21.

Find the principle, interest on Rs.900/- at 6% p.a. for 3 years?

**Answer: Option 'A'**

**P = ?
T = 3 years
R = 6%
I = Rs.900/-
I = PTR/100
P = 100I/TR
P = (100 × 900)/(3 × 6)
P = Rs.5000/- **

22.

In how many years will sum of Rs 4000 yield an interest of Rs.1080/- at 9% p.a?

**Answer: Option 'B'**

**P = Rs.4000/-
T = ?
R = 9%
I = Rs.1080/-
I = PTR/100
T = I × 100/PR
T = (1080 × 100)/(400 × 9)
T = 3 years **

23.

In how many years will sum of Rs.6000/- yield an interest of Rs.1200/- at 8% p.a?

**Answer: Option 'A'**

**P = Rs.6000/-
T = ?
R = 8%
I = Rs.1200/-
I = PTR/100
T = (I × 100)/PR
T = (1200 × 100)/(6000 × 8)
T = 5/2 ==> 2 1/2 years **

24.

At what rate of percent per annum will a sum of money double in 8 years?

**Answer: Option 'B'**

**Let principal be Rs P. Then, S.I = Rs P and Time = 8 years>
Rate = (100 × S.I)/(P × T) = (100 × P/P × 8)% p.a
= 25/2 % p.a = 12.5% p.a **

25.

Simple interest on a certain sum 16/25 of the sum. if both the rate of interest and time are same. then what is the rate of interest?

**Answer: Option 'C'**

**Let the principal be Rs x. Then, S.I = Rs(16x/25)
Let, rate = R% p.a
and time = R yearss. Then,
S.I = (P×T×R)/100 ==>16X/25
= x×R×R/100 ==> R×R = 64 = 8
Hence,rate = 8% p.a and time = 8 years **

26.

If the simple interest on Rs. 1120 for 2 years is Rs.8000/-, what is the rate of interest percent per annum?

**Answer: Option 'B'**

**I = Rs.1120/-
T = 2 years
P = Rs.8000/-
R = ?
S.I = (P×T×R/100)
R = (S.I×100)/(P×T)
R = (1120×100)/(8000×2)
R = 56/8 = 7% **

27.

If the simple interest on Rs.400 for 3 years is Rs.4000/-, what is the rate of interest percent per annum?

**Answer: Option 'C'**

**I = Rs.400/-
T = 3 years
P = Rs.4000/-
R = ?
S.I = (P×T×R/100)
R = (S.I×100)/(P×T)
R = (400×100)/(4000×3)
R = 10/3 = 3 1/3% **

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