- 201. In the first 10 overs of a cricket game, the run rate was only 3.2. What should be the run rate in the remaining 40 overs to reach the target of 282 runs?

**Answer: Option 'A'**

**Required Run rate = ( 282 - ( 3.2 x 10 ) )/ (40) = ( 250) /(40) = 6.25**

- 202. In the first 10 overs of a cricket game, the run rate was only 3.2. What should be the run rate in the remaining 40 overs to reach the target of 282 runs?

**Answer: Option 'A'**

**Required Run rate = ( 282 - ( 3.2 x 10 ) )/ (40) = ( 250) /(40) = 6.25**

- 203. In the first 10 overs of a cricket game, the run rate was only 1.8. What should be the run rate in the remaining 20 overs to reach the target of 225 runs?

**Answer: Option 'A'**

**Required Run rate = ( 225 - ( 1.8 x 10 ) )/ (20) = (207 ) /(20) = 10.35**

- 204. In the first 10 overs of a cricket game, the run rate was only 1.8. What should be the run rate in the remaining 20 overs to reach the target of 225 runs?

**Answer: Option 'A'**

**Required Run rate = ( 225 - ( 1.8 x 10 ) )/ (20) = (207 ) /(20) = 10.35**

- 205. The average age of a group of 10 students was 26. The average age increased by 1 years when two new students joined the group. What is the average age of the two new students who joined the group?

**Answer: Option 'B'**

**The average age of a group of 10 students is 26.
Therefore, the sum of the ages of all 10 of them
= 10 × 26
= 260
When two students joins the group, the average increase by 1.
New Average = 27
Now there are 12 students Therefore, sum of all the ages of 12 students
= 12 × 27
= 324
Therefore, the sum of the ages of two students who joined
= 324 - 260
= 64
And the average age of these two students
= 64 / 2
= 32.**

- 206. The average age of a group of 10 students was 26. The average age increased by 1 years when two new students joined the group. What is the average age of the two new students who joined the group?

**Answer: Option 'B'**

**The average age of a group of 10 students is 26.
Therefore, the sum of the ages of all 10 of them
= 10 × 26
= 260
When two students joins the group, the average increase by 1.
New Average = 27
Now there are 12 students Therefore, sum of all the ages of 12 students
= 12 × 27
= 324
Therefore, the sum of the ages of two students who joined
= 324 - 260
= 64
And the average age of these two students
= 64 / 2
= 32.**

- 207. Average of five consecutive odd numbers is 35. Find the greatest number in these five numbers?

**Answer: Option 'C'**

**Let the Consecutive odd numbers are x , x +2 , x + 4 , x+ 6, x+ 8.
Given , Average of fiveConsecutive odd numbers = 35
=> Average = (x + x + 2 + x + 4 + x + 6 + x + 8)/5 = 35
=> (5x + 20) / 5 = 35
=> 5x + 20 = 175
=> 5x = 175 - 20
=> 5x = 155
=> x = 31 ---> which is the first term of the given consecutive odd series.
The numbers are 31, 33, 35 and 37, 39
The greatest number is 39.**

- 208. Average of five consecutive odd numbers is 35. Find the greatest number in these five numbers?

**Answer: Option 'C'**

**Let the Consecutive odd numbers are x , x +2 , x + 4 , x+ 6, x+ 8.
Given , Average of fiveConsecutive odd numbers = 35
=> Average = (x + x + 2 + x + 4 + x + 6 + x + 8)/5 = 35
=> (5x + 20) / 5 = 35
=> 5x + 20 = 175
=> 5x = 175 - 20
=> 5x = 155
=> x = 31 ---> which is the first term of the given consecutive odd series.
The numbers are 31, 33, 35 and 37, 39
The greatest number is 39.**

- 209. Find the average of the first 56 natural numbers

**Answer: Option 'A'**

**Solution is**

Average of the first n natural numbers = (n + 1) / 2

Average of the first 56 natural numbers = (56 + 1) / 2

= 57 / 2

= 28.5

- 210. Find the average of the first 56 natural numbers

**Answer: Option 'A'**

**Solution is**

Average of the first n natural numbers = (n + 1) / 2

Average of the first 56 natural numbers = (56 + 1) / 2

= 57 / 2

= 28.5

- 211. The average weight of a class having 25 students is 32 kg. Find the total weight of the class.

**Answer: Option 'D'**

**Solution is**

Given, Average weight = 32 kg

No.of students = 25

**Average = Total Quantity / No. of Quantity**

=> Total Weight of the class = Average weight x No. of Students

= 32 x 25

= 800

**Answer is 800**

- 212. The average weight of a class having 25 students is 32 kg. Find the total weight of the class.

**Answer: Option 'D'**

**Solution is**

Given, Average weight = 32 kg

No.of students = 25

**Average = Total Quantity / No. of Quantity**

=> Total Weight of the class = Average weight x No. of Students

= 32 x 25

= 800

**Answer is 800**

- 213. Find the average of the first 14 natural numbers

**Answer: Option 'B'**

**Solution is :**

**Average of the first n natural numbers = ( n + 1 ) / 2**

Average of the first 14 natural numbers = ( 14 + 1 ) / 2

= 15 / 2

**= 7.5**

- 214. Find the average of the first 14 natural numbers

**Answer: Option 'B'**

**Solution is :**

**Average of the first n natural numbers = ( n + 1 ) / 2**

Average of the first 14 natural numbers = ( 14 + 1 ) / 2

= 15 / 2

**= 7.5**

- 215. The average weight of a class having 16 students is 36 kg. Find the total weight of the class.

**Answer: Option 'A'**

**Solution is :**

Given, average weight = 36 kg

No. of students = 16

**Average = Total Quantity / No. of Quantity**

**=> Total weight of the class = Average weight x No. of Students**

= 36 × 16

**= 576 kg**

- 216. The average weight of a class having 16 students is 36 kg. Find the total weight of the class.

**Answer: Option 'A'**

**Solution is :**

Given, average weight = 36 kg

No. of students = 16

**Average = Total Quantity / No. of Quantity**

**=> Total weight of the class = Average weight x No. of Students**

= 36 × 16

**= 576 kg**

- 217. Find the average of the first 70 natural numbers ?

**Answer: Option 'B'**

**Solution is :**

**Average of the first n natural numbers = ( n + 1 ) / 2**

Average of the first 70 natural numbers = ( 70 + 1 ) / 2

= 71 / 2

**= 35.5**

- 218. Find the average of the first 70 natural numbers ?

**Answer: Option 'B'**

**Solution is :**

**Average of the first n natural numbers = ( n + 1 ) / 2**

Average of the first 70 natural numbers = ( 70 + 1 ) / 2

= 71 / 2

**= 35.5**

- 219. Find the average of first 26 multiples of 11.

**Answer: Option 'A'**

**Average of first 26 natural numbers = ( n + 1 ) / 2
= ( 26 + 1 ) / 2
= 27 / 2
= 13.5
Average of first 26 multiples of 11 = ( Average of first 26 natural numbers ) × 11
= 13.5 × 11
= 148.5**

- 220. Find the average of first 26 multiples of 11.

**Answer: Option 'A'**

**Average of first 26 natural numbers = ( n + 1 ) / 2
= ( 26 + 1 ) / 2
= 27 / 2
= 13.5
Average of first 26 multiples of 11 = ( Average of first 26 natural numbers ) × 11
= 13.5 × 11
= 148.5**

- 221. The average weight of a class having 14 students is 36 kg. Find the total weight of the class.

**Answer: Option 'A'**

**Solution is :**

Given, Average weight of the class = 36 kg

No. of students in the class = 14

**Average = Total Quantity / No. of Quantity
=> Total weight of the class = Average weight x No. of students**

= 36 × 14

=

- 222. The average weight of a class having 14 students is 36 kg. Find the total weight of the class.

**Answer: Option 'A'**

**Solution is :**

Given, Average weight of the class = 36 kg

No. of students in the class = 14

**Average = Total Quantity / No. of Quantity
=> Total weight of the class = Average weight x No. of students**

= 36 × 14

=

- 223. Find the average of first 17 multiples of 3

**Answer: Option ''**

**Solution is
Given**

Average of first 17 natural numbers=

=(18 / 2 )

= 9

Average of first 17 multiples of 3 =(Average of first 17 natural numbers) x 3

= 9 x 3

- 224. Find the average of first 17 multiples of 3

**Answer: Option ''**

**Solution is
Given**

Average of first 17 natural numbers=

=(18 / 2 )

= 9

Average of first 17 multiples of 3 =(Average of first 17 natural numbers) x 3

= 9 x 3

- 225. The average weight of a class having 14 students is 36 kg. Find the total weight of the class.

**Answer: Option 'A'**

**Total quantity = Average x No. of Quantity
Total weight = Average weight x No.of students**

= 36 x 14

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