1.
A car takes 6 hours to cover a distance of 540 Km. how much should the speed in Kmph be maintained to cover the same direction in 3/2th of the previous time?
Answer: Option 'A'
Time = 6
Distence = 540
3/2 of 6 hours = 6 × 3/2 = 9 Hours
Required speed = 540/9 = 60 Kmph
2.
A 280 – meter – long train moving with an average speed of 108 km/h crosses a platform in 12 seconds. A man crosses the same platform in 10 seconds. What is the speed of the man?
Answer: Option 'B'
Speed of thain = 108 km/hr = (108 x 5)/18 m/sec 30 m/sec
If the length of the platform be x meters, then
x + 280/12 = 30
x + 280 = 360
x = 3 = (360 - 280) = 80m
speed of man = 80/10 = 8m/sec
3.
A train moves past a telegraph post and a bridge 264 m long in 8 seconds and 20 seconds respectively. What is the speed of the train?
Answer: Option 'B'
79.2 km/hr
4.
A goods train runs at the speed of 72 km/hr and crosses a 250 m long platform in 26 seconds .What is the length of the goods train?
Answer: Option 'A'
270 m
5.
The length of the bridge , which a train 130 m long and travelling at 45 km/hr can cross in 30 seconds, is:
Answer: Option 'C'
245 m
6.
A bus started its journey from Ramgarh and reached Devgarh in 44 minutes at its average speed of 50 km/hr. If the average speed of the bus is increased by 5km/hour, how much time will it take to cover the same distance?
Answer: Option 'A'
Distance = (44/60) x 50 = (x/60) x 55
x = 40 minutes
7.
How many seconds will a 500 m long train take to cross a man walking with a speed of 3 km/hr in the direction of the moving train if the speed of the train is 63 km/hr?
Answer: Option 'A'
Given, Length of the train = 500 m
Speed of the man = 3 km/hr
Speed of the train = 63 km/hr
Time taken by the train to cross a man = Length of the train / (speed of the train – speed of the man)
=> Time = 500 m / (63 – 3) km/hr
=> Time = 500 m / 60 km/hr
(to convert 60 km/hr to m/sec)
=> Time = 500 m / [60 × (5/18) m/sec]
=> Time = {500 / [60 × (5/18)]} sec
=> Time = {(500 × 18) / (60 * 5)} sec
=> Time = 30 sec
8.
In a covering a certain distance the speed of A and B are in the ratio of 6: 9, A takes 20 min more, than B to reach the destination. The time taken by A to reach the destination is:
Answer: Option 'A'
Let the speed of A and B are 6x Kmph
and 9x Kmph respectively,
Let the total distance to travel = y Km
y/6x - y/9x = 1/3
y/x(1/18 = 1/3
y = 6x
Required time = 6x/6x = 1 hour
9.
If a man walks 24 Km at 8 Kmph, he will be late by 25min. if he walks 12 Kmph, how early the fixed time Will he reach?
Answer: Option 'D'
Time taken to cover 24 Km at the speed of 8 Kmph = 24/8 = 3 hours
Thus, right time was 2 hours 35 mintes
Now, time taken to cover 20 Km at the speed as 12 Kmph = 2 hours
Required time = 2 hours 35 minutes - 2 hours
= 35 minutes
10.
An aeroplane covers a certain distance of 420 Kmph in 6 hours. to cover the same distance in 4 2/3 hours, it Must travel at a speed of
Answer: Option 'C'
Speed of aeroplane = 420 Kmph
Distance travelled in 6 hours
= 420 × 6 = 2520 Km
Speed of aeroplane to acver 2520 Km in 14/3
= 2520 × 3/14 = 540 Km
11.
A man starts at 3 pm with the speed of 50 Kmph. Another man follows him at 4 pm with the speed Of 75 Kmph. When will they meet?
Answer: Option 'B'
12.
A train 800 m long is running at a speed of 78 km/hr. If it crosses a tunnel in 1 minute, then the length of the tunnel is:
Answer: Option 'B'
Given, Length of the train = 800 m
Speed of the train = 78 km/hr (convert km/hr to m/sec)
= 78 × (5/18) m /sec
= 21.667 m /sec
=> Speed of the train = 21.667 m /sec
Time taken by the train to cross the tunnel = 1 min = 60 sec
To find the length of the tunnel:
Time taken by train to cross tunnel = (Length of tunnel + Length of train) / speed of the train
=> 60 = (Length of tunnel + 800) / 21.667
=> 60 × 21.667 = Length of tunnel + 800
=> 1300 = Length of tunnel + 800
=> 1300 – 800 = Length of tunnel
=> 500 = Length of tunnel
Thus, the Length of tunnel = 500 m
13.
A 320 meter long train moving with an average speed of 120 km/hr crosses a platform in 24 seconds. A man crosses the same platform in 4 minutes. What is the speed of man in meter/second?
Answer: Option 'D'
Let the length of the platform be x meters, Then,
Speed of train = 120 km/h = 120 x 5/18 = 100/3 mps
320 + x = 100 x 24/3,
x = 800 - 320 = 480m
Required speed of man = 480/(4x60) = 2 mps
14.
A thief is noticed by a policeman from a distance of 300 Metres. The thief starts running and policeman chases him. The thief and the policeman run at the rate of 9 Kmph and 12 Kmph respectively. What is the difference between them after 3 Minutes?
Answer: Option 'D'
Speed of police man = 12 Kmph
and speed of thief = 9 Kmph
their relation speed = (12 - 9) = 3 Kmph
Distance travelled in 1/20 Hour
Thus, the distance between them = 150 Metres.
15.
A motorist travels for 6 hours, the first half at 60 Kmph and the rest at 48 Kmph. Find the distance Traveled by him.
Answer: Option 'A'
Distance = 3 × 60 + 3 × 48
= 180 + 144
= 324 Km
16.
A train 110 m long is running with speed of 60 km/hr .In what time will it pass a man who is running at 6 km/hr in the direction opposite to that in which the train is going?
Answer: Option 'C'
Relative speed = Train speed + Man Speed = 60 + 6 = 66 kmph = 18 1/3 m /sec
Distance to be covered = 110 meter
Time taken = Speed / Distance = 110 / (18 1/3) = (110 / 55) x 3 = 2 x 3 = 6 sec
17.
Train A crosses a pole in 20 seconds and Train B crosses the same pole in one minute. The length of Train A is half of the length of Train B. what is the ratio of the speed of Train A to that of Train B?
Answer: Option 'A'
Let the length of Train B be 2x and that of Train A be X.
Speed of Train A = x/20
Speed of Train B = 2x/60 = x/30
Ratio = Speed A/Speed B = X × 30/X * 20 = 3/2
18.
A train 360 m long is running at a speed of 45 km/hr. In what time will it pass a bridge 140 m long?
Answer: Option 'A'
Given, Length of train =360 m
Length of bridge =140 m
Speed of train = 45 km/hr ---> Converting into meter/ second
= 45 × (5/18) m / sec
= 12.5 m/sec
=>Speed of train = 12.5 m/sec
Required Time =(Length of train +Length of bridge) /Speed of train
= (360 + 140) / 12.5
= 500 / 12.5
= 40 sec
=>Required Time =40 sec
19.
I walk a certain distance and ride the car back taking a total time of 33 Minutes. I could walk both sides in 45 min. How long would it take me to ride both ways?
Answer: Option 'C'
Time taken in walking a certaind distance
from X and Y = 22 1/2 Min
Time taken in riding the same distance
= 33 - 22 1/2 = 10 1/2 Min
it will take 21 Min to ride both ways
20.
Avinash covers a distance of 8km in 50 minutes. If he covers 3km distance in 2/5th of time then, What speed should he maintain to cover the remaining distance in the remaining time?
Answer: Option 'C'
Total distance = 8 Km
Total time = 50 Km
Time taken to cover the distence of 3 Km = 50*2/5 = 20 min = 1/3 hours
Remaining distance = 8 - 3 = 5 Km
Required speed = 5/1/3 = 15 Kmph