## RRB NTPC - Averages (200 Questions with Explanation): Quantitative Aptitude Test

• 201. In the first 10 overs of a cricket game, the run rate was only 3.2. What should be the run rate in the remaining 40 overs to reach the target of 282 runs?
A.) 6.25
B.) 7.5
C.) 5.625
D.) 8.635

Answer: Option 'A'

Required Run rate = ( 282 - ( 3.2 x 10 ) )/ (40) = ( 250) /(40) = 6.25

• 202. In the first 10 overs of a cricket game, the run rate was only 3.2. What should be the run rate in the remaining 40 overs to reach the target of 282 runs?
A.) 6.25
B.) 7.5
C.) 5.625
D.) 8.635

Answer: Option 'A'

Required Run rate = ( 282 - ( 3.2 x 10 ) )/ (40) = ( 250) /(40) = 6.25

• 203. In the first 10 overs of a cricket game, the run rate was only 1.8. What should be the run rate in the remaining 20 overs to reach the target of 225 runs?
A.) 10.35
B.) 11.35
C.) 10
D.) 12.35

Answer: Option 'A'

Required Run rate = ( 225 - ( 1.8 x 10 ) )/ (20) = (207 ) /(20) = 10.35

• 204. In the first 10 overs of a cricket game, the run rate was only 1.8. What should be the run rate in the remaining 20 overs to reach the target of 225 runs?
A.) 10.35
B.) 11.35
C.) 10
D.) 12.35

Answer: Option 'A'

Required Run rate = ( 225 - ( 1.8 x 10 ) )/ (20) = (207 ) /(20) = 10.35

• 205. The average age of a group of 10 students was 26. The average age increased by 1 years when two new students joined the group. What is the average age of the two new students who joined the group?
A.) 22
B.) 32
C.) 21
D.) 41

Answer: Option 'B'

The average age of a group of 10 students is 26.
Therefore, the sum of the ages of all 10 of them
= 10 × 26
= 260
When two students joins the group, the average increase by 1.
New Average = 27
Now there are 12 students Therefore, sum of all the ages of 12 students
= 12 × 27
= 324
Therefore, the sum of the ages of two students who joined
= 324 - 260
= 64
And the average age of these two students
= 64 / 2
= 32.

• 206. The average age of a group of 10 students was 26. The average age increased by 1 years when two new students joined the group. What is the average age of the two new students who joined the group?
A.) 22
B.) 32
C.) 21
D.) 41

Answer: Option 'B'

The average age of a group of 10 students is 26.
Therefore, the sum of the ages of all 10 of them
= 10 × 26
= 260
When two students joins the group, the average increase by 1.
New Average = 27
Now there are 12 students Therefore, sum of all the ages of 12 students
= 12 × 27
= 324
Therefore, the sum of the ages of two students who joined
= 324 - 260
= 64
And the average age of these two students
= 64 / 2
= 32.

• 207. Average of five consecutive odd numbers is 35. Find the greatest number in these five numbers?
A.) 31
B.) 33
C.) 39
D.) 37

Answer: Option 'C'

Let the Consecutive odd numbers are x , x +2 , x + 4 , x+ 6, x+ 8.
Given , Average of fiveConsecutive odd numbers = 35
=> Average = (x + x + 2 + x + 4 + x + 6 + x + 8)/5 = 35
=> (5x + 20) / 5 = 35
=> 5x + 20 = 175
=> 5x = 175 - 20
=> 5x = 155
=> x = 31 ---> which is the first term of the given consecutive odd series.
The numbers are 31, 33, 35 and 37, 39
The greatest number is 39.

• 208. Average of five consecutive odd numbers is 35. Find the greatest number in these five numbers?
A.) 31
B.) 33
C.) 39
D.) 37

Answer: Option 'C'

Let the Consecutive odd numbers are x , x +2 , x + 4 , x+ 6, x+ 8.
Given , Average of fiveConsecutive odd numbers = 35
=> Average = (x + x + 2 + x + 4 + x + 6 + x + 8)/5 = 35
=> (5x + 20) / 5 = 35
=> 5x + 20 = 175
=> 5x = 175 - 20
=> 5x = 155
=> x = 31 ---> which is the first term of the given consecutive odd series.
The numbers are 31, 33, 35 and 37, 39
The greatest number is 39.

• 209. Find the average of the first 56 natural numbers
A.) 28.5
B.) 28
C.) 27.5
D.) 29

Answer: Option 'A'

Solution is
Average of the first n natural numbers = (n + 1) / 2
Average of the first 56 natural numbers = (56 + 1) / 2
= 57 / 2
= 28.5

• 210. Find the average of the first 56 natural numbers
A.) 28.5
B.) 28
C.) 27.5
D.) 29

Answer: Option 'A'

Solution is
Average of the first n natural numbers = (n + 1) / 2
Average of the first 56 natural numbers = (56 + 1) / 2
= 57 / 2
= 28.5

• 211. The average weight of a class having 25 students is 32 kg. Find the total weight of the class.
A.) 3200
B.) 1600
C.) 1225
D.) 800

Answer: Option 'D'

Solution is
Given, Average weight = 32 kg
No.of students = 25
Average = Total Quantity / No. of Quantity
=> Total Weight of the class = Average weight x No. of Students
= 32 x 25
= 800
Answer is 800

• 212. The average weight of a class having 25 students is 32 kg. Find the total weight of the class.
A.) 3200
B.) 1600
C.) 1225
D.) 800

Answer: Option 'D'

Solution is
Given, Average weight = 32 kg
No.of students = 25
Average = Total Quantity / No. of Quantity
=> Total Weight of the class = Average weight x No. of Students
= 32 x 25
= 800
Answer is 800

• 213. Find the average of the first 14 natural numbers
A.) 6.5
B.) 7.5
C.) 7
D.) 8

Answer: Option 'B'

Solution is :
Average of the first n natural numbers = ( n + 1 ) / 2
Average of the first 14 natural numbers = ( 14 + 1 ) / 2
= 15 / 2
= 7.5

• 214. Find the average of the first 14 natural numbers
A.) 6.5
B.) 7.5
C.) 7
D.) 8

Answer: Option 'B'

Solution is :
Average of the first n natural numbers = ( n + 1 ) / 2
Average of the first 14 natural numbers = ( 14 + 1 ) / 2
= 15 / 2
= 7.5

• 215. The average weight of a class having 16 students is 36 kg. Find the total weight of the class.
A.) 576
B.) 526
C.) 496
D.) 556

Answer: Option 'A'

Solution is :
Given, average weight = 36 kg
No. of students = 16
Average = Total Quantity / No. of Quantity
=> Total weight of the class = Average weight x No. of Students
= 36 × 16
= 576 kg

• 216. The average weight of a class having 16 students is 36 kg. Find the total weight of the class.
A.) 576
B.) 526
C.) 496
D.) 556

Answer: Option 'A'

Solution is :
Given, average weight = 36 kg
No. of students = 16
Average = Total Quantity / No. of Quantity
=> Total weight of the class = Average weight x No. of Students
= 36 × 16
= 576 kg

• 217. Find the average of the first 70 natural numbers ?
A.) 31.5
B.) 35.5
C.) 34.5
D.) 35

Answer: Option 'B'

Solution is :
Average of the first n natural numbers = ( n + 1 ) / 2
Average of the first 70 natural numbers = ( 70 + 1 ) / 2
= 71 / 2
= 35.5

• 218. Find the average of the first 70 natural numbers ?
A.) 31.5
B.) 35.5
C.) 34.5
D.) 35

Answer: Option 'B'

Solution is :
Average of the first n natural numbers = ( n + 1 ) / 2
Average of the first 70 natural numbers = ( 70 + 1 ) / 2
= 71 / 2
= 35.5

• 219. Find the average of first 26 multiples of 11.
A.) 148.5
B.) 149
C.) 148
D.) 149.5

Answer: Option 'A'

Average of first 26 natural numbers = ( n + 1 ) / 2
= ( 26 + 1 ) / 2
= 27 / 2
= 13.5
Average of first 26 multiples of 11 = ( Average of first 26 natural numbers ) × 11
= 13.5 × 11
148.5

• 220. Find the average of first 26 multiples of 11.
A.) 148.5
B.) 149
C.) 148
D.) 149.5

Answer: Option 'A'

Average of first 26 natural numbers = ( n + 1 ) / 2
= ( 26 + 1 ) / 2
= 27 / 2
= 13.5
Average of first 26 multiples of 11 = ( Average of first 26 natural numbers ) × 11
= 13.5 × 11
148.5

• 221. The average weight of a class having 14 students is 36 kg. Find the total weight of the class.
A.) 504
B.) 514
C.) 494
D.) 524

Answer: Option 'A'

Solution is :
Given, Average weight of the class = 36 kg
No. of students in the class = 14
Average = Total Quantity / No. of Quantity
=> Total weight of the class = Average weight x No. of students

= 36 × 14
= 504

• 222. The average weight of a class having 14 students is 36 kg. Find the total weight of the class.
A.) 504
B.) 514
C.) 494
D.) 524

Answer: Option 'A'

Solution is :
Given, Average weight of the class = 36 kg
No. of students in the class = 14
Average = Total Quantity / No. of Quantity
=> Total weight of the class = Average weight x No. of students

= 36 × 14
= 504

• 223. Find the average of first 17 multiples of 3
A.) 6.33
B.) 27
C.) 20
D.) 7.33

Answer: Option ''

Solution is
Given

Average of first 17 natural numbers= (n + 1 ) / 2
=(18 / 2 )
= 9
Average of first 17 multiples of 3 =(Average of first 17 natural numbers) x 3
= 9 x 3

• 224. Find the average of first 17 multiples of 3
A.) 6.33
B.) 27
C.) 20
D.) 7.33

Answer: Option ''

Solution is
Given

Average of first 17 natural numbers= (n + 1 ) / 2
=(18 / 2 )
= 9
Average of first 17 multiples of 3 =(Average of first 17 natural numbers) x 3
= 9 x 3

• 225. The average weight of a class having 14 students is 36 kg. Find the total weight of the class.
A.) 504
B.)  514
C.) 524
D.) 494

Answer: Option 'A'

Total quantity = Average x No. of Quantity
Total weight = Average weight x No.of students

= 36 x 14
= 504 kg