1.
The population of a town is 8000. It decreases annually at the rate of 20% p.a. What will be its population after 2 years?
Answer: Option 'B'
Formula :
( After =100 denominator
Ago = 100 numerator)
8000 × 80/100 × 80/100 = 5120
2.
In an examination it is required to get 30% of minimum marks to pass. A student got 110 marks and was declared failed by 10 marks difference. Then what is total marks:?
Answer: Option 'A'
30 % -------> 120 ( 30 × 4 = 120)
100% -------> 400 (100 × 4 = 400)
3.
Ganesh scored 93% in his exams. If he scored 84 marks less than the maximum marks. Find the maximum marks
Answer: Option 'B'
He scored 7% less than the maximum marks.
7% of x = 84 x = 1200
4.
What percent is 36paisa's of 12 rupees?
Answer: Option 'A'
12 Rupees = 1200paisa's
36/1200 × 100 = 3/12
12/3 = 3 %
5.
Daal is now being sold at Rs. 20 a kg. Last month, is rate was Rs. 16 per kg. By how much percent should a family reduce its consumption so as to keep the expenditure fixed?
Answer: Option 'C'
Let a family's monthly consumption of daal be x kg.
To keep the expenditure fixed,
their consumption for this month should be 16x/20 = 4x/5.
Reduction in consumption = x/5 = 20% of x
6.
In an election between the two candidates ,The candidates who gets 60% of votes polled is winned by 280 votes majority. What is the total number of votes polled?
Answer: Option 'B'
Note : majority (20 %) = difference in votes polled to win (60 %) & defeated candidates (40 %)
20 % = 60 % - 40 %
20% -----> 280 (20×14 = 280 )
100% -----> 1400 (100×14 = 1400)
7.
In an elaction between two candidates, 20% of votes are were declares invalid. First candidate got 480 votes which were 60% of the total valid votes . The total number of votes enrolled in that election was:
Answer: Option 'B'
(100%-20%=80%
48%-32%=16%
16% = 16×30 = 480
100% =100×30 =3000 votes)
8.
The population of a town is 10000. It increases annually at the rate of 20% p.a. What will be its population after 2 years?
Answer: Option 'C'
Formula :
( After =100 denominator
Ago = 100 numerator)
10000 × 120/100 × 120/100 = 14400
9.
In an examination it is required to get 40% of minimum marks to pass. A student got 142 marks, Thus he got 22 marks more than minimum marks required to pass. What is total marks?
Answer: Option 'C'
40 % ------> 120 ( 40 × 3 = 120 )
100 % ------> 300 ( 100 × 3 = 300 )
10.
In a class 60% of students passed in telugu, 50% 0f students passde in english and 20% of students passed in both the subjects then what is the percentage the students who failed in the both the subjects?
Answer: Option 'B'
only t = 40,only e = 30 and both subjects passed 20%
10% failed in both subjects
11.
Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. The marks obtained by them are:
Answer: Option 'C'
Let their marks be (x + 9) and x.
Then, x + 9 = (56/100)(x+9+x)
25(x+9) = 14(2x + 9)
3x = 99
x = 33
So, their marks are 42 and 33.
12.
If 20% of a = b, then b% of 20 is the same as:
Answer: Option 'C'
20% of a = b
=> b = 20/100a
b% of 20 = (b/100)20 = [(20/100a)/100]20
= (20 × 20 × a)/(100 × 100)
= 4a/100 = 4% of a
13.
If X is 20% greater than Y, Z is 20% smaller than how much percent is X greater than Z?
Answer: Option 'B'
X = 120
Y = 100
Z = 80
X-Z/Z × 100 = 40/80 × 100 = 50 % greater than Z
14.
Out of the first 75 natural numbers, what percentage of them have 7 either in the units place or the tens place?
Answer: Option 'B'
There are 13 numbers.
(7, 17, 27, 37, 47, 57, 67, 70, 71, 72, 73, 74, 75) * 100 = 17.33%
15.
In an elaction between two candidates, 10% of votes are were declares invalid. First candidate got 1800 votes which were 60% of the total valid votes . The total number of votes enrolled in that election was:
Answer: Option 'C'
100 % - 10 % = 90 %
54%-36%=18%
18% ------> 1800 ( 18 × 100 = 1800)
100% -------> 10000 votes (100 × 100 = 10000)
16.
In an election between two candidates first candidate got 60% of votes polled and second Candidate got 280 votes. The total number of votes polled was?
Answer: Option 'A'
Total = 100 %,
First person got 60%
second person got remaining 40 % of votes.
than 40 % = 280
40% = 40×7 = 280
100% =100×7 =700votes
17.
The population of a town increases 10% and 20% respectively in two consecutive years. After the growth the present population of the town is 13200. Then what is the population of the town 2 years ago?
Answer: Option 'C'
Formula :
( After =100 denominator
Ago = 100 numerator)
13200 × 100/110 × 100/120 = 10000
18.
What percent is 5 gm of 1 kg?
Answer: Option 'B'
1 kg = 1000 gm
5/1000 × 100 = 500/1000
=1/2 = 0.5 %
19.
A number increased by 20% gives 480. The number is
Answer: Option 'C'
Formula = TOTAL=100% ,INCRESE = "+" DECREASE= "-"
A number means = 100 %
That same number increased by 20 % = 120 %
120 % -------> 480 (120 × 4 = 480)
100 % -------> 400 (100 × 4 = 400)
20.
When a number is first increased by 10% and then reduced by 10%, The number is:
Answer: Option 'B'
Farmula = AFTER INCREASED 10% × AFTER REDUCED 10%/TOTAL 100%
= 110 × 90/100 = 99 %
= Decreases by 1%