# Percentage Problems for SSC CGL

1.

In expressing a length of 81.472 km as nearly as possible with the three significant digits, find the percentage error

A.) 0.35%
B.) 0.34%
C.) 0.034%
D.) 0.035%

Error = (81.5 - 81.472) = 0.028
Required percentage = (0.028/81.472) x 100 = 0.034%

2.

The number of 20% more than 80 is

A.) 90
B.) 96
C.) 40
D.) 46

20% of 80 = (20/100) × 80 = 16
20% more than 80 = 80 + 16 = 96

3.

The population of a twon increased each year by 3% of its total at the beginning of the year. If the population on 1st january 2007 was 600000, what it on 1st January 2010?

A.) 653636
B.) 655636
C.) 455636
D.) 659836

Population 1st January 2007 = 60000
Time span = 2010 - 2007 = 3 years
Increase rate = 3%
Population after 3 years
= Population in beginning x [(1 + (increasing rate)/100]time span
= 600000(1 + (3/100))3
= 600000 x (1.03)3
= 600000 x 1.092727 = 655636.2 = 655636

4.

88% of 370 + 24% of 210 - x = 118

A.) 150
B.) 250
C.) 158
D.) 258

258

5.

A batsman scored 120 runs which included 3 boundaries and 8 sixes. What percent of his total score did he make by running between the wickets.

A.) 40%
B.) 50%
C.) 60%
D.) 70%

Number of runs made by running = 110 - (3 x 4 + 8 x 6)
= 120 - (60)
= 60
Now, we need to calculate 60 is what percent of 120.
=> 60/120 × 100 = 50 %

6.

Three candidates contested an election and received 1136, 7636 and 11628 votes respectively. What percentage of the total votes did the winning candidate got

A.) 55%
B.) 56%
C.) 57%
D.) 58%

Total number of votes polled = (1136 + 7636 + 11628) = 20400
So, Required percentage = 11628/20400 * 100 = 57%

7.

One fourth of one third of two fifth of a number is 15. What will be40% of that number

A.) 140
B.) 160
C.) 180
D.) 190

(1/4) × (1/3) × (2/5) × x = 15 then x = 15 × 30 = 450
40% of 450 = 180

8.

If the radius of a circle is increased by 50%, its area is increased by

A.) 125%
B.) 105%
C.) 100%
D.) 163%

125%

9.

Total number of boys and girls in a school is 150. If the number of boys is x, then girls become x% of the total number of students. The number of boys is

A.) 50
B.) 60
C.) 70
D.) 80

x% of 150 = 150 - x [as x is number of boys]
=> x + (x/100) × 150 = 150
=> (5/2)x = 150
=> x = 60

10.

Half of 1 percent written as decimal is

A.) 5
B.) 0.5
C.) 0.05
D.) 0.005

It will be 1/2(1%) = 1/2(1/100) = 1/200 = 0.005

11.

What will be the fraction of 4%

A.) 1/20
B.) 1/50
C.) 1/75
D.) 1/25