11.

Of the two square fields, the area of the one is 1 hectare, while anothe one is broader by 1%. There differences in area is:

**Answer: Option 'C'**

**Area of one square field = 10000 m ^{2}
10000 × 1 = 10000
Side of this field = √10000 m = 100 m
Side of another square = 101 m
Difference of areas = [ 101^{2} - 100^{2} ] m^{2}
[101+100][101-100] m^{2}
(201)(1) m^{2} = 201 m^{2}**

12.

Find the cost of carpenting a room 13 m long and 9 m broad with a carpet 100 Cm broad at the rate of Rs.20 per meter.

**Answer: Option 'A'**

**Area of the carper = Area of the room
= 13 × 9 => 117 m ^{2}
Breadth of the carpet = 100 cm = 1m
Length of carpet = Area/Breadth => 117/1 = 177 m.**

13.

A girl walking at the rate of 9 Km per hour crosses a square field diagonally in 12 seconds. The area of the field is:

**Answer: Option 'D'**

**Distance covered in (9×1000)/(3600) × 12 = 30 m
Diagonal of squarre field = 30 m.
area of square field = 302/2
= 900/2 = 450 Sq.m**

14.

The inner circumference of a circle race track 18 m wide is 880 m. Find the radius of the outer circle.

**Answer: Option 'C'**

**Let inner radius be r metres
Then 2πr = 640
2 × 22/7 r = 880
44/7 r = 880
r = 880 × 7/44 = 140 m**

15.

The perimeter of a square circumscribed about a ciecle of radius r is:

**Answer: Option 'D'**

**Each side of the square = 2r
Perimeter of the square = (4×2r) = 8r**

16.

The area of a square field is 4802 m2 the length of its diagonal is:

**Answer: Option 'C'**

**Let the diagonal be d metres,
Then 1/2 d ^{2} = 4802
d^{2} = 9604
d = √9604
d = 98 m**

17.

The diagonal of a rhombus are 65 m and 60 m. Its area is:

**Answer: Option ''**

**Area of the rhombus = 1/2 d1d2 = ( 1/2 × 65 × 60 ) cm ^{2}
= 65 × 30 = 1950 cm^{2}**

18.

The diagonal of a square is 40 m. The area of the square is:

**Answer: Option 'A'**

**Arear = 1/2 × ( diagonal ) ^{2}
= ( 1/2 × 40 × 40 )m^{2}
= 1600/2 = 800 m^{2}**

19.

The area of the largest triangle that can be inscribed in a semicircle pf rasius r Cm, is:

**Answer: Option 'C'**

**Area of the largest triangle = (1/2 × 2r × r) cm ^{2} = r^{2} cm^{2}**

20.

Find the area of the sector whose are is making an angle of 90° at the center of a circle of radius 3.2 Cm.

**Answer: Option 'D'**

**Area of the sector = 90/360 × πr ^{2}
= 90/360 × 22/7 × 3.2 × 3.2
= (11 × 10.24)/2 = 112.64/2 = 56.32 Sq.Cm**

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