1.
A person walking at 4 Kmph reaches his office 8 minutes late. If he walks at 6 Kmph, he reaches there 8 minutes earlier. How far is the office from his house?
Answer: Option 'A'
Formula = S1×S2/S2-S1 × T1+T2/60
= 4×6/2 × 16/6
= 24/2 × 16/60
= 8 × 2/5
= 16/5 = 3 1/5 Km
2.
A car takes 6 hours to cover a distance of 540 Km. how much should the speed in Kmph be maintained to cover the same direction in 3/2th of the previous time?
Answer: Option 'A'
Time = 6
Distence = 540
3/2 of 6 hours = 6 × 3/2 = 9 Hours
Required speed = 540/9 = 60 Kmph
3.
Avinash covers a distance of 8km in 50 minutes. If he covers 3km distance in 2/5th of time then, What speed should he maintain to cover the remaining distance in the remaining time?
Answer: Option 'C'
Total distance = 8 Km
Total time = 50 Km
Time taken to cover the distence of 3 Km = 50*2/5 = 20 min = 1/3 hours
Remaining distance = 8 - 3 = 5 Km
Required speed = 5/1/3 = 15 Kmph
4.
A man covers a distance of 180 Km at 72 Kmph and next 190km at 88 Kmph. what is his average speed For his whole journey of 370 Km?
Answer: Option 'A'
Formula = 2 × F.S*S.P/F.S+S.P
= 2 × 72 × 88/88+72
= 79.2 Kmph
5.
An aeroplane covers a certain distance of 420 Kmph in 6 hours. to cover the same distance in 4 2/3 hours, it Must travel at a speed of
Answer: Option 'C'
Speed of aeroplane = 420 Kmph
Distance travelled in 6 hours
= 420 × 6 = 2520 Km
Speed of aeroplane to acver 2520 Km in 14/3
= 2520 × 3/14 = 540 Km
6.
If a man walks 24 Km at 8 Kmph, he will be late by 25min. if he walks 12 Kmph, how early the fixed time Will he reach?
Answer: Option 'D'
Time taken to cover 24 Km at the speed of 8 Kmph = 24/8 = 3 hours
Thus, right time was 2 hours 35 mintes
Now, time taken to cover 20 Km at the speed as 12 Kmph = 2 hours
Required time = 2 hours 35 minutes - 2 hours
= 35 minutes
7.
In a covering a certain distance the speed of A and B are in the ratio of 6: 9, A takes 20 min more, than B to reach the destination. The time taken by A to reach the destination is:
Answer: Option 'A'
Let the speed of A and B are 6x Kmph
and 9x Kmph respectively,
Let the total distance to travel = y Km
y/6x - y/9x = 1/3
y/x(1/18 = 1/3
y = 6x
Required time = 6x/6x = 1 hour
8.
I walk a certain distance and ride the car back taking a total time of 33 Minutes. I could walk both sides in 45 min. How long would it take me to ride both ways?
Answer: Option 'C'
Time taken in walking a certaind distance
from X and Y = 22 1/2 Min
Time taken in riding the same distance
= 33 - 22 1/2 = 10 1/2 Min
it will take 21 Min to ride both ways
9.
A thief is noticed by a policeman from a distance of 300 Metres. The thief starts running and policeman chases him. The thief and the policeman run at the rate of 9 Kmph and 12 Kmph respectively. What is the difference between them after 3 Minutes?
Answer: Option 'D'
Speed of police man = 12 Kmph
and speed of thief = 9 Kmph
their relation speed = (12 - 9) = 3 Kmph
Distance travelled in 1/20 Hour
Thus, the distance between them = 150 Metres.
10.
A man starts at 3 pm with the speed of 50 Kmph. Another man follows him at 4 pm with the speed Of 75 Kmph. When will they meet?
Answer: Option 'B'