# Averages Problems for SSC CGL

1.

Of the three numbers whose average is 45, the first is half of the sum of the others. The first number is:

A.) 45
B.) 51
C.) 59
D.) 49

45

2.

Total Marks obtained by a class is 1564 and the average score of the class is 68. Find the Total students in the class?

A.) 21
B.) 22
C.) 23
D.) 24

Use the below formula to find the Total,
when Average and Total No. of Students is provided
Total no of students = Total Marks / Average Marks
Total No. of students = ( 1564 / 68) = 23.

3.

The average of 5 consecutive numbers is n. if the next two number are also included. The average will?

A.) Remain the same
B.) Increase by 1
C.) Increase by 2
D.) Decrease by 1

Increase by 1

4.

Out of 12 employs of a bank, one employ retires and his place, a new employ of age 24 years joins as a result average age of employs reduces by 4 years. The age of the retired employ is:

A.) 72
B.) 62
C.) 64
D.) 71

72

5.

Total Marks obtained by a class is 1564 and the average score of the class is 68. Find the Total students in the class?

A.) 21
B.) 22
C.) 23
D.) 24

Use the below formula to find the Total,
when Average and Total No. of Students is provided
Total no of students = Total Marks / Average Marks
Total No. of students = ( 1564 / 68) = 23.

6.

The average temperature for Monday, Tuesday and Wednesday is 36.30 C. The average temperature for Tuesday, Wednesday and Thursday is 36.70 C. If Monday's temperature recorded as 390 C, find the Thursday's temperature ?

A.) 40.2º C
B.) 40.4º C
C.) 40.5º C
D.) 41.2º C

Mon + Tue + Wed Temperature = 3X36.3 = 108.9
Given, Monday's temperature = 39º C
=> Tue + wed Temperature = 108.9 - 39 = 69.9
Given, Tue + wed + Thu temperature = 3 X 36.7 = 110.1
So, Thursday's temperature = 110.1 - 69.9 = 40.2º C

7.

The average of 26 numbers is zero. Of them, at the most how many may be greater than zero?

A.) 25
B.) 27
C.) 24
D.) 13

Average of 26 numbers is = 0 Therefore sum of all 26 numbers = 0
It is quite possible that 25 of these numbers may be positive and if their sum is "a" then 26th number is "(-a)"

8.

The average age of a group of 10 students was 18. The average age increased by 1 year when two new students joined the group. What is the average age of the two new students who joined the group?

A.) 23
B.) 24.5
C.) 24
D.) 26

The average age of a group of 10 students is 18.
Therefore, the sum of the ages of all 10 of them = 10 × 18 = 180
When two students joins the group, the average increase by 1. New Average = 19
Now there are 12 students Therefore, sum of all the ages of 12 students = (12 X 19 ) = 228
Therefore, the sum of the ages of two students who joined = 228 - 180 = 48
And the average age of these two students = 24

9.

The average age of a group of 10 students was 24. The average age increased by 1 years when two new students joined the group. What is the average age of the two new students who joined the group?

A.) 30
B.) 31.5
C.) 30.5
D.) 31

The average age of a group of 10 students is 24.
Therefore, the sum of the ages of all 10 of them = 10 × 24 = 240
When two students joins the group, the average increase by 1. New Average = 25
Now there are 12 students
Therefore, sum of all the ages of 12 students = ( 12 X 25 ) = 300
Therefore, the sum of the ages of two students who joined = 300 - 240 = 60
And the average age of these two students = 30

10.

In a class of 27, the overall weight of the students is 997. Can you find the average weight of students in the class?

A.) 36.93
B.) 38.78
C.) 40.62
D.) 35.08