1.
853 + ? ÷ 17 = 1000
Answer: Option 'A'
853 + ?/17 = 1000
?/17 = 1000 – 853 = 147
? = 17 × 147 = 2499
2.
65% of 400 + √? = 44% of 800 – 12% of 400
Answer: Option 'A'
65% of 400 + √? = 44% of 800 – 12% of 400
65% of 400 + √? = 44% of 800 – 12% of 400
⇒ (50% of 400 + 10% of 400 + 5% of 400) + √? = (50% of 800 – 6% of 800) – 12% of 400
⇒ (200 + 40 + 20) + √? = (400 – 48) – 48
or, √? = 352 – 48 – 260 = 44
∴ ? = (44)2 = 1936.65% of 400 + √? = 44% of 800 – 12% of 400
⇒ (50% of 400 + 10% of 400 + 5% of 400) + √? = (50% of 800 – 6% of 800) – 12% of 400
⇒ (200 + 40 + 20) + √? = (400 – 48) – 48
or, √? = 352 – 48 – 260 = 44
∴ ? = (44)2 = 1936.
3.
(14896 ÷ 19) ÷ 16 = ?
Answer: Option 'C'
(14896 ÷ 19) ÷ 16 = ?
⇒ ? = 14896/19 ÷ 16
⇒ ? = 14896/19 ÷ 16 ⇒ 784/16 = 49
4.
6156 ÷ √? × 53 = 4028
Answer: Option 'B'
6153 × 53/√? = 4028
⇒ √? = 80.96 ≈ 81
⇒ ? = 6561
5.
8195 ÷ 745 + ? × 12 = 7847
Answer: Option 'B'
8195 ÷ 745 + ? × 12 = 7847
or, ? × 12 = 7847 – 8195/745 = 7847 – 11
or, ? × 12 = 7836
∴ ? = 653.
6.
98643 – 21748 = 51212 + ?
Answer: Option 'A'
Given eqn,
98643 – 21748 = 51212 + ?
⇒ ? = 98643 – 21748 – 51212
⇒ ? = 25683
7.
A contractor pays Rs. 20 to a worker for each day and the worker forfeits Rs. 10 for each day if he is idle. At the end of 60 days, the worker gets Rs. 300. Find for how many days the worker was idle?
Answer: Option 'B'
Step 1: Number of days worked by the worker = 60 and he remained idle for x days. Therefore, number of days worked = (60 – x)
Step 2: Each day he was getting paid Rs. 20. Therefore, the payment received for working days = (60 – x) 20
Step 3: After subtracting the amount which he forfeited, he receives Rs. 300.
Therefore,
(60 – x) 20 – 10x = 300
1200 – 20x – 10x = 300
900 = 30x
x = 30 days
8.
70% of 1680 + ?% of 1750 = 55% of 2820 – 886
Answer: Option 'A'
70% of 1680 + ?% of 1750 = 55% of 2820 – 886
70/100 × 1680 + ?/100 × 1750 = 55/100 × 2820 – 886
1176 + ?/10 × 175 = 1551 – 886 = 665
?/10 × 175 = 665 – 1176 = –511
? = (–511 × 10)/175 = –29.2
9.
46% of 1250 + ?% of 4680 = 1183.4
Answer: Option 'D'
46% of 1250 + ?% of 4680 = 1183.4
46/100 × 1250 + ?/100 × 4680 = 1183.4
575 + ?/5 × 234 = 1183.4
?/5 × 234 = 1183.4 – 575 = 608.4
? = (608.4 × 5)/234 = 3042/234 = 13
10.
If x/y = 3/4 and 8x + 5y = 22, then find the value of x.
Answer: Option 'A'
y = 4/3 x
Substitute this value in 8x+5y=22
8x + 5(4/3) x = 22
44x=66
x=1.5
11.
(764 × ?) ÷ 250 = 382
Answer: Option 'B'
(764 × ?)/250 = 382
? = (382 × 250)/764 = 125
12.
Simplify: 13.05 × 4.5 ÷ 0.5
Answer: Option 'B'
Follow the rule of ‘VBODMAS’
No bar, No bracket. Hence, first step starts from ‘DMAS’
Step 1: Divide 4.5 ÷ 0.5=9
Step 2: Multiply 13.05 × 9 = 117.45
13.
1035 ÷ [(3/4) of (71 + 65) – 15 ¾] = ?
Answer: Option 'A'
1035 ÷ [(3/4)× 136 – 63/4] = x
X = 1035 ÷ [102 – (63/4)]
X = 1035 ÷ [(408 – 63)/4]
X = 1035 ÷ (345/4)
X = 1035 × 4/345
X = 12
14.
4/9 × 1701 + 2/11 × 1386 = ?
Answer: Option 'B'
4/9 × 1701 + 2/11 × 1386 = ?
? = (4 × 189) + (2 × 126)
? = 756 + 252 = 1008.
Hence, option B is correct.
15.
[(4)3 × (5)4] ÷ (4)5 = ?
Answer: Option 'A'
? = [43 × 54]/45 = 54/42 = 625/16 = 39.0625