RRB NTPC - Time and Distance :(25) MCQs with Answers

1.

A motorist travels for 6 hours, the first half at 60 Kmph and the rest at 48 Kmph. Find the distance Traveled by him.

A.) 324 Km
B.) 320 Km
C.) 300 Km
D.) 340 Km

Distance = 3 × 60 + 3 × 48
= 180 + 144
= 324 Km

2.

A train 110 m long is running with speed of 60 km/hr .In what time will it pass a man who is running at 6 km/hr in the direction opposite to that in which the train is going?

A.) 10 sec
B.) 5 sec
C.) 6 sec
D.) 7 sec

Relative speed = Train speed + Man Speed = 60 + 6 = 66 kmph = 18 1/3 m /sec
Distance to be covered = 110 meter
Time taken = Speed / Distance = 110 / (18 1/3) = (110 / 55) x 3 = 2 x 3 = 6 sec

3.

How many seconds will a 500 m long train take to cross a man walking with a speed of 3 km/hr in the direction of the moving train if the speed of the train is 63 km/hr?

A.) 30
B.) 25
C.) 40
D.) 45

Given, Length of the train = 500 m
Speed of the man = 3 km/hr
Speed of the train = 63 km/hr
Time taken by the train to cross a man = Length of the train / (speed of the train – speed of the man)
=> Time = 500 m / (63 – 3) km/hr
=> Time = 500 m / 60 km/hr
(to convert 60 km/hr to m/sec)
=> Time = 500 m / [60 × (5/18) m/sec]
=> Time = {500 / [60 × (5/18)]} sec
=> Time = {(500 × 18) / (60 * 5)} sec
=> Time = 30 sec

4.

A train moves past a telegraph post and a bridge 264 m long in 8 seconds and 20 seconds respectively. What is the speed of the train?

A.) 76 km/hr
B.) 79.2 km/hr
C.) 69.5 km/hr
D.) 68.5 km/hr

79.2 km/hr

5.

A train 360 m long is running at a speed of 45 km/hr. In what time will it pass a bridge 140 m long?

A.) 40 seconds
B.) 45 seconds
C.) 42 seconds
D.) 48 seconds

Given, Length of train =360 m
Length of bridge =140 m
Speed of train = 45 km/hr ---> Converting into meter/ second
= 45 × (5/18) m / sec
= 12.5 m/sec
=>Speed of train = 12.5 m/sec
Required Time =(Length of train +Length of bridge) /Speed of train
= (360 + 140) / 12.5
= 500 / 12.5
= 40 sec
=>Required Time =40 sec

6.

A train covers a distance of 12 km in 10 minutes .If it takes 6 seconds to pass a telegraph post,then the length of the train is:

A.) 120 m
B.) 140 m
C.) 200 m
D.) 100 m

120 m

7.

A train running at the speed of 60 km/hr crosses a pole in 9 seconds .What is the length of the train?

A.) 120 m
B.) 324 m
C.) 150 m
D.) 200 m

150 m

8.

A train 800 m long is running at a speed of 78 km/hr. If it crosses a tunnel in 1 minute, then the length of the tunnel is:

A.) 540 m
B.) 500 m
C.) 450 m
D.) 350 m

Given, Length of the train = 800 m
Speed of the train = 78 km/hr (convert km/hr to m/sec)
= 78 × (5/18) m /sec
= 21.667 m /sec
=> Speed of the train = 21.667 m /sec
Time taken by the train to cross the tunnel = 1 min = 60 sec

To find the length of the tunnel:
Time taken by train to cross tunnel = (Length of tunnel + Length of train) / speed of the train
=> 60 = (Length of tunnel + 800) / 21.667
=> 60 × 21.667 = Length of tunnel + 800
=> 1300 = Length of tunnel + 800
=> 1300 – 800 = Length of tunnel
=> 500 = Length of tunnel
Thus, the Length of tunnel = 500 m

9.

The length of the bridge , which a train 130 m long and travelling at 45 km/hr can cross in 30 seconds, is:

A.) 200 m
B.) 225 m
C.) 245 m
D.) 250 m

​245 m

10.

A train 240 m long passed a pole in 24 seconds .How long will it take to pass a platform 650 m long?

A.) 89 sec
B.) 99 sec
C.) 109 sec
D.) 59 sec

89 sec

11.

A train speeds past pole in 15 seconds and a platform 100 m long in 25 seconds ,its length is:

A.) 150 m
B.) 100 m
C.) 200 m
D.) 50 m

150 m

12.

A train passes a station platform in 36 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr ,what is the length of the platform?

A.) 260 m
B.) 240 m
C.) 280 m
D.) 320 m

Given, time taken by train to pass the man = 20 sec
Speed of the train = 54 km/hr
---> Converting into meter/sec
=> Speed of train =54 × (5/18) m/sec = 15 m/sec
W.K.T: Speed of train = Length of train/ Time taken by train to pass the man
=> 15 =Length of train / 20
=>Length of train = 15 × 20
=>Length of train = 300 metre.
Given,A train passes a station platform in 36 seconds.
=>Speed of train = (Length of train + Length of platform) / Time taken by train to pass the platform
=> 15 = (300 +Length of platform) / 36
=> 15 × 36 = (300+Length of platform)
=> 540 =300+Length of platform
=> 540 - 300 =Length of platform
Thus,Length of platform = 240 meter.

13.

A goods train runs at the speed of 72 km/hr and crosses a 250 m long platform in 26 seconds .What is the length of the goods train?

A.) 270 m
B.) 250 m
C.) 230 m
D.) 130 m

270 m

14.

How much time does a train 110 metres long running at the speed of 72 km/hr take to cross a bridge 132 metres in length?

A.) 12.42 seconds
B.) 13.1 seconds
C.) 12.1 seconds
D.) 15.1 seconds

Given, Length of train = 110 meter
Speed of train = 72 km/hr
Length of bridge = 132 metre
---> Converting Speed from km/hr into m/sec
=>Speed of train = 72 × (5/18) m/sec
= 4 × 5
20 m/sec
Formula:-Time taken by train to cross the bridge = (Length of the train + Length of the bridge) /Speed of train
= (110 + 132) / 20
= 242/ 20
= 12.1 sec
Thus,Time taken by train to cross the bridge =12.1 seconds

15.

A train 100 m long is running at the speed of 30 km/hr.Find the time taken by it to pass a man standing near the railway line:

A.) 12 sec
B.) 8 sec
C.) 14 sec
D.) 16 sec

12 sec

16.

A person drove a certain distance by car at the speed of 35 km/h and returned on cycle at the speed of 10 km/h, if the whole journey took 18 hours. Then what total distance covered by the person?

A.) 80 km
B.) 120 km
C.) 140 km
D.) 150 km

Let the distance be x km
Time taken by car = x/35 and time taken on cycle = x/10
x/10 + x/35 = 18
x = 140 km

17.

A 320 meter long train moving with an average speed of 120 km/hr crosses a platform in 24 seconds. A man crosses the same platform in 4 minutes. What is the speed of man in meter/second?

A.) 2.4 mps
B.) 1.5 mps
C.) 1.6 mps
D.) 2 mps

Let the length of the platform be x meters, Then,
Speed of train = 120 km/h = 120 x 5/18 = 100/3 mps
320 + x = 100 x 24/3,
x = 800 - 320 = 480m
Required speed of man = 480/(4x60) = 2 mps

18.

Mohit traveled 20% of the time walking at a speed of 10 km/hr, 50% of the time in a bus at 40 km/hr and rest of the journey in a cab at 50 km/hr. What is the average speed of Mohit over the entire journey?

A.) 37 km/hr
B.) 25.97 km/hr
C.) 42 km/hr
D.) 40 km/hr

Let the total time Mohit takes to complete the entire journey be t hours
Mohit spent 20%, 50% and the remaining 30% of the time walking in the bus and in the cab respectively.
Thus, time spent walking, in the bus and in the cab are 0.2 t, 0.5 t and 0.3 t respectively.
So Average speed = Total distance covered/Total Time taken = 10(0.2 t0 + 40(0.5 t) + 50(0.3 t)/t = 37 km/hr

19.

Train A crosses a pole in 20 seconds and Train B crosses the same pole in one minute. The length of Train A is half of the length of Train B. what is the ratio of the speed of Train A to that of Train B?

A.) 3 : 2
B.) 3 : 4
C.) 4 : 3
D.) 3 : 1

Let the length of Train B be 2x and that of Train A be X.
Speed of Train A = x/20
Speed of Train B = 2x/60 = x/30
Ratio = Speed A/Speed B = X × 30/X * 20 = 3/2

20.

The ratio of the speed of a car, a train and a bus is 5 : 9 : 4. The average speed of the car, the bus and the train is 72 km/hr together. What is the average speed of the car and the train together?

A.) 82 km/hr
B.) 78 km/hr
C.) 84 km/hr
D.) 76 km/hr