RRB NTPC - Time and Distance :(25) MCQs with Answers

21.

A train speeds past pole in 15 seconds and a platform 100 m long in 25 seconds ,its length is:

   A.) 150 m
   B.) 100 m
   C.) 200 m
   D.) 50 m

Answer: Option 'A'

150 m

22.

A train passes a station platform in 36 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr ,what is the length of the platform? 

   A.) 260 m
   B.) 240 m
   C.) 280 m
   D.) 320 m

Answer: Option 'B'

Given, time taken by train to pass the man = 20 sec
Speed of the train = 54 km/hr
---> Converting into meter/sec
=> Speed of train =54 × (5/18) m/sec = 15 m/sec
W.K.T: Speed of train = Length of train/ Time taken by train to pass the man
=> 15 =Length of train / 20
=>Length of train = 15 × 20
=>Length of train = 300 metre.
Given,A train passes a station platform in 36 seconds.
=>Speed of train = (Length of train + Length of platform) / Time taken by train to pass the platform
=> 15 = (300 +Length of platform) / 36
=> 15 × 36 = (300+Length of platform)
=> 540 =300+Length of platform
=> 540 - 300 =Length of platform
Thus,Length of platform = 240 meter.

23.

A goods train runs at the speed of 72 km/hr and crosses a 250 m long platform in 26 seconds .What is the length of the goods train?

   A.) 270 m
   B.) 250 m
   C.) 230 m
   D.) 130 m

Answer: Option 'A'

270 m

24.

How much time does a train 110 metres long running at the speed of 72 km/hr take to cross a bridge 132 metres in length?

   A.) 12.42 seconds
   B.) 13.1 seconds
   C.) 12.1 seconds
   D.) 15.1 seconds

Answer: Option 'C'

Given, Length of train = 110 meter
Speed of train = 72 km/hr
Length of bridge = 132 metre
---> Converting Speed from km/hr into m/sec
=>Speed of train = 72 × (5/18) m/sec
= 4 × 5
20 m/sec
Formula:-Time taken by train to cross the bridge = (Length of the train + Length of the bridge) /Speed of train
= (110 + 132) / 20
= 242/ 20
= 12.1 sec
Thus,Time taken by train to cross the bridge =12.1 seconds

25.

A train 100 m long is running at the speed of 30 km/hr.Find the time taken by it to pass a man standing near the railway line:

   A.) 12 sec
   B.) 8 sec
   C.) 14 sec
   D.) 16 sec

Answer: Option 'A'

12 sec

26.

A person drove a certain distance by car at the speed of 35 km/h and returned on cycle at the speed of 10 km/h, if the whole journey took 18 hours. Then what total distance covered by the person?

   A.) 80 km
   B.) 120 km
   C.) 140 km
   D.) 150 km

Answer: Option 'C'

Let the distance be x km
Time taken by car = x/35 and time taken on cycle = x/10
x/10 + x/35 = 18
x = 140 km

27.

A 320 meter long train moving with an average speed of 120 km/hr crosses a platform in 24 seconds. A man crosses the same platform in 4 minutes. What is the speed of man in meter/second?

   A.) 2.4 mps
   B.) 1.5 mps
   C.) 1.6 mps
   D.) 2 mps

Answer: Option 'D'

Let the length of the platform be x meters, Then, 
Speed of train = 120 km/h = 120 x 5/18 = 100/3 mps
320 + x = 100 x 24/3,
x = 800 - 320 = 480m
Required speed of man = 480/(4x60) = 2 mps

28.

Mohit traveled 20% of the time walking at a speed of 10 km/hr, 50% of the time in a bus at 40 km/hr and rest of the journey in a cab at 50 km/hr. What is the average speed of Mohit over the entire journey?

   A.) 37 km/hr
   B.) 25.97 km/hr
   C.) 42 km/hr
   D.) 40 km/hr

Answer: Option 'A'

Let the total time Mohit takes to complete the entire journey be t hours 
Mohit spent 20%, 50% and the remaining 30% of the time walking in the bus and in the cab respectively.
Thus, time spent walking, in the bus and in the cab are 0.2 t, 0.5 t and 0.3 t respectively.
So Average speed = Total distance covered/Total Time taken = 10(0.2 t0 + 40(0.5 t) + 50(0.3 t)/t = 37 km/hr

29.

Train A crosses a pole in 20 seconds and Train B crosses the same pole in one minute. The length of Train A is half of the length of Train B. what is the ratio of the speed of Train A to that of Train B?

   A.) 3 : 2
   B.) 3 : 4
   C.) 4 : 3
   D.) 3 : 1

Answer: Option 'A'

Let the length of Train B be 2x and that of Train A be X.
Speed of Train A = x/20
Speed of Train B = 2x/60 = x/30 
Ratio = Speed A/Speed B = X × 30/X * 20 = 3/2

30.

The ratio of the speed of a car, a train and a bus is 5 : 9 : 4. The average speed of the car, the bus and the train is 72 km/hr together. What is the average speed of the car and the train together?

   A.) 82 km/hr
   B.) 78 km/hr
   C.) 84 km/hr
   D.) 76 km/hr

Answer: Option 'C'

Total speed of car, train, bus = 72 x 3 = 216 km/hr
Total speed of car and train = (216 x 14)/18 = 168 km/hr
Average speed of car and train = 168/2 = 84 km/hr

31.

A train of length 200 m can cross a man, sitting inside another train of length 100 m coming from opposite direction at speed of 25 m/sec, in 5 seconds. Find the speed of first train?

   A.) 40 m/sec
   B.) 20 m/sec
   C.) 10 m/sec
   D.) 35 m/sec

Answer: Option 'D'

Time taken by the train to cross the man = 300/(x+25) = 5 or 'x' = 35 m/sec

32.

A 280 – meter – long train moving with an average speed of 108 km/h crosses a platform in 12 seconds. A man crosses the same platform in 10 seconds. What is the speed of the man?

   A.) 5 m/s
   B.) 8 m/s
   C.) 12 m/s
   D.) cannot be determined

Answer: Option 'B'

Speed of thain = 108 km/hr = (108 x 5)/18 m/sec 30 m/sec
If the length of the platform be x meters, then
x + 280/12 = 30 
x + 280 = 360 
x = 3 = (360 - 280) = 80m
speed of man = 80/10 = 8m/sec

33.

A bus started its journey from Ramgarh and reached Devgarh in 44 minutes at its average speed of 50 km/hr. If the average speed of the bus is increased by 5km/hour, how much time will it take to cover the same distance?

   A.) 40 minutes
   B.) 38 minutes
   C.) 36 minutes
   D.) 31 minutes

Answer: Option 'A'

Distance = (44/60) x 50 = (x/60) x 55 
x = 40 minutes

34.

The average speed of a train is 1(3⁄7) the average speed of a car. The car covers a distance of 588 km in 6 hours. How much distance will the train cover in 13 hours?

   A.) 1750km
   B.) 1760km
   C.) 1720km
   D.) 1820 km

Answer: Option 'D'

Speed of the car = 588/6 = 98 km/hr 
Speed of train = (10/7) x 98 = 140 km/hr
Distance covered by the train in 13 hours = 140 x 13 = 1820 km
 

35.

The 200-metre train crosses a platform double its length in 36seconds. What is the speed of the train in km/hr?

   A.) 60
   B.) 48
   C.) 64
   D.) 66

Answer: Option 'A'

Speed of the train = (200 + 400)m/36 sec = 600/36 m/sec
= (600*18)/(36*5) km/h 
= 60 km/h


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