## RRB NTPC - Averages (200 Questions with Explanation): Quantitative Aptitude Test

• 151. In the first 30 overs of a cricket game, the run rate was only 4.5. What should be the run rate in the remaining 20 overs to reach the target of 320 runs. ?
A.)
B.) 11.75
C.) 9.25
D.) 19.25

Answer: Option 'C'

Required Run rate = ( 320 - ( 4.5 x 30 ) )/ (20) = ( 185) /(20) = 9.25

• 152. In the first 30 overs of a cricket game, the run rate was only 4.5. What should be the run rate in the remaining 20 overs to reach the target of 320 runs. ?
A.)
B.) 11.75
C.) 9.25
D.) 19.25

Answer: Option 'C'

Required Run rate = ( 320 - ( 4.5 x 30 ) )/ (20) = ( 185) /(20) = 9.25

• 153. In the first 30 overs of a cricket game, the run rate was only 5.4. What should be the run rate in the remaining 20 overs to reach the target of 314 runs. ?
A.) 8.4
B.) 9.1
C.) 7.6
D.) 6.5

Answer: Option 'C'

"Required Run rate = ( 314 - ( 5.4 x 30 ) )/ (20) = ( 152) /(20) = 7.6 "

• 154. In the first 30 overs of a cricket game, the run rate was only 5.4. What should be the run rate in the remaining 20 overs to reach the target of 314 runs. ?
A.) 8.4
B.) 9.1
C.) 7.6
D.) 6.5

Answer: Option 'C'

"Required Run rate = ( 314 - ( 5.4 x 30 ) )/ (20) = ( 152) /(20) = 7.6 "

• 155. The average of 30 numbers is zero. Of them, at the most how many may be greater than zero?
A.) 30
B.) 29
C.) 28
D.) 15

Answer: Option 'B'

Average of 30 numbers is = 0
Therefore sum of all 30 numbers = 0
It is quite possible that 29 of these numbers may be positive and if their sum is "a" then 30th number is "(-a)"

• 156. The average of 30 numbers is zero. Of them, at the most how many may be greater than zero?
A.) 30
B.) 29
C.) 28
D.) 15

Answer: Option 'B'

Average of 30 numbers is = 0
Therefore sum of all 30 numbers = 0
It is quite possible that 29 of these numbers may be positive and if their sum is "a" then 30th number is "(-a)"

• 157. In the first 25 overs of a cricket game, the run rate was only 2.2. What should be the run rate in the remaining 25 overs to reach the target of 225 runs. ?
A.) 7.5
B.) 6.8
C.) 5.8
D.) 12.3

Answer: Option 'B'

"Required Run rate = ( 225 - ( 2.2 x 25 ) )/ (25) = ( 170) /(25) = 6.8 "

• 158. In the first 25 overs of a cricket game, the run rate was only 2.2. What should be the run rate in the remaining 25 overs to reach the target of 225 runs. ?
A.) 7.5
B.) 6.8
C.) 5.8
D.) 12.3

Answer: Option 'B'

"Required Run rate = ( 225 - ( 2.2 x 25 ) )/ (25) = ( 170) /(25) = 6.8 "

• 159. In the first 25 overs of a cricket game, the run rate was only 2.2. What should be the run rate in the remaining 25 overs to reach the target of 225 runs. ?
A.) 7.5
B.) 6.8
C.) 5.8
D.) 12.3

Answer: Option 'B'

"Required Run rate = ( 225 - ( 2.2 x 25 ) )/ (25) = ( 170) /(25) = 6.8 "

• 160. In the first 25 overs of a cricket game, the run rate was only 2.2. What should be the run rate in the remaining 25 overs to reach the target of 225 runs. ?
A.) 7.5
B.) 6.8
C.) 5.8
D.) 12.3

Answer: Option 'B'

"Required Run rate = ( 225 - ( 2.2 x 25 ) )/ (25) = ( 170) /(25) = 6.8 "

• 161. In the first 10 overs of a cricket game, the run rate was only 5.6. What should be the run rate in the remaining 40 overs to reach the target of 254 runs. ?
A.) 5.4
B.) 5.9
C.) 5
D.) 8.5

Answer: Option 'C'

Given
Target = 254 runs
First 10 overs, run rate = 5.6
Remaining Overs = 40.
Required Run rate
= ( 254 - ( 5.6 x 10 ) / (40)
= ( 198 ) /(40)
=4.95

• 162. In the first 10 overs of a cricket game, the run rate was only 5.6. What should be the run rate in the remaining 40 overs to reach the target of 254 runs. ?
A.) 5.4
B.) 5.9
C.) 5
D.) 8.5

Answer: Option 'C'

Given
Target = 254 runs
First 10 overs, run rate = 5.6
Remaining Overs = 40.
Required Run rate
= ( 254 - ( 5.6 x 10 ) / (40)
= ( 198 ) /(40)
=4.95

• 163. In the first 30 overs of a cricket game, the run rate was only 6.4. What should be the run rate in the remaining 20 overs to reach the target of 225 runs. ?
A.) 1.65
B.) 1.98
C.) 1.485
D.) 2.935

Answer: Option 'A'

Given
In, first30 overs of a cricket game.
Run rate = 6.4
Required Run rate in the remaining 20 overs to reach the target of 225 runs
Required Run rate
= ( 225 - ( 6.4 x 30 ) ) / (20)
= ( 33) / (20)
= 1.65.

• 164. In the first 30 overs of a cricket game, the run rate was only 6.4. What should be the run rate in the remaining 20 overs to reach the target of 225 runs. ?
A.) 1.65
B.) 1.98
C.) 1.485
D.) 2.935

Answer: Option 'A'

Given
In, first30 overs of a cricket game.
Run rate = 6.4
Required Run rate in the remaining 20 overs to reach the target of 225 runs
Required Run rate
= ( 225 - ( 6.4 x 30 ) ) / (20)
= ( 33) / (20)
= 1.65.

• 165. In the first 10 overs of a cricket game, the run rate was only 6.2. What should be the run rate in the remaining 40 overs to reach the target of 414 runs. ?
A.) 7.9
B.) 8.8
C.) 13.1
D.) 9.7

Answer: Option 'B'

Given
Target = 414 runs
First 10 overs, run rate = 6.2
Required Run rate
= ( 414 - ( 6.2 x 10 ) / (40)
= ( 352) /(40)
= 8.8

• 166. In the first 10 overs of a cricket game, the run rate was only 6.2. What should be the run rate in the remaining 40 overs to reach the target of 414 runs. ?
A.) 7.9
B.) 8.8
C.) 13.1
D.) 9.7

Answer: Option 'B'

Given
Target = 414 runs
First 10 overs, run rate = 6.2
Required Run rate
= ( 414 - ( 6.2 x 10 ) / (40)
= ( 352) /(40)
= 8.8

• 167. The average of 34 numbers is zero. Of them, at the most how many may be greater than zero?
A.) 34
B.) 35
C.) 32
D.) 33

Answer: Option 'C'

Average of 34 numbers is = 0
Therefore sum of all 34 numbers = 0
It is quite possible that 33 of these numbers may be positive and if their sum is a then 34th number is (-a)

• 168. The average of 34 numbers is zero. Of them, at the most how many may be greater than zero?
A.) 34
B.) 35
C.) 32
D.) 33

Answer: Option 'C'

Average of 34 numbers is = 0
Therefore sum of all 34 numbers = 0
It is quite possible that 33 of these numbers may be positive and if their sum is a then 34th number is (-a)

• 169. In the first 25 overs of a cricket game, the run rate was only 1.3. What should be the run rate in the remaining 25 overs to reach the target of 287 runs. ?
A.) 10.2
B.) 12.2
C.) 9.2
D.) 14.1

Answer: Option 'A'

"Required Run rate = ( 287 - ( 1.3 x 25 ) )/ (25) = ( 254.5) /(25) = 10.18 "

• 170. In the first 25 overs of a cricket game, the run rate was only 1.3. What should be the run rate in the remaining 25 overs to reach the target of 287 runs. ?
A.) 10.2
B.) 12.2
C.) 9.2
D.) 14.1

Answer: Option 'A'

"Required Run rate = ( 287 - ( 1.3 x 25 ) )/ (25) = ( 254.5) /(25) = 10.18 "

• 171. In the first 25 overs of a cricket game, the run rate was only 5.6. What should be the run rate in the remaining 25 overs to reach the target of 280 runs. ?
A.) 6.16
B.) 6.72
C.) 5.6
D.) 5.04

Answer: Option 'C'

Required Run rate = ( 280 - ( 5.6 x 25 ) )/ (25) = ( 140) /(25) = 5.6

• 172. In the first 25 overs of a cricket game, the run rate was only 5.6. What should be the run rate in the remaining 25 overs to reach the target of 280 runs. ?
A.) 6.16
B.) 6.72
C.) 5.6
D.) 5.04

Answer: Option 'C'

Required Run rate = ( 280 - ( 5.6 x 25 ) )/ (25) = ( 140) /(25) = 5.6

• 173. In the first 25 overs of a cricket game, the run rate was only 1.3. What should be the run rate in the remaining 25 overs to reach the target of 287 runs?
A.) 10.18
B.) 9.162
C.) 12.216
D.) 14.058

Answer: Option 'A'

Required Run rate = ( 287 - ( 1.3 x 25 ) )/ (25) = ( 254.5) /(25) = 10.18

• 174. In the first 25 overs of a cricket game, the run rate was only 1.3. What should be the run rate in the remaining 25 overs to reach the target of 287 runs?
A.) 10.18
B.) 9.162
C.) 12.216
D.) 14.058

Answer: Option 'A'

Required Run rate = ( 287 - ( 1.3 x 25 ) )/ (25) = ( 254.5) /(25) = 10.18

• 175. Of three numbers, the third is twice the second and the second is 4 times the first. If their average is 78, the smallest of the three numbers is:
A.) 18
B.) 21
C.) 17
D.) 15

Answer: Option 'A'

Let first number be x.
So,2nd number = 4x and 3rd number = 8x.
Given average = 78 So,x + 4x + 8x = 78 Ã— 3 = 234. => 13x = 234 => x = 234/13
Hence, Smallest Number x=18.