Basic Computer Knowledge 10000 + Questions and Answers

RRB Group D - ALP 2018 Maths & Reasoning Free Mock Test

Percentage : Aptitude Test

  • 6. What percent is 120 of 90? 
A.) 132 1/3%
B.) 132 2/3%
C.) 133 1/3%
D.) None of these

Answer: Option 'C'

120/90 = 4/3 
4/3 × 100 = 400/3 = 133 1/3 %

  • 7. What percent is 5 gm of 1 kg? 
A.) 0.05%
B.) 0.5%
C.) 0.005%
D.) None of these

Answer: Option 'B'

1 kg = 1000 gm 
5/1000 × 100 = 500/1000
=1/2 = 0.5 %

  • 8. What percent is 36paisa's of 12 rupees? 
A.) 3%
B.) 0.03%
C.) 0.03%
D.) None of these

Answer: Option 'A'

12 Rupees = 1200paisa's 
36/1200 × 100 = 3/12 
12/3 = 3 %

  • 9. A number increased by 20% gives 480. The number is 
A.) 380
B.) 420
C.) 400
D.) 300

Answer: Option 'C'

Formula = TOTAL=100% ,INCRESE = "+" DECREASE= "-" 
A number means = 100 % 
That same number increased by 20 % = 120 % 
120 % -------> 480 (120 × 4 = 480) 
100 % -------> 400 (100 × 4 = 400)

  • 10. Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. What are the marks obtained by them? 
A.) 42, 33
B.) 44, 36
C.) 43, 36
D.) 42, 36

Answer: Option 'A'

Let the marks secured by them be x and (x + 9)
Then sum of their marks = x + (x + 9) = 2x + 9
Given that (x + 9) was 56% of the sum of their marks
=>(x+9) = 56/100(2x+9)
=>(x+9) = 14/25(2x+9)
=> 25x + 225 = 28x + 126
=> 3x = 99
=> x = 33
Then (x + 9) = 33 + 9 = 42
Hence their marks are 33 and 42

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