16.

In a class 60% of students passed in telugu, 50% 0f students passde in english. Then if every student Passed in either telugu or english or both the subjects. Then what is the percentage of students passed In both the subjects?

**Answer: Option 'A'**

**passed in Telugu = 60 %
passed in English = 50 %
only passed in telugu = 50%
only passed in english = 40%
the percentage of studebts passed in both the subjects = 10 %**

17.

A mixture of 20 litres of milk and water contains 20% of water. The new mixture is formed by adding 5 lit of water. What is the percentage of milk in the new mixture?

**Answer: Option 'C'**

**(20 li = 4 li water 16 li milk
-------- 5 li water
Total = 9 li water 16 li milk (new)
16/25×100=64%**

18.

If 40% of a certain number is 120, then what is 90% of that number?

**Answer: Option 'D'**

**40% = 40 × 3 = 120
90% = 90 × 3 = 270**

19.

What percent is 70 of 280?

**Answer: Option 'A'**

**70/280 = 1/4
1/4 × 100 = 25 %**

20.

Express 3/4 as rate percent.

**Answer: Option 'C'**

**3/4 × 100 = 300/4 % = 75 %**

21.

If X,Y is 20%,30% smaller than Z then how much percentage is Y greater than X?

**Answer: Option 'C'**

**X = 80 %
Y = 70 %
Z = 100 %
X-Y/X × 100 = 10/80 × 100 = 12 1/2 % greater than X**

22.

The population of a town increases 10% and 20% respectively in two consecutive years. After the growth the present population of the town is 13200. Then what is the population of the town 2 years ago?

**Answer: Option 'C'**

**Formula :
( After =100 denominator
Ago = 100 numerator)
13200 × 100/110 × 100/120 = 10000 **

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23.

If A is 25% greater than B then how much percentage is B smaller than A?

**Answer: Option 'A'**

**A = 125
B = 100
A-B/A × 100 = 25/125 × 100 = 20 % smaller smaller than A**

24.

In an election between the two candidates ,The candidates who gets 60% of votes polled is winned by 280 votes majority. What is the total number of votes polled?

**Answer: Option 'B'**

**Note : majority (20 %) = difference in votes polled to win (60 %) & defeated candidates (40 %)
20 % = 60 % - 40 %
20% -----> 280 (20×14 = 280 )
100% -----> 1400 (100×14 = 1400)**

25.

If 20% of a certain number is 80, then what is 30% of that number?

**Answer: Option 'B'**

**20% = 20 × 4 = 80
30% = 30 × 4= 120**

26.

The population of a town is 8000. It decreases annually at the rate of 20% p.a. What will be its population after 2 years?

**Answer: Option 'B'**

**Formula :
( After =100 denominator
Ago = 100 numerator)
8000 × 80/100 × 80/100 = 5120**

#### Quantitative Aptitude Problems With Answers - Free Online Practice Test

- Quantitative Aptitude Problems With Answers All Chapters with multiple Examples
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27.

The population of a town is 8100. It decreases annually at the rate of 10% p.a. What was its population 2 years ago?

**Answer: Option 'C'**

**Formula :
( After =100 denominator
Ago = 100 numerator)
8100 × 100/90 × 100/90 = 10000**

28.

The Shopkeeper increased the price of a product by 25% so that customer finds it difficult to purchase the required amount. But somehow the customer managed to purchase only 70% of the required amount. What is the net difference in the expenditure on that product?

**Answer: Option 'C'**

**Quantity X Rate = Price
1 x 1 = 1
0.7 x 1.25 = 0.875
Decrease in price = (0.125/1) × 100 = 12.5%**

29.

Two employees X and Y are paid a total of Rs. 550 per week by their employer. If X is paid 120 percent of the sum paid to Y, how much is Y paid per week?

**Answer: Option 'C'**

**Let the amount paid to X per week = x
and the amount paid to Y per week = y
Then x + y = 550
But x = 120% of y = 120y/100 = 12y/10
∴12y/10 + y = 550
⇒ y[12/10 + 1] = 550
⇒ 22y/10 = 550
⇒ 22y = 5500
⇒ y = 5500/22 = 500/2 = Rs.250**

#### Quantitative Aptitude Problems With Answers - Free Online Practice Test

- Quantitative Aptitude Problems With Answers All Chapters with multiple Examples
- Latest model Quant Questions for SBI PO - Free online Practice Test 1
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30.

If 20% of a = b, then b% of 20 is the same as:

**Answer: Option 'C'**

**20% of a = b
=> b = 20/100a
b% of 20 = (b/100)20 = [(20/100a)/100]20
= (20 × 20 × a)/(100 × 100)
= 4a/100 = 4% of a**

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