201.

Total Marks obtained by a class is 2695 and the average score of the class is 55. Find the Total students in the class?

**Answer: Option 'B'**

**Use the below formula to find the Total, when Average and Total No. of Students is provided Total no of students = Total Marks / Average Marks Total No. of students = ( 2695 / 55) = 49**

202.

There were 20 students in a particular Class. The class teacher knows the overall height of all the students in the class is 1300. Can you find the average height of students in the class?

**Answer: Option 'A'**

**Use the below formula to find the average height of students in the class Average Height = ( Total Height of all students in the Class / Total Number of Students) Average Height = ( 1300/20) = 65**

203.

Six years ago the average of a family of 4 members was 26 years. A child has been born, due to Which the average age of the family is 24 years today. What is present age of the child?

**Answer: Option 'C'**

**8 years**

204.

The age of father 10 years ago was thrice the age of his son. Ten years hence, father's age will be twice that of his son. The ratio of their present ages is:

**Answer: Option 'C'**

**Let the ages of father and son 10 years ago be 3x and x years respectively.
Then, (3x + 10) + 10 = 2[(x + 10) + 10] 3x + 20 = 2x + 40 x = 20.
Required ratio = (3x + 10) : (x + 10) = 70 : 30 = 7 : 3.**

205.

There were 17 students in a particular Class. The class teacher knows the overall height of all the students in the class is 1200. Can you find the average height of students in the class?

**Answer: Option 'B'**

**Use the below formula to find the average height of students in the class Average Height = ( Total Height of all students in the Class / Total Number of Students) Average Height = ( 1200/17) = 70.59**

206.

Find the average of the first 70 natural numbers

**Answer: Option 'C'**

**Solution is**

Average of n natural numbers = (**n + 1 ) / 2**

= ( 70 + 1 ) / 2

= 71 / 2

= **35.5**

**Answer is 35.5**

207.

In the first 10 overs of a cricket game, the run rate was only 8.2. What should be the run rate in the remaining 40 overs to reach the target of 106 runs?

**Answer: Option 'B'**

**Required Run rate = ( 106 - ( 8.2 x 10 ) )/ (40) = ( 24) /(40) = 0.6**

208.

In the first 30 overs of a cricket game, the run rate was only 1.9. What should be the run rate in the remaining 20 overs to reach the target of 98 runs?

**Answer: Option 'A'**

**Required Run rate = ( 98 - ( 1.9 x 30 ) )/ (20) = ( 41) /(20) = 2.05**

209.

The average weight of 8 persons increases by 1.5 kg when a person weighting 65 kg is replaced by a new person. What could be the weight of the new person?

**Answer: Option 'C'**

**Let the average weight of 8 persons be 'x' kg
and the weight of the new person be 'y' kg
so, (8x - 65 + y) / 8 = x+1.5 => y = 65 + 8 * 1.5 = 77 kgs
Weight of the new person = 77 kgs.**

210.

A particular student has scored an average marks of 69.25 in all his 20 subjects. Find the Total Score he has obtained in all his subjects?

**Answer: Option 'A'**

**Use the below formula to find the Total, when Average and Total No. of Students is provided Total
= Average * Total Students/People Total = Average x Total Number of Students) Average Weight = ( 69.25 x 20) = 1385**

211.

There were 17 students in a particular Class. The class teacher knows the overall height of all the students in the class is 1300. Can you find the average height of students in the class?

**Answer: Option 'D'**

**Use the below formula to find the average height of students in the class Average Height = ( Total Height of all students in the Class / Total Number of Students) Average Height = ( 1300/17) = 76.47**

212.

Total Marks obtained by a class is 1584 and the average score of the class is 72. Find the Total students in the class?

**Answer: Option 'C'**

**Use the below formula to find the Total, when Average and Total No. of Students is provided
Total no of students = Total Marks / Average Marks
Total No. of students
= ( 1584 / 72)
=**

213.

Total Marks obtained by a class is 1156 and the average score of the class is 68. Find the Total students in the class?

**Answer: Option 'B'**

**Use the below formula to find the Total, when Average and Total No. of Students is provided Total no of students = Total Marks / Average Marks Total No. of students = ( 1156 / 68) = 17**

214.

In a class of 18 students in an examination in science 1 student scored 100 marks, 2 get zero each and the average oh the rest was 45. What is the average of the whole class?

**Answer: Option 'B'**

**43**

215.

In the first 35 overs of a cricket game, the run rate was only 6.4. What should be the run rate in the remaining 15 overs to reach the target of 410 runs?

**Answer: Option 'A'**

**Required Run rate = ( 410 - ( 6.4 x 35 ) )/ (15)
= ( 186) /(15) = 12.4**

216.

Of three numbers, the third is twice the second and the second is 4 times the first. If their average is 78, the smallest of the three numbers is:

**Answer: Option 'D'**

**Let first number be x.
So,2nd no. = 4x & 3rd no.=8x.
So,x+4x+8x=78 × 3 = 234.
13x = 234
x = 234/13
Hence,smallest Number x=18.**

217.

The average weight of a class having 12 students is 30 kg. Find the total weight of the class.

**Answer: Option 'B'**

**Solution is
[ Total quantity = Average x No.of quantity ]**

= 12 x 30

=

Answer is 360

218.

Average of five consecutive even numbers is 35. Find the greatest number in these five numbers?

**Answer: Option 'C'**

**39**

219.

Physics Teacher knows the average score of 43 students in her subject is 49.5. Can you help the physics teacher to find the overall marks obtained by all the students in her subject?

**Answer: Option 'C'**

**Use the below formula to find the Total, when Average and Total No. of Students is provided Total = Average * Total Students/People Total = Average * Total Number of Students) Average Weight = ( 49.5 x 43) = 2128.5**

220.

There were 45 students in a hostel, if the numbers of students increased by 7, the expenses of the mess were increased by Rs. 39 per day while the average expenditure per head diminished by Re.1. What is the original expenditure of the mess (in Rs)?

**Answer: Option 'B'**

**Let the original expenditure be Rs.x
Original average expenditure = X/45
New average expenditure = (x+39)/52
So (x/45) - ((x+39) / 52) = 1 => (52x - 45x - 45 × 39) / (45 × 52) = 1 => (7x - 1755) / 2340 = 1 => 7x = 2340 + 1755 => 7x = 4095 so x = 585
so, original expenditure is Rs 585**

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