Percentage Problems for SSC CGL

1.

The population of a twon increased each year by 3% of its total at the beginning of the year. If the population on 1st january 2007 was 600000, what it on 1st January 2010?

   A.) 653636
   B.) 655636
   C.) 455636
   D.) 659836

Answer: Option 'B'

Population 1st January 2007 = 60000
Time span = 2010 - 2007 = 3 years
Increase rate = 3%
Population after 3 years
= Population in beginning x [(1 + (increasing rate)/100]time span
= 600000(1 + (3/100))3
= 600000 x (1.03)3
= 600000 x 1.092727 = 655636.2 = 655636

2.

88% of 370 + 24% of 210 - x = 118

   A.) 150
   B.) 250
   C.) 158
   D.) 258

Answer: Option 'D'

258

3.

In expressing a length of 81.472 km as nearly as possible with the three significant digits, find the percentage error

   A.) 0.35%
   B.) 0.34%
   C.) 0.034%
   D.) 0.035%

Answer: Option 'C'

Error = (81.5 - 81.472) = 0.028
Required percentage = (0.028/81.472) x 100 = 0.034%

4.

If the radius of a circle is increased by 50%, its area is increased by

   A.) 125%
   B.) 105%
   C.) 100%
   D.) 163%

Answer: Option 'A'

125%

5.

A batsman scored 120 runs which included 3 boundaries and 8 sixes. What percent of his total score did he make by running between the wickets.

   A.) 40%
   B.) 50%
   C.) 60%
   D.) 70%

Answer: Option 'B'

Number of runs made by running = 110 - (3 x 4 + 8 x 6)
= 120 - (60)
= 60
Now, we need to calculate 60 is what percent of 120.
=> 60/120 × 100 = 50 %

6.

One fourth of one third of two fifth of a number is 15. What will be40% of that number

   A.) 140
   B.) 160
   C.) 180
   D.) 190

Answer: Option 'C'

(1/4) × (1/3) × (2/5) × x = 15 then x = 15 × 30 = 450 
40% of 450 = 180

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