m/sec
=>Speed of train = 12.5 m/sec
Required Time =(Length of train +Length of bridge) /Speed of train
= (360 + 140) / 12.5
= 500 / 12.5
= 40 sec
=>Required Time =40 sec
3.
The 200-metre train crosses a platform double its length in 36seconds. What is the speed of the train in km/hr?
Answer: Option 'A'
Speed of the train = (200 + 400)m/36 sec = 600/36 m/sec
= (600*18)/(36*5) km/h
= 60 km/h
4.
If a man walks 24 Km at 8 Kmph, he will be late by 25min. if he walks 12 Kmph, how early the fixed time Will he reach?
Answer: Option 'D'
Time taken to cover 24 Km at the speed of 8 Kmph = 24/8 = 3 hours
Thus, right time was 2 hours 35 mintes
Now, time taken to cover 20 Km at the speed as 12 Kmph = 2 hours
Required time = 2 hours 35 minutes - 2 hours
= 35 minutes
5.
A train moves past a telegraph post and a bridge 264 m long in 8 seconds and 20 seconds respectively. What is the speed of the train?
Answer: Option 'B'
79.2 km/hr