1.
A train speeds past pole in 15 seconds and a platform 100 m long in 25 seconds ,its length is:
Answer: Option 'A'
150 m
2.
The ratio of the speed of a car, a train and a bus is 5 : 9 : 4. The average speed of the car, the bus and the train is 72 km/hr together. What is the average speed of the car and the train together?
Answer: Option 'C'
Total speed of car, train, bus = 72 x 3 = 216 km/hr
Total speed of car and train = (216 x 14)/18 = 168 km/hr
Average speed of car and train = 168/2 = 84 km/hr
3.
A train passes a station platform in 36 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr ,what is the length of the platform?
Answer: Option 'B'
Given, time taken by train to pass the man = 20 sec
Speed of the train = 54 km/hr
---> Converting into meter/sec
=> Speed of train =54 × (5/18) m/sec = 15 m/sec
W.K.T: Speed of train = Length of train/ Time taken by train to pass the man
=> 15 =Length of train / 20
=>Length of train = 15 × 20
=>Length of train = 300 metre.
Given,A train passes a station platform in 36 seconds.
=>Speed of train = (Length of train + Length of platform) / Time taken by train to pass the platform
=> 15 = (300 +Length of platform) / 36
=> 15 × 36 = (300+Length of platform)
=> 540 =300+Length of platform
=> 540 - 300 =Length of platform
Thus,Length of platform = 240 meter.
4.
An aeroplane covers a certain distance of 420 Kmph in 6 hours. to cover the same distance in 4 2/3 hours, it Must travel at a speed of
Answer: Option 'C'
Speed of aeroplane = 420 Kmph
Distance travelled in 6 hours
= 420 × 6 = 2520 Km
Speed of aeroplane to acver 2520 Km in 14/3
= 2520 × 3/14 = 540 Km
5.
A car takes 6 hours to cover a distance of 540 Km. how much should the speed in Kmph be maintained to cover the same direction in 3/2th of the previous time?
Answer: Option 'A'
Time = 6
Distence = 540
3/2 of 6 hours = 6 × 3/2 = 9 Hours
Required speed = 540/9 = 60 Kmph
6.
A train 800 m long is running at a speed of 78 km/hr. If it crosses a tunnel in 1 minute, then the length of the tunnel is:
Answer: Option 'B'
Given, Length of the train = 800 m
Speed of the train = 78 km/hr (convert km/hr to m/sec)
= 78 × (5/18) m /sec
= 21.667 m /sec
=> Speed of the train = 21.667 m /sec
Time taken by the train to cross the tunnel = 1 min = 60 sec
To find the length of the tunnel:
Time taken by train to cross tunnel = (Length of tunnel + Length of train) / speed of the train
=> 60 = (Length of tunnel + 800) / 21.667
=> 60 × 21.667 = Length of tunnel + 800
=> 1300 = Length of tunnel + 800
=> 1300 – 800 = Length of tunnel
=> 500 = Length of tunnel
Thus, the Length of tunnel = 500 m
7.
Train A crosses a pole in 20 seconds and Train B crosses the same pole in one minute. The length of Train A is half of the length of Train B. what is the ratio of the speed of Train A to that of Train B?
Answer: Option 'A'
Let the length of Train B be 2x and that of Train A be X.
Speed of Train A = x/20
Speed of Train B = 2x/60 = x/30
Ratio = Speed A/Speed B = X × 30/X * 20 = 3/2
8.
A thief is noticed by a policeman from a distance of 300 Metres. The thief starts running and policeman chases him. The thief and the policeman run at the rate of 9 Kmph and 12 Kmph respectively. What is the difference between them after 3 Minutes?
Answer: Option 'D'
Speed of police man = 12 Kmph
and speed of thief = 9 Kmph
their relation speed = (12 - 9) = 3 Kmph
Distance travelled in 1/20 Hour
Thus, the distance between them = 150 Metres.
9.
Mohit traveled 20% of the time walking at a speed of 10 km/hr, 50% of the time in a bus at 40 km/hr and rest of the journey in a cab at 50 km/hr. What is the average speed of Mohit over the entire journey?
Answer: Option 'A'
Let the total time Mohit takes to complete the entire journey be t hours
Mohit spent 20%, 50% and the remaining 30% of the time walking in the bus and in the cab respectively.
Thus, time spent walking, in the bus and in the cab are 0.2 t, 0.5 t and 0.3 t respectively.
So Average speed = Total distance covered/Total Time taken = 10(0.2 t0 + 40(0.5 t) + 50(0.3 t)/t = 37 km/hr
10.
If a man walks 24 Km at 8 Kmph, he will be late by 25min. if he walks 12 Kmph, how early the fixed time Will he reach?
Answer: Option 'D'
Time taken to cover 24 Km at the speed of 8 Kmph = 24/8 = 3 hours
Thus, right time was 2 hours 35 mintes
Now, time taken to cover 20 Km at the speed as 12 Kmph = 2 hours
Required time = 2 hours 35 minutes - 2 hours
= 35 minutes
11.
A 280 – meter – long train moving with an average speed of 108 km/h crosses a platform in 12 seconds. A man crosses the same platform in 10 seconds. What is the speed of the man?
Answer: Option 'B'
Speed of thain = 108 km/hr = (108 x 5)/18 m/sec 30 m/sec
If the length of the platform be x meters, then
x + 280/12 = 30
x + 280 = 360
x = 3 = (360 - 280) = 80m
speed of man = 80/10 = 8m/sec
12.
A bus started its journey from Ramgarh and reached Devgarh in 44 minutes at its average speed of 50 km/hr. If the average speed of the bus is increased by 5km/hour, how much time will it take to cover the same distance?
Answer: Option 'A'
Distance = (44/60) x 50 = (x/60) x 55
x = 40 minutes
13.
The average speed of a train is 1(3⁄7) the average speed of a car. The car covers a distance of 588 km in 6 hours. How much distance will the train cover in 13 hours?
Answer: Option 'D'
Speed of the car = 588/6 = 98 km/hr
Speed of train = (10/7) x 98 = 140 km/hr
Distance covered by the train in 13 hours = 140 x 13 = 1820 km
14.
Avinash covers a distance of 8km in 50 minutes. If he covers 3km distance in 2/5th of time then, What speed should he maintain to cover the remaining distance in the remaining time?
Answer: Option 'C'
Total distance = 8 Km
Total time = 50 Km
Time taken to cover the distence of 3 Km = 50*2/5 = 20 min = 1/3 hours
Remaining distance = 8 - 3 = 5 Km
Required speed = 5/1/3 = 15 Kmph
15.
The 200-metre train crosses a platform double its length in 36seconds. What is the speed of the train in km/hr?
Answer: Option 'A'
Speed of the train = (200 + 400)m/36 sec = 600/36 m/sec
= (600*18)/(36*5) km/h
= 60 km/h
16.
The length of the bridge , which a train 130 m long and travelling at 45 km/hr can cross in 30 seconds, is:
Answer: Option 'C'
245 m
17.
A train 240 m long passed a pole in 24 seconds .How long will it take to pass a platform 650 m long?
Answer: Option 'A'
89 sec
18.
A motorist travels for 6 hours, the first half at 60 Kmph and the rest at 48 Kmph. Find the distance Traveled by him.
Answer: Option 'A'
Distance = 3 × 60 + 3 × 48
= 180 + 144
= 324 Km
19.
A man covers a distance of 180 Km at 72 Kmph and next 190km at 88 Kmph. what is his average speed For his whole journey of 370 Km?
Answer: Option 'A'
Formula = 2 × F.S*S.P/F.S+S.P
= 2 × 72 × 88/88+72
= 79.2 Kmph
20.
A 320 meter long train moving with an average speed of 120 km/hr crosses a platform in 24 seconds. A man crosses the same platform in 4 minutes. What is the speed of man in meter/second?
Answer: Option 'D'
Let the length of the platform be x meters, Then,
Speed of train = 120 km/h = 120 x 5/18 = 100/3 mps
320 + x = 100 x 24/3,
x = 800 - 320 = 480m
Required speed of man = 480/(4x60) = 2 mps